/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 First solve the equation \(f(x)=... [FREE SOLUTION] | 91Ó°ÊÓ

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First solve the equation \(f(x)=0\) to find the critical points of the given autonomous differential equation \(d x / d t=f(x) .\) Then analyze the sign of \(f(x)\) to determine whether each critical point is stable or unstable, and construct the corresponding phase diagram for the differential equation. Next, solve the differential equation explicitly for \(x(t)\) in terms of \(t .\) Finally, use either the exact solution or a computer-generated slope field to sketch typical solution curves for the given differential equation, and verify visually the stability of each critical point. $$ \frac{d x}{d t}=x^{2}-4 x $$

Short Answer

Expert verified
Critical points are \(x = 0\) and \(x = 4\), both unstable; typical solutions increase away from \(x = 0\) and \(x = 4\).

Step by step solution

01

Compute Critical Points

To find the critical points, set the differential equation to zero: \( f(x) = x^2 - 4x = 0 \). Factor the equation to find the roots: \( x(x - 4) = 0 \). The critical points are \( x = 0 \) and \( x = 4 \).
02

Analyze Stability at Critical Points

To determine stability, evaluate the sign of \( f(x) = x^2 - 4x \) around each critical point. For \( x \) near 0, choose values like \( x = -1 \) and \( x = 1 \):- For \( x = -1 \), \( f(-1) = (-1)^2 - 4(-1) = 1 + 4 = 5 > 0 \).- For \( x = 1 \), \( f(1) = 1^2 - 4 \times 1 = 1 - 4 = -3 < 0 \).Thus, \( x = 0 \) is unstable (switches from positive to negative).Near \( x = 4 \), choose \( x = 3 \) and \( x = 5 \):- For \( x = 3 \), \( f(3) = 3^2 - 4 \times 3 = 9 - 12 = -3 < 0 \).- For \( x = 5 \), \( f(5) = 5^2 - 4 \times 5 = 25 - 20 = 5 > 0 \).Thus, \( x = 4 \) is also unstable (switches from negative to positive).
03

Construct Phase Diagram

Use the sign analysis to construct the phase diagram:- For \( x < 0 \), \( f(x) > 0 \) indicating increasing behavior.- Between 0 and 4, \( f(x) < 0 \) indicating decreasing behavior.- For \( x > 4 \), \( f(x) > 0 \) indicating increasing behavior.Draw arrows to show decreasing (towards \( x = 0 \)) and increasing (away from \( x = 4 \)) behaviors.
04

Solve Differential Equation for \( x(t) \)

Separate variables to solve \( \frac{d x}{d t} = x^2 - 4x \): \( \frac{1}{x(x - 4)} \frac{dx}{dt} = 1 \).Integrate both sides:\[ \int \frac{1}{x(x-4)} \, dx = \int \, dt \]Partial fraction decomposition: \( \frac{1}{x(x-4)} = \frac{A}{x} + \frac{B}{x-4} \).Solve for \( A \) and \( B \):\[ 1 = A(x - 4) + Bx \rightarrow A = -1/4, B = 1/4 \].Integrate: \(-\frac{1}{4}\ln|x| + \frac{1}{4}\ln|x-4| = t + c \).Simplify: \( \ln|\frac{x - 4}{x}|^{1/4} = t + c \).Exponentiate: \( |\frac{x-4}{x}| = e^{4t+4c} \). Solve for \( x \).
05

Sketch Solution Curves

Use the phase diagram and possible slope fields to sketch solutions:- Solutions start increasing towards 0 from the left of \( x=0 \).- Between 0 and 4, solutions decrease towards negative time infinity.- Starting from \( x=4 \), solutions increase upwards. Verify curves using software for accuracy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Autonomous Differential Equations
Autonomous differential equations are a type of differential equation where the rate of change of a variable, usually denoted by \(x\), only depends on \(x\) itself and not explicitly on the independent variable \(t\) (often time). In the given problem, the autonomous differential equation is \(\frac{dx}{dt} = x^2 - 4x\). This equation indicates that the rate of change of \(x\) with respect to \(t\) is determined by the polynomial \(f(x) = x^2 - 4x\).
A key characteristic of autonomous equations is that their structure allows for analysis of stability and behavior over time without directly inserting time into the equation. This often simplifies analysis since solutions depend on the initial conditions and the form of \(f(x)\). Autonomous equations typically lead to significant concepts like critical points and phase diagrams, allowing us to sketch solution behaviors effectively.
Phase Diagrams
Phase diagrams, sometimes called phase portraits, are graphical representations that show the behavior of differential equations over time. For autonomous differential equations, phase diagrams are particularly useful for demonstrating the stability and attractor dynamics by visualizing how solutions evolve.
In the problem \(\frac{dx}{dt} = x^2 - 4x\), the phase diagram is constructed based on the sign analysis of \(f(x)\) around each critical point. This involves determining whether the solutions are increasing (when \(f(x) > 0\)) or decreasing (when \(f(x) < 0\)):
  • For \(x < 0\), \(f(x) > 0\) suggests solutions move away from zero, increasing.
  • For \(0 < x < 4\), \(f(x) < 0\) suggests solutions decay towards negative infinity.
  • For \(x > 4\), \(f(x) > 0\) suggests solutions rise again, moving away from four.
These directional arrows within the diagram help visualize stability and instability without requiring the full solution to be attained.
Critical Points
Critical points in differential equations occur where the rate of change \(\frac{dx}{dt}\) equals zero, which means the system is at equilibrium at these points. To find them, we set the equation \(f(x) = x^2 - 4x = 0\) to find that \(x = 0\) and \(x = 4\) are the critical points in the given problem.
Understanding the stability of these points is key:
  • At \(x = 0\), \(f(x)\) changes sign from positive to negative, indicating it is an unstable equilibrium. Solutions nearby will tend away from 0.
  • At \(x = 4\), \(f(x)\) changes sign from negative to positive, indicating it too is unstable. Solutions will tend away from 4.
Identifying and analyzing critical points help predict long-term behavior for differential equations, such as oscillations or steady states, which are crucial for fields like physics and biology.
Solution Curves
Solution curves represent the actual trajectories or paths taken by a differential equation over time. In the analysis of the given autonomous equation \(\frac{dx}{dt} = x^2 - 4x\), these are plotted based on initial conditions and computed phase diagrams.
Solving explicitly for \(x(t)\) gives detailed trajectories, but even without exact solutions, you can still derive critical insights using computer-generated slope fields or phase diagrams:
  • Solutions that start with \(x < 0\) initially increase towards zero as \(t\) grows.
  • For initial conditions between zero and four, solutions decrease considerably.
  • With \(x > 4\), solutions start to increase again, diverging away.
Solution curves essentially offer a "big picture" perspective of the autonomous equation’s behavior, especially useful in dynamic systems where understanding potential long-term outcomes is crucial.

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Most popular questions from this chapter

Suppose that the fish population \(P(t)\) in a lake is attacked by a disease at time \(t=0\), with the result that the fish cease to reproduce (so that the birth rate is \(\beta=0\) ) and the death rate \(\delta\) (deaths per week per fish) is thereafter proportional to \(1 / \sqrt{P}\). If there were initially 900 fish in the lake and 441 were left after 6 weeks, how long did it take all the fish in the lake to die?

Use either the exact solution or a computer-generated slope field to sketch the graphs of several solutions of the given differential equation, and highlight the indicated particular solution. $$ \frac{d x}{d t}=7 x(x-13), x(0)=17 $$

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