Chapter 6: Problem 17
If \(T: M_{23}(\mathbb{R}) \rightarrow P_{6}(\mathbb{R})\) is one-to-one, what is \(\operatorname{dim}[\operatorname{Rng}(T)] ?\)
Short Answer
Expert verified
The dimension of the range of the linear transformation \(T: M_{23}(\mathbb{R}) \rightarrow P_{6}(\mathbb{R})\) is 6.
Step by step solution
01
Identify the dimensions of domain and kernel
We are given that T is a linear transformation from \(M_{23}(\mathbb{R})\) (the space of 2x3 matrices) to \(P_{6}(\mathbb{R})\) (the space of polynomials of degree at most 6). The dimension of \(M_{23}(\mathbb{R})\) is 2 * 3 = 6, since each entry is an independent component.
We also know that T is a one-to-one linear transformation, so the kernel of T (the set of vectors v in the domain such that T(v) = 0) is trivial and contains only the zero vector. Thus, the dimension of the kernel is 0.
02
Apply the rank-nullity theorem
We will now apply the rank-nullity theorem to find the dimension of the range of T. The theorem states:
\[\operatorname{dim}(\operatorname{Dom}(T)) = \operatorname{dim}(\operatorname{Rng}(T)) + \operatorname{dim}(\operatorname{Ker}(T))\]
Substitute the dimensions of the domain and kernel that we found in Step 1:
\[6 = \operatorname{dim}(\operatorname{Rng}(T)) + 0\]
03
Solve for the dimension of the range
Since the equation becomes \(6 = \operatorname{dim}(\operatorname{Rng}(T))+0\), we can easily solve for the dimension of the range of T:
\[\operatorname{dim}(\operatorname{Rng}(T)) = 6\]
Therefore, the dimension of the range of the linear transformation T is 6.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Space
Matrix space is a fascinating concept in linear algebra. It refers to the set of all matrices of a certain size over a given field. For example, in the previous problem, we discussed the space of 2x3 matrices, denoted as \(M_{23}(\mathbb{R})\). This space consists of all matrices that have 2 rows and 3 columns with real number entries.
Matrix spaces have dimensions similar to vectors - think of them as vectors with more structure due to their shape. For a matrix space \(M_{mn}(\mathbb{R})\), the dimension is calculated by the product of the number of rows and columns (\(m \times n\)). Thus, the dimension of \(M_{23}(\mathbb{R})\) is 6, since it has 6 individual entries that can vary independently.
Matrix spaces have dimensions similar to vectors - think of them as vectors with more structure due to their shape. For a matrix space \(M_{mn}(\mathbb{R})\), the dimension is calculated by the product of the number of rows and columns (\(m \times n\)). Thus, the dimension of \(M_{23}(\mathbb{R})\) is 6, since it has 6 individual entries that can vary independently.
- Each entry is an independent component.
- Matrix spaces are essential in defining transformations between different vector spaces.
- They help represent linear transformations in a compact form.
Rank-Nullity Theorem
The rank-nullity theorem is a fundamental theorem in linear algebra that links dimensions of different pieces of a linear transformation. For a linear transformation \(T\) from one vector space to another, this theorem connects the dimension of the domain, the range, and the kernel.
The theorem is mathematically expressed as:\[\operatorname{dim}(\operatorname{Dom}(T)) = \operatorname{dim}(\operatorname{Rng}(T)) + \operatorname{dim}(\operatorname{Ker}(T))\]This equation essentially says the dimension of the domain is the sum of the dimensions of the range and the kernel. It is useful because:
The theorem is mathematically expressed as:\[\operatorname{dim}(\operatorname{Dom}(T)) = \operatorname{dim}(\operatorname{Rng}(T)) + \operatorname{dim}(\operatorname{Ker}(T))\]This equation essentially says the dimension of the domain is the sum of the dimensions of the range and the kernel. It is useful because:
- If you know the dimensions of any two spaces, you can find the third.
- It helps verify properties of \(T\), such as injectivity (one-to-one) or surjectivity (onto).
- It's pivotal in determining the possible outcomes of a transformation.
Polynomial Space
Polynomial spaces are sets of polynomials with coefficients in a particular field, such as the real numbers \(\mathbb{R}\). In our problem, the polynomial space \(P_{6}(\mathbb{R})\) consists of polynomials with real coefficients of degree at most 6.
Such a polynomial space has a dimension equal to one more than the highest polynomial degree. So, \(P_{6}(\mathbb{R})\) has dimension 7, with basis elements
Grasping polynomial spaces allows us to see how abstract operations in calculus relate to hands-on computations in algebra, such as transformations and solving equations.
Such a polynomial space has a dimension equal to one more than the highest polynomial degree. So, \(P_{6}(\mathbb{R})\) has dimension 7, with basis elements
- \(1\)
- \(x\)
- \(x^2\)
- \(x^3\)
- \(x^4\)
- \(x^5\)
- \(x^6\)
Grasping polynomial spaces allows us to see how abstract operations in calculus relate to hands-on computations in algebra, such as transformations and solving equations.