Chapter 3: Problem 17
In Problems 1 through 20, find a particular solution \(y_{p}\) of the given equation. In all these problems, primes denote derivatives with respect to \(x .\) $$ y^{\prime \prime}+y=\sin x+x \cos x $$
Short Answer
Expert verified
Particular solution: \( y_p = -x \cos x - \sin x \)
Step by step solution
01
Identify the Homogeneous Equation
First, identify the homogeneous version of the given differential equation by setting the right side to zero. We have: \[y^{\prime \prime} + y = 0\]The solution to this will provide the complementary solution.
02
Solve the Homogeneous Equation
This is a second-order linear differential equation with constant coefficients. Its characteristic equation is \[ r^2 + 1 = 0 \]. Solving gives roots \( r = \pm i \). Therefore, the complementary solution is: \[y_c = C_1 \cos x + C_2 \sin x\]where \(C_1\) and \(C_2\) are arbitrary constants.
03
Choose a Form for the Particular Solution
The non-homogeneous term on the right is \( \sin x + x \cos x \). Using the method of undetermined coefficients, guess a particular solution of the form \[y_p = A x \cos x + Bx \sin x + C \sin x\]where \(A\), \(B\), and \(C\) are constants to be determined.
04
Compute Derivatives of the Particular Solution
Compute the first and second derivatives of the guessed particular solution:First derivative:\[y_p' = A (\cos x - x \sin x) + B(\sin x + x \cos x) + C \cos x\]Second derivative:\[y_p'' = -A(2 \sin x + x \cos x) + B(2 \cos x - x \sin x) - C \sin x\]
05
Substitute and Simplify
Substitute \(y_p\), \(y_p'\), and \(y_p''\) into the original differential equation:\[(-A(2 \sin x + x \cos x) + B(2 \cos x - x \sin x) - C \sin x) + (A x \cos x + B x \sin x + C \sin x) = \sin x + x \cos x\]After simplification, collect like terms.
06
Solve for Coefficients
Matching coefficients for each term, solve the following system:- For \(x \cos x\):\[ A = -1 \]- For \(x \sin x\):\[ B = 0 \]- For \(\sin x\) and \(\cos x\) constant terms, determine \(C\) to satisfy the equation:\[-2A + C = 1\] gives \(C = -1\)Therefore, \(A = -1\), \(B = 0\), and \(C = -1\).
07
Write the Particular Solution
With the values of \(A\), \(B\), and \(C\) determined, write the particular solution:\[y_p = -x \cos x - \sin x\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Particular Solution
When dealing with differential equations, one crucial step is finding a particular solution. This is separate from the complementary solution, which solves the homogeneous version of an equation. The particular solution specifically addresses the non-homogeneous part. To create this solution, we conjecture a form that resembles the non-homogeneous term on the right side of the equation.
In this instance, our differential equation is given by:
In this instance, our differential equation is given by:
- The non-homogeneous term: \( \sin x + x \cos x \)
- \( y_p = A x \cos x + B x \sin x + C \sin x \)
Homogeneous Equation
A homogeneous equation is a fundamental concept in solving differential equations. It is obtained by eliminating the non-homogeneous part of the given differential equation. Doing so leaves us with an equation that only involves the derivatives of the function.
- A homogeneous equation helps in finding the complementary solution.
- \( y^{\prime\prime} + y = 0 \)
- \( r^2 + 1 = 0 \)
- \( y_c = C_1 \cos x + C_2 \sin x \)
Method of Undetermined Coefficients
The Method of Undetermined Coefficients is a valuable strategy in differential equations for finding particular solutions to non-homogeneous equations. This method works well when the non-homogeneous part is a function where its derivatives can be expressed similarly, like polynomials, exponentials, sines, and cosines.
- Non-homogeneous term: \( \sin x + x \cos x \)
- Assumed form: \( y_p = A x \cos x + B x \sin x + C \sin x \)
- Given conditions: \( A = -1 \), \( B = 0 \), \( C = -1 \)