Chapter 8: Problem 5
Verify that \((0,0)\) is a simple critical point for each of the following systems, and determine its nature and stability properties: \(\left\\{\begin{array}{l}\frac{d x}{d t}=x+y-2 x y \\ \frac{d y}{d t}=-2 x+y+3 y^{2}\end{array}\right.\) \(\left\\{\begin{array}{l}\frac{d x}{d t}=-x-y-3 x^{2} y \\ \frac{d y}{d t}=-2 x-4 y+y \sin x\end{array}\right.\)
Short Answer
Step by step solution
Identify the Critical Point
Analyze System 1
Linearize System 1 Around (0,0)
Determine Stability for System 1
Analyze System 2
Linearize System 2 Around (0,0)
Determine Stability for System 2
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Critical Points
Jacobian Matrix
- For system 1: \( J = \begin{bmatrix} \frac{\partial F_1}{\partial x} & \frac{\partial F_1}{\partial y} \ \frac{\partial F_2}{\partial x} & \frac{\partial F_2}{\partial y} \end{bmatrix} \)
- For system 2: Do the same with its respective functions.
Stability Analysis
- If all eigenvalues have negative real parts, the system returns to equilibrium, indicating a stable critical point.
- If any eigenvalue has a positive real part, the deviation grows, and the critical point is unstable.
- Complex eigenvalues with positive real parts often indicate spiraling away, showcasing an unstable spiral.
Eigenvalues
Linearization
- Calculate the Jacobian matrix at the critical point.
- Replace the nonlinear terms with their linear approximations.
- Analyze this resulting linear system to infer about the original system's behavior near its critical point.