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A certain bacterium, given plenty of nutrient and room, is known to grow according to the Malthusian model with reproductive rate \(r\). Suppose that the biologist working with the culture harvests the bacteria at a constant rate of \(h\) bacteria per hour. Use qualitative analysis to discuss the fate of the culture.

Short Answer

Expert verified
The culture stabilizes at an equilibrium population size \( P = \frac{h}{r} \).

Step by step solution

01

Understand the Malthusian Model

The Malthusian model describes exponential growth, where the population size, denoted as \( P(t) \), changes over time \( t \) according to the equation: \[ \frac{dP}{dt} = rP \] Here, \( r \) is the constant rate of reproduction. The model assumes unlimited resources and space, leading to continuous exponential growth.
02

Modify the Model for Constant Harvesting

The problem introduces a constant harvesting rate \( h \), meaning bacteria is removed from the population at this constant rate. The differential equation becomes: \[ \frac{dP}{dt} = rP - h \] Here, \( rP \) represents the natural growth, while \( h \) represents the constant harvesting of bacteria.
03

Equilibrium Condition

To find the fate of the culture, consider the equilibrium condition where the population size does not change over time. This occurs when \( \frac{dP}{dt} = 0 \). Setting the modified growth equation to zero gives: \[ rP - h = 0 \] Solving for \( P \), we find: \[ P = \frac{h}{r} \] This represents the equilibrium population size.
04

Stability Analysis

To determine the stability of the equilibrium, consider small perturbations around \( P = \frac{h}{r} \). If \( P \) is below \( \frac{h}{r} \), the growth rate \( rP \) is less than \( h \), leading to a decrease in \( P \). If \( P \) is above \( \frac{h}{r} \), the growth rate \( rP \) exceeds \( h \), increasing \( P \). Thus, the equilibrium \( P = \frac{h}{r} \) is stable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Growth
Exponential growth is an important concept in biology and ecology, describing how a population can increase rapidly when there are no limitations on resources. In the Malthusian model, this is depicted mathematically as \( \frac{dP}{dt} = rP \), where \( P(t) \) is the population size at time \( t \) and \( r \) is the rate of reproduction. This equation highlights how the change in population at any time point, \( \frac{dP}{dt} \), is directly proportional to its current size.

The beauty of exponential growth lies in its simplicity; as the population grows, the rate of growth itself increases, leading to a rapid rise in numbers. However, it's crucial to note that this only holds when resources and space are abundant, making it an idealized model. In reality, factors like food shortages, predation, and environmental constraints often slow down exponential growth over time.
Differential Equations
Differential equations are mathematical tools used to describe how a quantity changes over time. In the context of population dynamics, they illustrate how populations grow or decline. The basic Malthusian model uses a differential equation \( \frac{dP}{dt} = rP \) to show exponential growth. However, our scenario involves harvesting the bacteria at a constant rate \( h \), which modifies the equation to \( \frac{dP}{dt} = rP - h \).

This new equation captures two competing processes: the natural exponential growth \( rP \) and the constant removal \( h \). Solving this equation lets us predict future population sizes and understand long-term growth trends. In practical applications, differential equations like these help scientists and ecologists model real-world systems and make informed predictions.
  • They describe continuous changes.
  • Offer a way to predict future behavior of systems.
  • Can be adapted to include various real-life constraints like harvesting.
Equilibrium Stability
Equilibrium stability is a key concept when analyzing population models. It refers to a state where the population size remains constant over time. In our modified Malthusian model with harvesting, the equilibrium occurs when the growth and harvesting rates are balanced, such that \( \frac{dP}{dt} = 0 \).

Solving \( rP - h = 0 \) yields \( P = \frac{h}{r} \), the equilibrium population size. The stability of this equilibrium is examined by seeing how the population behaves when slightly above or below this level.

This equilibrium is stable if small disturbances cause the population to return to \( P = \frac{h}{r} \). Here, if the population is less than \( \frac{h}{r} \), the removal rate outpaces the growth, causing a decrease. Conversely, if it's more, the growth exceeds removal, pulling the population back to equilibrium. This stability means populations will naturally adjust over time to stay around this size.
Qualitative Analysis
Qualitative analysis in the context of differential equations involves assessing the behavior of solutions without finding explicit answers. For the Malthusian model with harvesting, this means considering how the population will behave over time given different initial conditions and parameter values.

Through qualitative analysis, we predict the fate of our bacterial culture by understanding the dynamics between growth and harvesting. If the initial population is less than \( \frac{h}{r} \), the population will steadily decrease due to insufficient growth. If it's more, the culture's growth will counteract harvesting until equilibrium is reached.

This type of analysis is valuable for gaining insights into system behavior and helping to guide data collection or further analysis. Overall, qualitative analysis enables us to create a comprehensive plan of expectation without diving into the complexities of solving the equation precisely.

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Most popular questions from this chapter

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A population of bacteria is growing according to the Malthusian model. If the population triples in 10 hours, what is the reproduction rate? How often does the population double itself?

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