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Tritium, \({ }^{3} \mathrm{H}\), is an isotope of hydrogen that is sometimes used as a biochemical tracer. Suppose that \(100 \mathrm{mg}\) of \({ }^{3} \mathrm{H}\) decays to \(80 \mathrm{mg}\) in 4 hours. Determine the half-life of \({ }^{3} \mathrm{H}\).

Short Answer

Expert verified
The half-life of \(^{3} \mathrm{H} \) is approximately 12.318 hours.

Step by step solution

01

Determine the Decay Formula

The decay of a substance is often modeled using the exponential decay formula: \[ A(t) = A_0 e^{-kt} \]where \( A(t) \) is the amount remaining at time \( t \), \( A_0 \) is the initial amount, \( k \) is the decay constant, and \( t \) is the time elapsed.
02

Set Up the Known Values

We know that \( A_0 = 100 \, \mathrm{mg} \), \( A(t) = 80 \, \mathrm{mg} \) after \( t = 4 \, \text{hours} \). We will use these values to find the decay constant \( k \).
03

Solve for the Decay Constant \( k \)

Plug the known values into the exponential decay formula:\[ 80 = 100 e^{-4k} \]Divide both sides by 100:\[ 0.8 = e^{-4k} \]Take the natural logarithm of both sides to solve for \( k \):\[ \ln(0.8) = -4k \]\[ k = -\frac{\ln(0.8)}{4} \]
04

Calculate the Half-Life Formula

The half-life \( T \) is the time required for a quantity to reduce to half its initial amount. The half-life is given by:\[ T = \frac{\ln(2)}{k} \]
05

Substitute to Find the Half-Life

Substitute the expression we found for \( k \) into the half-life formula:\[ T = \frac{\ln(2)}{-\frac{\ln(0.8)}{4}} \]Simplify the expression:\[ T = \frac{4 \ln(2)}{-\ln(0.8)} \]
06

Evaluate the Expression

Calculate the numerical value:1. Find \( \ln(0.8) \) using a calculator: \( \ln(0.8) \approx -0.2231\)2. Find \( \ln(2) \approx 0.6931 \)3. Substitute them in: \( T \approx \frac{4 \times 0.6931}{0.2231} \)4. Calculate the result: \( T \approx 12.318 \) hours.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life Calculation
Half-life is a key concept in understanding how substances decay over time. It is defined as the duration required for a quantity to diminish to half its initial amount. This concept applies to various processes, including radioactive decay, biological processes, and even certain financial calculations.
In the context of radioactive decay, knowing the half-life helps predict how long a sample can remain effective or hazardous.

Calculating the half-life requires knowing the decay constant, which is typically derived from observed data. Once the decay constant is determined, you can use the formula:
  • \[T = \frac{\ln(2)}{k} \]Where\( T \) is the half-life, and \( k \) is the decay constant.
It's a straightforward calculation once you have the decay constant, providing valuable insights into the behavior of decaying substances when considered in combination with the exponential decay model.
Decay Constant
The decay constant, often represented by the symbol \( k \), is crucial to modeling exponential decay. It quantifies the rate at which a substance undergoes decay. In the exponential decay equation \( A(t) = A_0 e^{-kt} \), the decay constant determines how quickly the substance decays over time.
This constant can be calculated with measurements of initial and remaining quantities after a given time period. Typically, this is achieved by taking the natural logarithm of the ratio of remaining to initial quantities, and dividing it by the time elapsed.

For instance, using our step-by-step solution:
  • Given initial quantity \( A_0 = 100 \, \mathrm{mg} \) and remaining quantity \( A(t) = 80 \, \mathrm{mg} \) after 4 hours, the equation is setup as \( 80 = 100 e^{-4k} \).
  • The natural logarithm helps to solve for \( k \): - \[\ln(0.8) = -4k\]- Rearranging gives: \( k = -\frac{\ln(0.8)}{4} \)
  • With this method, we obtain \( k \approx 0.0558 \), providing the rate of decay for future calculations.
Understanding the decay constant is a stepping stone for deeper insights into the decay process and making reliable predictions for half-life calculations.
Exponential Functions
Exponential functions play a pivotal role in depicting situations involving rapid growth or decay. In our context, these functions help model how substances reduce in amount over time. The hallmark of an exponential function in decay is its base \( e \), the mathematical constant approximately equal to 2.718.
Let's break down the general form of the exponential decay function:
  • \[A(t) = A_0 e^{-kt}\]Here,
    • \( A(t) \) represents the quantity remaining at time \( t \).
    • \( A_0 \) is the initial quantity before decay starts.
    • \( k \) is the decay constant, controlling the rate of decay.
  • Exponential decay illustrates how a large quantity rapidly decreases and then slows as it approaches zero. The decrease follows a curve recognized by its continuously diminishing gradient.
  • In practical terms, exponential decay models are invaluable across scientific disciplines, from chemistry to physics, providing a simple yet robust framework to understand systems where constant proportional decay is present.
Through practice, understanding, and application of these functions, one can accurately model and predict behaviors in natural processes governed by exponential decay.

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Most popular questions from this chapter

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