Chapter 13: Problem 5
The temperature in a circular plate of radius \(c\) is determined from the
boundary-value problem
$$
\begin{aligned}
&k\left(\frac{\partial^{2} u}{\partial r^{2}}+\frac{1}{r} \frac{\partial
u}{\partial r}\right)=\frac{\partial u}{\partial t}, \quad 0
Short Answer
Step by step solution
Identify the Problem Type
Recognize the PDE Form
Applying Separation of Variables
Solve the Radial Equation
Solve the Time-dependent Equation
Construct the General Solution and Apply Initial Condition
Solve for Coefficients Using Fourier-Bessel Expansion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heat Conduction Equation
- \[ k \left( \frac{\partial^{2} u}{\partial r^{2}}+\frac{1}{r} \frac{\partial u}{\partial r} \right) = \frac{\partial u}{\partial t} \]
Bessel's Differential Equation
- \[ R''(r) + \frac{1}{r} R'(r) + \lambda R(r) = 0 \]
However, due to physical reasons, we usually discard \(Y_0\) because it becomes singular at \(r = 0\). For boundary-value problems like ours, which require the function to be zero at the boundary, we typically select Bessel functions of the first kind \(J_0\) to satisfy this.
These functions are critical in solving boundary problems involving circular or cylindrical shapes. The parameters \(\lambda\) are determined by the boundary condition \(J_0(\sqrt{\lambda}c) = 0\), where \(\alpha_n\) are roots of this equation, ensuring the solution remains finite.
Separation of Variables
- \( u(r, t) = R(r)T(t) \)
The method allows us to focus on solving a problem in one variable while considering the effects of the other as a constant. This approach is particularly effective for problems with clear boundary conditions, such as the zero-temperature condition \(u(c, t)=0\) on our plate. Separation of variables leads us to identify the radial part as Bessel’s differential equation and the temporal part as a simple first-order differential equation.
Fourier-Bessel Series
- Our solution is represented as a series of terms: \[ u(r, t) = \sum_{n=1}^{\infty} A_n J_0(\alpha_n r) e^{-\alpha_n^2 k t} \]
Finding \(A_n\) involves integrating the product of the initial condition function and the corresponding Bessel function:
- \[ A_n = \frac{2}{c^2 J_1^2(\alpha_n c)} \int_0^c r f(r) J_0(\alpha_n r) \, dr \]