Chapter 2: Problem 12
Find the general solution of the first-order, linear equation. $$ x^{t}-(n / t) x=e^{t} t^{n}, \quad n \text { an positive integer } $$
Short Answer
Expert verified
The general solution is \( x(t) = t^n (e^t + C) \).
Step by step solution
01
Recognize the Standard Form
The given differential equation is \( x' - \frac{n}{t}x = e^t t^n \). The standard form for a linear first-order differential equation is \( x' + p(t)x = q(t) \), so we identify \( p(t) = -\frac{n}{t} \) and \( q(t) = e^t t^n \).
02
Find the Integrating Factor
The integrating factor \( \mu(t) \) is given by \( e^{\int p(t) \, dt} \). Calculate the integral: \( \int -\frac{n}{t} \, dt = -n \ln |t| = \ln |t|^{-n} \). Thus, the integrating factor is \( \mu(t) = e^{\ln |t|^{-n}} = |t|^{-n} \).
03
Multiply Equation by Integrating Factor
Multiply the entire differential equation by the integrating factor \(|t|^{-n}\) to make the left-hand side a perfect derivative: \( |t|^{-n} x' + \, |t|^{-n}(-\frac{n}{t})x = |t|^{-n} e^t t^n \). Simplifying, we have \( (|t|^{-n} x)' = e^t \).
04
Integrate Both Sides
Integrate both sides with respect to \( t \). The integral of the left side \( \int (|t|^{-n} x)' \, dt \) is \( |t|^{-n} x \) (because it's a straightforward derivative), and the right side \( \int e^t \, dt \) is \( e^t + C \), where \( C \) is the constant of integration.
05
Solve for x(t)
Equating the results from Step 4, \( |t|^{-n} x = e^t + C \). Solving for \( x(t) \), we multiply through by \( |t|^n \) to get \( x(t) = |t|^n (e^t + C) \). Since \( |t|^n \) is simply \( t^n \) when \( t > 0 \) and \( n \) is an integer, the general solution is \( x(t) = t^n (e^t + C) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-order differential equation
A first-order differential equation involves the first derivative of a function but no higher derivatives. In simple terms, it is an equation that relates a function, its first derivative, and possibly the independent variable. The equation represented here is of the form \( x' + p(t)x = q(t) \), a classic structure for linear first-order differential equations.
The components of this form can be split as follows:
The components of this form can be split as follows:
- \( x' \) represents the first derivative of the dependent variable \( x \) with respect to the independent variable \( t \).
- \( p(t)x \) is a term where \( p(t) \) is a coefficient that could change over \( t \).
- \( q(t) \) is the non-homogeneous part, representing external inputs or forces.
Integrating factor method
The integrating factor method is a powerful technique used to solve first-order linear differential equations. It involves multiplying the entire differential equation by a specially chosen function—called the integrating factor—which transforms it into a conveniently solvable form.
Here's how it works:
Here's how it works:
- The integrating factor \( \mu(t) \) is found by calculating \( e^{\int p(t) \, dt} \), where \( p(t) \) is a function identified earlier that accompanies the \( x \) variable.
- This factor is then multiplied by every term in the differential equation, converting the left-hand side into a derivative of the product \( \mu(t)x \).
- Once transformed, the equation simplifies to a form which can be integrated easily.
General solution
The "general solution" of a differential equation is a comprehensive expression that includes all possible solutions. It typically involves a constant of integration, reflecting the infinite set of solutions corresponding to different initial conditions.
In solving the equation \( x' - \frac{n}{t}x = e^t t^n \), we aim to find such a solution that accounts for all dynamics. Upon integrating the appropriately formed equation, the solutions take on the form \( x(t) = t^n (e^t + C) \), where \( C \) is any constant.
This form signifies:
In solving the equation \( x' - \frac{n}{t}x = e^t t^n \), we aim to find such a solution that accounts for all dynamics. Upon integrating the appropriately formed equation, the solutions take on the form \( x(t) = t^n (e^t + C) \), where \( C \) is any constant.
This form signifies:
- \( t^n \) scales the influence of \( e^t \) and the constant \( C \) depending on \( t \).
- The term \( e^t \) reflects continuous growth or decay, typical of exponential functions.
- \( C \) allows flexibility, enabling the expression to satisfy initial or boundary conditions.