Chapter 3: Problem 1
Determine the period and frequency of the simple harmonic motion of a \(4-\mathrm{kg}\) mass on the end of a spring with spring constant \(16 \mathrm{~N} / \mathrm{m}\).
Short Answer
Expert verified
The period is \( \pi \) seconds, and the frequency is \( \frac{1}{\pi} \) Hz.
Step by step solution
01
Understand the Formula for Period
The formula for the period of simple harmonic motion for a mass-spring system is given by \( T = 2\pi \sqrt{\frac{m}{k}} \), where \( m \) is the mass attached to the spring, and \( k \) is the spring constant.
02
Substitute the Values into the Formula
Here, \( m = 4 \) kg and \( k = 16 \) N/m. Substitute these values into the formula: \[ T = 2\pi \sqrt{\frac{4}{16}} \].
03
Calculate the Expression Inside the Square Root
Simplify the expression inside the square root: \( \frac{4}{16} = \frac{1}{4} \). Now the formula becomes \( T = 2\pi \sqrt{\frac{1}{4}} \).
04
Evaluate the Square Root
The square root of \( \frac{1}{4} \) is \( \frac{1}{2} \). Substitute this back into the formula: \( T = 2\pi \times \frac{1}{2} \).
05
Simplify to Find the Period
The expression simplifies to \( T = \pi \). Thus, the period of the motion is \( T = \pi \) seconds.
06
Calculate the Frequency
The frequency \( f \) is the reciprocal of the period: \[ f = \frac{1}{T} = \frac{1}{\pi} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass-Spring System
In the realm of physics, the mass-spring system is a simple way of understanding harmonic motion. This system is characterized by a mass attached to a spring that can oscillate back and forth. When the mass is displaced from its equilibrium position, the spring exerts a force proportional to the displacement, guided by Hooke's Law. This force pulls the mass back toward equilibrium, setting it into motion.
- **Mass**: The object attached to the end of the spring. Its weight impacts the system's dynamics.
- **Spring Constant (k)**: A measure of the spring's stiffness. Larger values indicate a stiffer spring.
Period of Oscillation
The period of oscillation, denoted by \( T \), is the time it takes for the system to complete one full cycle of motion. In a mass-spring system, the period is determined by both the mass \( m \) and the spring constant \( k \).
The formula to calculate the period \( T \) is:
The formula to calculate the period \( T \) is:
- \( T = 2\pi \sqrt{\frac{m}{k}} \)
- First, evaluate the expression inside the square root: \( \frac{m}{k} = \frac{4}{16} = \frac{1}{4} \).
- Next, calculate the square root: \( \sqrt{\frac{1}{4}} = \frac{1}{2} \).
- Finally, find \( T = 2\pi \times \frac{1}{2} = \pi \). Thus, in this scenario, the period \( T \) is \( \pi \) seconds.
Frequency Calculation
The frequency of an oscillating system is the number of complete cycles it undergoes in one second. It's represented by \( f \), and in simple harmonic motion, the frequency is the reciprocal of the period. The formula is:
For the mass-spring example provided, where the period \( T \) is \( \pi \) seconds, the frequency is calculated as:
- \( f = \frac{1}{T} \)
For the mass-spring example provided, where the period \( T \) is \( \pi \) seconds, the frequency is calculated as:
- \( f = \frac{1}{\pi} \approx 0.318 \text{ Hz} \)