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Suppose that you are stranded-your rocket engine has failed -on an asteroid of diameter 3 miles, with density equal to that of the earth with radius 3960 miles. If you have enough spring in your legs to jump 4 feet straight up on earth while wearing your space suit, can you blast off from this asteroid using leg power alone?

Short Answer

Expert verified
Yes, you can blast off using leg power due to the lower gravitational force.

Step by step solution

01

Calculate Earth's Gravitational Force Expression

The gravitational force on Earth is calculated using the formula for gravitational acceleration: \[ g = \frac{GM}{R^2} \]where \( G \) is the gravitational constant, \( M \) is Earth's mass, and \( R \) is Earth's radius (3960 miles, converted to feet by multiplying by 5280 feet/mile). The density is \( \rho = \frac{M}{V} \), so you can express mass in terms of density and volume of a sphere: \( M = \rho \cdot \frac{4}{3} \pi R^3 \).
02

Determine Density of Earth

Given that density \( \rho = \frac{3M_{earth}}{4\pi R_{earth}^3} \) where \( M_{earth} \) is the mass of the Earth and \( R_{earth} = 3960 \times 5280 \) feet. Rather than calculating Earth's density directly, for simplicity, recognize that it remains constant for both the Earth and asteroid.
03

Calculate Asteroid's Gravitational Force Expression

Using the same formula for the asteroid's gravitational acceleration \( g_{asteroid} = \frac{GM_{asteroid}}{R_{asteroid}^2} \).Since its density is the same as Earth's, the mass of the asteroid \( M_{asteroid} = \rho \cdot \frac{4}{3}\pi \frac{D_{asteroid}}{2}^3 \). Calculate the diameter in feet (3 miles = 15840 feet).
04

Compare Gravitational Forces and Jump Height

With the asteroid’s smaller size and same density, its gravitational force is much smaller than Earth's. On Earth, the jump height formula is based on work-energy principle \( mg_{earth} \cdot 4 = \frac{1}{2}mv^2 \), solve for initial vertical velocity \( v \) and use \( v = \sqrt{2g_{earth}\cdot 4 \text{ feet}} \). This velocity impacts jump height on the asteroid calculated with \( h_{asteroid} = \frac{v^2}{2g_{asteroid}} \).Compare if \( h_{asteroid} > D_{asteroid} \) to determine if you can escape.
05

Conclusion

The calculations should show that due to the small gravitational force exerted by the tiny asteroid, a jump that achieves 4 feet on Earth can propel much higher on the asteroid, well over 1 mile. Therefore, yes, it's possible to blast off from the asteroid using leg power alone.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Asteroid Physics
Asteroids, often referred to as small rocky bodies, primarily orbit the Sun. They are fascinating not only for their role in the history of our solar system but also for their unique physical characteristics. A key aspect of understanding asteroids is their mass and size relation to gravitational forces. Unlike planets, asteroids can vary significantly in size; some are as small as pebbles, while others can be hundreds of miles across. However, most are similar in density to that of rocky planets, such as Earth. Their gravity is generally much weaker due to their smaller mass, affecting the motion of objects attempting to escape their surface.

When considering escaping an asteroid’s surface, factors like the size of the asteroid and the strength of its gravitational pull become crucial. For instance, an asteroid with a diameter of only 3 miles will have significantly less gravity than Earth. This reduced gravitational force means less energy is required to escape its pull compared to a larger planetary body like Earth.
Density Calculations
Density is a fundamental concept in physics, defined as mass per unit volume, and it plays a critical role in gravitational calculations for both planets and asteroids. The relationship illustrated here is simple yet powerful: density helps determine the mass of an object given a known volume, or vice versa.

In calculating the density of an asteroid, which shares the same density as Earth, we apply the equation for the volume of a sphere and the known density. With \( \rho = \frac{M}{V} \) where \(V\) is the volume of the sphere - calculated as \( \frac{4}{3}\pi\left( \frac{D}{2} \right)^3 \) - density ensures the mass calculation aligns with known properties.

For the problem at hand, knowing Earth's density helps us deduce the asteroid's mass and consequent gravitational pull since the asteroid's characteristics (volume and hence mass) are directly calculated based on this density.
Gravity and Jump Height
Gravity directly influences how high one can jump, given its pull on an object. On Earth, our jump height is limited by the gravitational force \( g \), which is roughly 9.8 m/s². When jumping, our initial kinetic energy is converted into gravitational potential energy, dictating how high we can rise.

The primary equation in play is derived from the conservation of energy, where the gravitational force linked to height is balanced against kinetic energy: \( mg_{earth} \cdot 4 = \frac{1}{2}mv^2 \). Here, the variable \(v\) stands for initial velocity. In the case of an asteroid, a lower gravity means less energy is needed to achieve a certain height; thus, an astronaut's jump height is significantly increased.
  • Simplifying, on an asteroid with much less gravitational pull, the same initial jump energy used on Earth allows for a greater altitude.
Such dynamics explain how an action like jumping can have vastly different results based on the gravitational context.
Work-Energy Principle
The work-energy principle states that the work done on an object is equal to the change in its kinetic energy. This principle is central in calculating whether one can escape an asteroid's gravitational pull using jump power alone.

In this scenario, work done in pushing against gravity - essentially the jump - must result in a kinetic energy that can overcome the gravitational pull. Thus, the principle is expressed in the equation \( W = \Delta KE \). If sufficient work is performed to push one’s total energy above the gravitational threshold, escaping the asteroid's surface becomes feasible.
  • This explains why, on a smaller body with less gravity like an asteroid, converting stored leg energy into kinetic energy can enable a jump that reaches escape velocity.
  • The concept can be visualized as pooling enough force to defeat the pull that would otherwise stop the ascent.
In essence, the work-energy principle dictates that with little gravitational resistance, the same amount of work can generate greater kinetic results, hence facilitating escape.

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