Chapter 7: Problem 28
Without actually solving, which systems have unique solutions? Explain. \(x_{1}+2 x_{2}=4\) \(x_{1}-x_{2}=6\)
Short Answer
Expert verified
The system has a unique solution because the determinant is non-zero.
Step by step solution
01
Recognize the Equations
We have two linear equations with two variables: 1. \( x_{1} + 2x_{2} = 4 \)2. \( x_{1} - x_{2} = 6 \).
02
Check the Coefficients for Consistency
To determine if these equations have a unique solution, we need to check if they satisfy certain conditions. For a system of two linear equations to have a unique solution, the lines represented by the equations must intersect at a single point, which happens when the determinant of the coefficient matrix is non-zero.
03
Form the Coefficient Matrix
The coefficient matrix \( A \) for this system is formed from the coefficients of \( x_{1} \) and \( x_{2} \): \[A = \begin{bmatrix} 1 & 2 \ 1 & -1 \end{bmatrix}\]
04
Find the Determinant of the Coefficient Matrix
Calculate the determinant of matrix \( A \). The formula for the determinant of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is:\[\text{det}(A) = ad - bc\]Apply this to the matrix \( A \):\[\text{det}(A) = (1)(-1) - (2)(1) = -1 - 2 = -3\]
05
Interpret the Determinant
Since \( \text{det}(A) eq 0 \), it indicates that the system of equations has a unique solution. This means the lines represented by these equations are not parallel and will intersect at a single point.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Systems of Linear Equations
In mathematics, a system of linear equations consists of two or more linear equations involving the same set of variables. Each equation can be represented graphically as a line. The goal is often to find the point where these lines intersect, which represents the solution to the system.
For example, consider a system with two variables, as shown in the original exercise:
For example, consider a system with two variables, as shown in the original exercise:
- \( x_{1} + 2x_{2} = 4 \)
- \( x_{1} - x_{2} = 6 \)
Determinants
Determinants play a vital role in linear algebra when analyzing systems of linear equations. A determinant is a special number calculated from a square matrix. It provides important information about the matrix, such as whether it is invertible or the volume transformation it describes.
For a system of linear equations, like our example, you can form a coefficient matrix and compute its determinant to see if there's a unique solution.
The coefficient matrix \( A \) from our exercise is:\[A = \begin{bmatrix} 1 & 2 \ 1 & -1 \end{bmatrix}\]Calculating the determinant of this matrix using the formula for a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is:\[ \text{det}(A) = ad - bc = (1)(-1) - (2)(1) = -3 \]The determinant is non-zero, indicating the system has a unique solution where the lines intersect.
For a system of linear equations, like our example, you can form a coefficient matrix and compute its determinant to see if there's a unique solution.
The coefficient matrix \( A \) from our exercise is:\[A = \begin{bmatrix} 1 & 2 \ 1 & -1 \end{bmatrix}\]Calculating the determinant of this matrix using the formula for a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is:\[ \text{det}(A) = ad - bc = (1)(-1) - (2)(1) = -3 \]The determinant is non-zero, indicating the system has a unique solution where the lines intersect.
Coefficient Matrix
A coefficient matrix is a matrix created from the coefficients of the variables in a system of linear equations. It serves as a useful way to organize information and make calculations easier in linear algebra.
For our system:
For our system:
- \( x_{1} + 2x_{2} = 4 \)
- \( x_{1} - x_{2} = 6 \)
Unique Solutions
When discussing solutions to systems of linear equations, a unique solution means that there is exactly one point at which all equations in the system intersect. This occurs only when the determinant of the coefficient matrix is non-zero, as seen in the solution to our exercise example.
For the system:
This unique intersection point is the solution to the system. Knowing how to identify whether a system has a unique solution is essential for solving linear equations and applying linear algebra concepts effectively.
For the system:
- \( x_{1} + 2x_{2} = 4 \)
- \( x_{1} - x_{2} = 6 \)
This unique intersection point is the solution to the system. Knowing how to identify whether a system has a unique solution is essential for solving linear equations and applying linear algebra concepts effectively.