Chapter 5: Problem 18
Find the equation of the least squares line to the given data points. $$(-3,1),(-2,0),(-1,1),(0,-1),(2,-1).$$
Short Answer
Expert verified
The equation of the least squares line that best fits the given data points is \(y \approx -0.4x + 0.32\).
Step by step solution
01
Find the average of the x and y coordinates
Calculate the average of the x and y values for the given data points. This will help us to determine the slope and y-intercept of the least squares line.
$$
\begin{aligned}
\bar{x} &= \frac{-3+-2+-1+0+2}{5} = -\frac{4}{5}\\
\bar{y} &= \frac{1+0+1+-1+-1}{5} = 0
\end{aligned}
$$
02
Calculate the slope (m) of the line
To find the slope of the least squares line, we can use the following formula:
$$
m = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2}
$$
Substitute the values of x and y into the formula and calculate the slope:
$$
\begin{aligned}
m &= \frac{(-3-(-\frac{4}{5}))(1-0) + (-2-(-\frac{4}{5}))(0-0) + (-1-(-\frac{4}{5}))(1-0)+\\
&(0-(-\frac{4}{5}))(-1-0)+(2-(-\frac{4}{5}))(-1-0)}{(-3-(-\frac{4}{5}))^2+(-2-(-\frac{4}{5}))^2+(-1-(-\frac{4}{5}))^2+(0-(-\frac{4}{5}))^2+(2-(-\frac{4}{5}))^2}\\
m & \approx -0.4
\end{aligned}
$$
03
Calculate the y-intercept (b) of the line
To find the y-intercept of the least squares line, we can use the following formula:
$$
b = \bar{y} - m\bar{x}
$$
Substitute the values of \(m\) and \(\bar{x}\) into the formula and calculate the y-intercept:
$$
\begin{aligned}
b &= 0 - (-0.4)\left(-\frac{4}{5}\right)\\
b & \approx 0.32
\end{aligned}
$$
04
Write the equation of the least squares line
Now that we have calculated the slope and y-intercept, we can write the equation of the least squares line in the form y = mx + b:
$$
y \approx -0.4x + 0.32
$$
This is the equation of the least squares line that best fits the given data points.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Data Points
In the context of finding a least squares line, data points are the specific coordinates on a graph that you want to analyze and understand. These are the
Each data point consists of an
These points are used to establish a relationship between variables by approximating a line. The line's purpose is to give a "best fit," predicting how the values might relate if they were to continue. It helps identify trends or make forecasts about
- measured values,
- experimental results,
- or observed outcomes,
Each data point consists of an
- x-value (horizontal axis),
- y-value (vertical axis).
These points are used to establish a relationship between variables by approximating a line. The line's purpose is to give a "best fit," predicting how the values might relate if they were to continue. It helps identify trends or make forecasts about
- future points,
- missing data,
- or general patterns.
Slope Calculation
The slope of a line in the context of least squares represents the rate at which one variable changes with respect to another. It is a measure of how steep the line is.
To calculate the slope (\(m\)) of the least squares line, you use the formula:
\[ m = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2} \]This formula takes into account all of the data points, as well as their deviations from their averages (\(\bar{x}\) and \(\bar{y}\)).
Here's how it works:
To calculate the slope (\(m\)) of the least squares line, you use the formula:
\[ m = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2} \]This formula takes into account all of the data points, as well as their deviations from their averages (\(\bar{x}\) and \(\bar{y}\)).
Here's how it works:
- You calculate the deviation for each x-value by subtracting the mean of x (\(\bar{x}\)) from each \(x_i\).
- Similarly, compute the deviation for each y-value by subtracting the mean of y (\(\bar{y}\)) from each \(y_i\).
- The sum of the products of these deviations gives the numerator.
- The sum of the squared deviations of x-values gives the denominator.
Y-Intercept
The y-intercept is a key component of the equation of a line, famously expressed as \(y = mx + b\). This component, denoted by \(b\), represents the point where the line crosses the y-axis. It's the y-value when \(x = 0\).
Finding \(b\) for a least squares line involves using the values of the slope (\(m\)) and the mean x-value (\(\bar{x}\)), calculated as follows:\[ b = \bar{y} - m\bar{x} \]This formula essentially adjusts the average \(y\)-value downward or upward based on the slope of the line.
In our particular exercise, the y-intercept was found to be approximately \(0.32\). This means that when \(x = 0\), the prediction based on the least squares line would be \(y = 0.32\). Understanding this can help conceptualize how high or low the line starts before being influenced by the slope's direction.
This y-intercept indicates how the line positions itself vertically on the graph, providing crucial information about the general level of y-values independent of the x-variable.
Finding \(b\) for a least squares line involves using the values of the slope (\(m\)) and the mean x-value (\(\bar{x}\)), calculated as follows:\[ b = \bar{y} - m\bar{x} \]This formula essentially adjusts the average \(y\)-value downward or upward based on the slope of the line.
In our particular exercise, the y-intercept was found to be approximately \(0.32\). This means that when \(x = 0\), the prediction based on the least squares line would be \(y = 0.32\). Understanding this can help conceptualize how high or low the line starts before being influenced by the slope's direction.
This y-intercept indicates how the line positions itself vertically on the graph, providing crucial information about the general level of y-values independent of the x-variable.