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On the day of his birth, Jason's grandmother pledges to make available \(\$ 50,000\) on his eighteenth birthday for his college education. She negotiates an account paying \(6.25 \%\) annual interest, compounded continuously, with no initial deposit, but agrees to deposit a fixed amount each year. What annual deposit should be made to reach her goal?

Short Answer

Expert verified
The annual deposit should be approximately \( \$1501.81 \).

Step by step solution

01

Understand the Future Value Formula for Continuous Compounding

The future value of a series of deposits compounded continuously is given by the formula:\[ FV = P \times \left( e^{rt} - 1 \right) / r \]where:- \( FV \) is the future value she wants, \( \$50,000 \)- \( P \) is the annual deposit amount- \( r \) is the annual interest rate as a decimal (6.25% = 0.0625)- \( t \) is the number of years (18 years)- \( e \) is the base of the natural logarithm, approximately equal to 2.71828We need to rearrange this formula to solve for \( P \).
02

Rearrange the Formula to Solve for P

The formula can be rearranged for \( P \) as follows:\[ P = \frac{FV \times r}{e^{rt} - 1} \]
03

Substitute Known Values

Substitute the known values into the equation:- \( FV = 50,000 \)- \( r = 0.0625 \)- \( t = 18 \)The equation becomes:\[ P = \frac{50000 \times 0.0625}{e^{0.0625 \times 18} - 1} \]
04

Calculate the Exponent

First, compute the exponent in the denominator:\[ e^{0.0625 \times 18} = e^{1.125} \].
05

Evaluate the Exponential Expression

Calculate \( e^{1.125} \), which is approximately 3.08022.
06

Calculate Denominator

Now calculate the denominator:\[ e^{1.125} - 1 = 3.08022 - 1 = 2.08022 \].
07

Solve for the Annual Deposit P

Finally, substitute back into the rearranged formula and solve for \( P \):\[ P = \frac{50000 \times 0.0625}{2.08022} \approx \frac{3125}{2.08022} \approx 1501.81 \]Thus, the annual deposit should be approximately \( \$1501.81 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Future Value Formula for Continuous Compounding
When saving for goals like Jason's college education, the Future Value Formula for Continuous Compounding is a powerful tool. This formula calculates how much money you'll have in the future based on periodic deposits earning interest that compounds continuously.

The key elements in this formula are:
  • The future value (FV), which is the target amount you aim to achieve. For Jason's case, this is \(\$50,000\).
  • The annual deposit (P), which is what we want to find out.
  • The annual interest rate (r), expressed in decimal form, not as a percentage.
  • The time period (t) for the investment or savings, here 18 years, as Jason's payout is expected on his 18th birthday.
The mathematical expression for this is:\[ FV = P \times \left( e^{rt} - 1 \right) / r \]This controlled calculation method allows us to input the interest rate and period to determine the necessary annual deposit needed to meet future financial goals by rearranging it for \(P\).
Understanding Annual Interest Rate
The annual interest rate plays a crucial role in calculating compound interest. In our formula, the interest rate is expressed as a decimal. An interest rate of 6.25% is converted to 0.0625 by dividing by 100.

When compounded continuously, the interest isn’t calculated at regular intervals but continuously grows, leading to a more efficient way of accumulating wealth.

To use continuous compounding:
  • Identify the nominal annual interest rate provided.
  • Convert it to a decimal for use in the formulas.
  • Apply it within the context of the exponential nature of Euler's Number \(e\).
The essence is understanding that continuous growth is faster than any finite compounding frequency due to this ever-accumulating nature, making saving plans more efficient with shorter time periods required to achieve the desired future values.
Exponential Growth and Its Importance
Exponential growth is the concept that money increases at a rate proportional to its current value, meaning it grows faster over time if left to compound continuously. This is represented by the expression \(e^{rt}\) in the continuous compounding formula.

Here’s why it is crucial:
  • It models real-world growth processes where finances grow based on their current state.
  • It takes advantage of the natural exponential base \(e\), approximated as 2.71828, which is inherently efficient for calculating continuous growth.
In Jason's case, understanding this growth is crucial for knowing how much to save annually for his college fund. By interpolating \(e^{1.125}\), which results from the exponent \(0.0625 \times 18\), we determine how funds will grow significantly when compounded over time. This nature makes continuous compounding ideal for long-term savings like education funds, maximizing the potential compound interest returns.

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Most popular questions from this chapter

A biologist develops a culture that obeys the modified logistic equation $$ P^{\prime}=0.38 p\left(1-\frac{P}{1000}\right)-h(t), $$ where the "harvesting" is defined by the piecewise function $$ h(t)= \begin{cases}200, & \text { if } t<3 \\ 0, & \text { otherwise. }\end{cases} $$ (a) Use a numerical solver to plot solution trajectories for initial bacterial populations ranging between 0 and 1000 . You'll note that in some cases, the population "recovers," but in others, the bacterial count goes to zero. Determine experimentally the critical initial population that separates these two behaviors. (b) Use an analytic method to determine the exact value of the "critical" initial population found in part (a). Justify your answer.

A resistor \((10 \Omega)\) and capacitor ( \(1 \mathrm{~F})\) are linked in series with an electromotive force (see Figure 4). Initially, there is no charge on the capacitor. The emf produces a constant voltage difference of \(100 \mathrm{~V}\) for the first five seconds, after which it is switched off. (a) Use a numerical solver to approximate the charge on the capacitor at the end of 10 seconds. (b) Set up and solve a differential equation modeling this circuit, then use the resulting formula to calculate the charge on the capacitor at the end of 10 seconds.

A biologist prepares a culture. After 1 day of growth, the biologist counts 1000 cells. After 2 days of growth, he counts 3000 . Assuming a Malthusian model, what is the reproduction rate and how many cells were present initially?

A certain bacterium is known to grow according to the Malthusian model, doubling itself every 8 hours. If a biologist starts with a culture containing 20,000 bacteria, then harvests the culture at a constant rate of 2000 bacteria per hour, how long until the culture is depleted? What would happen in the same time span if the initial culture contained 25,000 bacteria?

José is 25 years old. His current annual salary is \(\$ 28,000\). Over the next 20 years, he expects his salary to increase continuously at a rate of \(1 \%\) per year. He establishes a fund paying \(6 \%\) annual interest, compounded continuously, with an initial deposit of \(\$ 2500\) and a promise to deposit a fixed percentage of his annual income each year. Find that fixed percentage if José wants his balance to reach \(\$ 50,000\) at the end of the 20 -year period.

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