Chapter 3: Problem 4
The equation $$ x^{2} y^{*}+p x y^{\prime}+q y=0 $$ where \(p\) and \(q\) are constants, is called Euler's equidimensional equation. \({ }^{1}\) Show that the change of independent variable given by \(x=e^{z}\) transforms it into an equation with constant coefficients, and apply this technique to find the general solution of each of the following equations: a. \(x^{2} y^{\prime \prime}+3 x y^{\prime}+10 y=0\); b. \(2 x^{2} y^{\prime \prime}+10 x y^{\prime}+8 y=0\); c. \(x^{2} y^{n}+2 x y^{\prime}-12 y=0\).
Short Answer
Step by step solution
Understand the transformation
Transform derivatives
Substitute and Simplify
Solve for Case a
Solve for Case b
Solve for Case c
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differential Equations
For example, Euler's equation is of the form:
- \( x^2 y'' + px y' + q y = 0 \)
Change of Variables
In Euler's Equidimensional Equation, we substitute:
- \( x = e^z \)
- \( y' = e^{-z} \frac{dy}{dz} \)
- \( y'' = e^{-2z} (\frac{d^2y}{dz^2} - \frac{dy}{dz}) \)
Constant Coefficient Equations
The equation looks something like:
- \( \frac{d^2y}{dz^2} + a \frac{dy}{dz} + by = 0 \)
Characteristic Equation
When we plug this into the differential equation, we get an algebraic equation for \( m \), known as the characteristic equation:
- \( m^2 + am + b = 0 \)
- If the roots are real and distinct, the solution will be a combination of exponential functions.
- If they are real and repeated, it will involve terms of the form \( z \).
- Complex roots will result in oscillatory solutions, involving sine and cosine functions.
General Solution
For distinct roots \( m_1 \) and \( m_2 \), the general solution is:
- \( y(z) = C_1 e^{m_1 z} + C_2 e^{m_2 z} \)
For repeated roots \( m \), the solution takes the form:
- \( y(z) = (C_1 + C_2 z) e^{mz} \)
- \( y(z) = e^{\alpha z} (C_1 \cos(\beta z) + C_2 \sin(\beta z)) \)