Chapter 9: Problem 4
Use hand calculations to find the characteristic polynomial and eigenvalues for each of the matrices. \(A=\left(\begin{array}{ll}-4 & 1 \\ -2 & 1\end{array}\right)\)
Short Answer
Expert verified
The eigenvalues are \( \frac{-3 + \sqrt{17}}{2} \) and \( \frac{-3 - \sqrt{17}}{2} \).
Step by step solution
01
Finding the Characteristic Polynomial
The characteristic polynomial of a matrix \( A \) is defined by \( \det(\lambda I - A) \), where \( \lambda \) is a scalar and \( I \) is the identity matrix. First, we write \( \lambda I - A \):\(\lambda I - A = \begin{pmatrix} \lambda & 0 \ 0 & \lambda \end{pmatrix} - \begin{pmatrix} -4 & 1 \ -2 & 1 \end{pmatrix} = \begin{pmatrix} \lambda + 4 & -1 \ 2 & \lambda - 1 \end{pmatrix}\)Next, we find the determinant of this matrix:\[\det(\begin{pmatrix} \lambda + 4 & -1 \ 2 & \lambda - 1 \end{pmatrix}) = (\lambda + 4)(\lambda - 1) - (-1)(2)\]Simplify the expression:\[= \lambda^2 + 4\lambda - \lambda - 4 + 2 = \lambda^2 + 3\lambda - 2\]Thus, the characteristic polynomial is \( \lambda^2 + 3\lambda - 2 \).
02
Finding the Eigenvalues
To find the eigenvalues, solve the characteristic polynomial equation \( \lambda^2 + 3\lambda - 2 = 0 \).This can be solved using the quadratic formula, \( \lambda = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1 \), \( b = 3 \), and \( c = -2 \):\[\lambda = \frac{-3 \pm \sqrt{3^2 - 4(1)(-2)}}{2(1)} = \frac{-3 \pm \sqrt{9 + 8}}{2} = \frac{-3 \pm \sqrt{17}}{2}\]Thus, the eigenvalues are \( \frac{-3 + \sqrt{17}}{2} \) and \( \frac{-3 - \sqrt{17}}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Characteristic Polynomial
The characteristic polynomial is a key concept in linear algebra, especially when dealing with matrices and eigenvalues. It helps in identifying the eigenvalues of a matrix. Given a square matrix, the characteristic polynomial is determined by the formula \( ext{det}(abla I - A) \). Here, \( abla \) represents a scalar value, usually denoted by \( abla \), and \( I \) is the identity matrix. This formula creatively transforms the matrix \( A \) into a new matrix through subtraction before calculating its determinant.
The idea is that the roots of the characteristic polynomial are the eigenvalues of the matrix. They reveal essential properties of a matrix, such as stability and, in some cases, geometric orientation.
Calculating the polynomial involves these steps:
The idea is that the roots of the characteristic polynomial are the eigenvalues of the matrix. They reveal essential properties of a matrix, such as stability and, in some cases, geometric orientation.
Calculating the polynomial involves these steps:
- Forming \( abla I - A \) by subtracting \( A \) from \( abla I \).
- Computing the determinant of the resulting matrix.
- Finding a polynomial expression in terms of \( abla \).
Quadratic Formula
When the characteristic polynomial is a quadratic equation, we often rely on the Quadratic Formula to find its roots, which represent the eigenvalues of the matrix. The quadratic formula is expressed as:
\[ \lambda = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
This formula is applicable for any equation of the form \( ax^2 + bx + c = 0 \).
In our exercise, for instance, the characteristic polynomial is \( \lambda^2 + 3\lambda - 2 = 0 \), and by comparing, we see:
This formula not only helps find eigenvalues but also gives insights into the behavior of quadratic functions, emphasizing its role as a mathematical tool for solving polynomials.
\[ \lambda = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
This formula is applicable for any equation of the form \( ax^2 + bx + c = 0 \).
In our exercise, for instance, the characteristic polynomial is \( \lambda^2 + 3\lambda - 2 = 0 \), and by comparing, we see:
- \( a = 1 \)
- \( b = 3 \)
- \( c = -2 \)
This formula not only helps find eigenvalues but also gives insights into the behavior of quadratic functions, emphasizing its role as a mathematical tool for solving polynomials.
Matrix Determinant
The determinant of a matrix is a scalar value that provides valuable insights into the matrix's properties. It is essential for calculating the characteristic polynomial and eventually finding eigenvalues. The determinant can help identify a matrix's invertibility, with a nonzero determinant suggesting an invertible matrix.
Here's how it is related to our exercise:
For a 2x2 matrix, the determinant is found using the formula:
\[ \ ext{det} \begin{pmatrix} a & b \ c & d \end{pmatrix} = ad - bc \]
In Step 1 of our solution, \( (abla + 4)(abla - 1) - (-2)(1) \) simplifies to \( abla^2 + 3abla - 2 \), giving us the characteristic polynomial.
The determinant is not only crucial for eigenvalue calculation; it also influences other matrix properties like orientation and scale transformation in geometric contexts.
Here's how it is related to our exercise:
For a 2x2 matrix, the determinant is found using the formula:
\[ \ ext{det} \begin{pmatrix} a & b \ c & d \end{pmatrix} = ad - bc \]
In Step 1 of our solution, \( (abla + 4)(abla - 1) - (-2)(1) \) simplifies to \( abla^2 + 3abla - 2 \), giving us the characteristic polynomial.
The determinant is not only crucial for eigenvalue calculation; it also influences other matrix properties like orientation and scale transformation in geometric contexts.
Eigenvalue Calculation
Eigenvalue calculation is the endpoint of determining a matrix's characteristic polynomial. Once we have the polynomial, finding its roots gives us the eigenvalues.
In the example of our exercise, the process unfolded as follows:
In practical terms, eigenvalues can influence systems dynamics, vibrations in mechanical structures, and more.
In the example of our exercise, the process unfolded as follows:
- The characteristic polynomial \( \lambda^2 + 3\lambda - 2 = 0 \) was derived using determinants.
- We applied the quadratic formula, a reliable method for solving quadratic polynomials.
- Calculating the roots resulted in eigenvalues \( \frac{-3 + \sqrt{17}}{2} \) and \( \frac{-3 - \sqrt{17}}{2} \).
In practical terms, eigenvalues can influence systems dynamics, vibrations in mechanical structures, and more.