/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Find the radius of convergence o... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the radius of convergence of each of the series in Exercises 1-12. $$ \sum_{n=0}^{\infty} \frac{x^{n+1}}{n !} $$

Short Answer

Expert verified
The radius of convergence is \( \infty \).

Step by step solution

01

Identify the Series

Given the series \( \sum_{n=0}^{\infty} \frac{x^{n+1}}{n!} \), we need to determine the radius of convergence. This series is similar to the exponential series.
02

Apply the Ratio Test

To find the radius of convergence, we apply the Ratio Test, which uses the ratio \( \left| \frac{a_{n+1}}{a_n} \right| \). For our series, let \( a_n = \frac{x^{n+1}}{n!} \). The next term \( a_{n+1} = \frac{x^{n+2}}{(n+1)!} \).
03

Calculate the Ratio

Calculate \( \left| \frac{a_{n+1}}{a_n} \right| = \left| \frac{x^{n+2}}{(n+1)!} \times \frac{n!}{x^{n+1}} \right| = \left| \frac{x^{n+2} \cdot n!}{x^{n+1} \cdot (n+1)!} \right|. \) Simplifying, we get \( \left| \frac{x}{n+1} \right| \).
04

Take the Limit of the Ratio

The Ratio Test requires taking the limit as \( n \to \infty \) of the expression \( \left| \frac{x}{n+1} \right| \). Therefore, \( \lim_{n \to \infty} \left| \frac{x}{n+1} \right| = 0 \) for any finite \( x \), because the denominator \( n+1 \to \infty \).
05

Determine the Radius of Convergence

Since the limit is 0 for all \( x \), the series converges for any value of \( x \). Thus, the radius of convergence is \( R = \infty \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Ratio Test
The Ratio Test is a popular mathematical tool to determine the convergence of an infinite series. It is particularly useful when dealing with series where each term is expressed in a complex form involving factorials, powers, or other functions.
To apply the Ratio Test, we need to find the ratio of consecutive terms:
  • Identify a general term in the series, say \( a_n \).
  • Compute the next term, \( a_{n+1} \).
  • Calculate \( \left| \frac{a_{n+1}}{a_n} \right| \), the absolute ratio of these terms.
To decide on the convergence:
  • If \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| < 1 \), the series converges absolutely.
  • If \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| > 1 \), the series diverges.
  • If the limit equals 1, the test is inconclusive.
In the given series, we determined \( \lim_{n \to \infty} \left| \frac{x}{n+1} \right| = 0 \), which is less than 1 for all \( x \), indicating convergence for all real numbers.
Diving into Infinite Series
An infinite series is the sum of the terms of an infinite sequence. Mathematically, it is expressed as \( \sum_{n=0}^{\infty} a_n \). Since it involves an endless sequence of terms, the main question often is whether the series converges or diverges as the number of terms goes to infinity.
To explore convergence, you can use various methods such as the Ratio Test, the Root Test, or the Comparison Test, among others. Each method has its own advantages based on the form of the series you're examining. Infinite series are significant in mathematical analysis especially when functions are represented in new ways through series expansions.
A convergent series means adding more terms up to infinity reaches a finite sum. This concept is important when approximating functions and in calculus. The series \( \sum_{n=0}^{\infty} \frac{x^{n+1}}{n!} \) is analogous to series used to define exponential functions, exhibiting properties typical for convergent series in analysis.
Exploring the Limit of a Sequence
Limits are fundamental in calculus and analysis. When you hear 'limit,' you're looking at what happens to a sequence or function as it approaches a point. With an infinite sequence \( a_n \), we often want to know its behavior as \( n \) approaches infinity.
For sequences that correspond to the terms of a series, the limit will help determine if the sequence approaches a particular value (indicating convergence), or moves unbounded (indicating divergence).
  • If \( \lim_{n \to \infty} a_n = L \), for some finite \( L \), the sequence converges to \( L \).
  • If the limit doesn’t exist or is infinite, the sequence diverges.
In the original problem, using the limit helped us to conclude that \( \lim_{n \to \infty} \left| \frac{x}{n+1} \right| = 0 \). This strongly indicates that each term tends towards zero as \( n \to \infty \), supporting convergence of the series for all values of \( x \).
Understanding Exponential Series
Exponential series are a vital component of mathematical analysis. The classic exponential series expansion is \( e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!} \). It provides a way of expressing exponential functions using an infinite series of terms.
The beauty of these series lies in their convergence properties, particularly the fact that they converge for all real numbers \( x \). This is because the terms \( \frac{x^n}{n!} \) decrease rapidly to zero as \( n \) increases, ensuring the series remains finite even as more terms are added.
For the series \( \sum_{n=0}^{\infty} \frac{x^{n+1}}{n!} \), it is a slight shift of the exponential series. The convergence analysis remains similar; hence, the exponential nature ensures it converges for any real \( x \). This has important applications in calculus for representing complex functions and calculating precise values with series expansions.

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Most popular questions from this chapter

In Exercises 1-9, classify each singular point of the given equation. $$ \left(4-x^{2}\right)^{2} y^{\prime \prime}+x(2-x) y^{\prime}+(2+x) y=0 $$

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