/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Find the family of curves that i... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the family of curves that is orthogonal to the family defined by the equation \(y^{2}=c x\) and provide a sketch depicting the orthogonality of the two families.

Short Answer

Expert verified
The orthogonal family is given by \( y = ke^{-\frac{2}{c}x} \).

Step by step solution

01

Differentiate the given family of curves

To find the family of curves that are orthogonal to the given family, we start by differentiating the equation of the family of curves, which is \( y^2 = c x \), with respect to \( x \). Differentiating implicitly, we get:\[ 2y \frac{dy}{dx} = c \]Thus, the derivative \( \frac{dy}{dx} \), representing the slope of the tangent to the curves, is given by:\[ \frac{dy}{dx} = \frac{c}{2y} \]
02

Determine the slope of the orthogonal family

The slopes of orthogonal curves are negative reciprocals of each other. Thus, for the orthogonal family of curves, the slope \( \frac{dy}{dx} \) will be the negative reciprocal of the original slope:\[ \frac{dy}{dx}_{\text{orthogonal}} = -\frac{2y}{c} \]
03

Construct the differential equation for the orthogonal family

From the negative reciprocal slope \( \frac{dy}{dx}_{\text{orthogonal}} = -\frac{2y}{c} \), we can form the differential equation:\[ \frac{dy}{dx} = -\frac{2y}{c} \]
04

Solve the differential equation for the orthogonal family

To solve \( \frac{dy}{dx} = -\frac{2y}{c} \), separate variables:\[ \frac{dy}{y} = -\frac{2}{c} \, dx \]Integrating both sides gives:\[ \ln|y| = -\frac{2}{c}x + C \]Exponentiating both sides to eliminate the logarithm, we have:\[ |y| = e^{C} e^{-\frac{2}{c}x} \]Let \( e^{C} = k \) where \( k \) is a constant, then:\[ y = ke^{-\frac{2}{c}x} \]
05

Sketch the curves to show orthogonality

The original family of curves \( y^{2} = c x \), are parabolas opening to the right. The orthogonal family of curves \( y = ke^{-\frac{2}{c}x} \), are decaying exponential curves. When sketched on a graph, these exponential curves are orthogonal (perpendicular) to the parabolic groupings due to the nature of their slope relationships.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a fundamental mathematical process used to find the rate at which one quantity changes with respect to another. In simpler terms, it gives the slope of a function at any point, describing how the function behaves—a little like finding how steep a hill is at a particular spot. When you differentiate a function, you are calculating what's known as a derivative. Derivatives are crucial in mathematics, especially in calculus, and have applications in many fields such as physics, engineering, and economics.
Differentiation can be visualized as a way of zooming in on a curve until it looks like a straight line. This straight line is known as the tangent line, and its slope is the derivative. For example, consider the curve represented by the equation \( y = x^2 \). The process of differentiation will show that its derivative is \( rac{dy}{dx} = 2x \), indicating how the slope of \( y = x^2 \) changes as \( x \) varies.
Implicit Differentiation
Implicit Differentiation is a technique used when a function is not given explicitly. In other words, instead of expressing one variable directly in terms of another, the variables are intertwined in an equation. This is common when dealing with equations like circles, ellipses, or the family of curves we have in the original problem.
With implicit differentiation, you treat both variables as functions of each other and differentiate both sides of the equation with respect to one variable, while applying the chain rule to the other variable. For instance, if you have an equation like \( y^2 = cx \), even though \( y \) is expressed in terms of \( x \), both \( x \) and \( y \) are treated independently while differentiating. Hence, using implicit differentiation, the derivative \( rac{dy}{dx} \) becomes \( rac{c}{2y} \), which tells us how \( y \) changes for small changes in \( x \), even when \( y \) is not explicitly isolated.
Negative Reciprocal
The Negative Reciprocal of a slope is important when dealing with orthogonal (perpendicular) curves. When two lines or curves are orthogonal, their slopes are negative reciprocals of each other. This means if the slope of one curve is \( m \), the slope of the orthogonal curve will be \( -\frac{1}{m} \).
For our original exercise, after finding the derivative of the given family of curves \( y^2 = cx \), we obtained the slope \( rac{c}{2y} \). To find the slopes of the orthogonal curves, we need to take the negative reciprocal. Thus, the slope of the orthogonal curves becomes \( -\frac{2y}{c} \). This negative reciprocal relationship ensures that the angles formed between the original and orthogonal curves at points of intersection are 90 degrees, which is how we define orthogonality in geometry.
Exponential Functions
Exponential Functions are functions where a constant base is raised to a variable exponent. These functions often describe growth or decay processes, such as population growth, radioactive decay, or cooling of objects. Their general form is \( y = a e^{bx} \), where \( a \) and \( b \) are constants and \( e \) is the base of the natural logarithm, approximately equal to 2.718.
In our solution, after implicit differentiation and utilizing the negative reciprocal slope, the orthogonal family of curves took the form \( y = ke^{-\frac{2}{c}x} \). Here, the negative exponent indicates an exponential decay, meaning that as \( x \) increases, the value of \( y \) decreases. These curves are typically smooth and do not cross the \( x \)-axis, which stands in contrast to curves like parabolas. Exponential functions are immensely useful not only in mathematics but also in modeling real-world phenomena across diverse disciplines, helping us make sense of patterns and processes that change rapidly over time.

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Most popular questions from this chapter

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