Chapter 10: Problem 15
Show that the eigenvalues and eigenfunctions of the Sturm-Liouville problem
$$
\begin{aligned}
y^{\prime \prime}+\lambda y &=0 & &(0
Short Answer
Expert verified
Eigenvalues \( \lambda_0 = 0 \), \( \lambda_n = \beta_n^2 \) and eigenfunctions \( y_0(x) = x-1 \), \( y_n(x) = \beta_n \cos(\beta_n x) - \sin(\beta_n x) \), for \( n \geq 1 \).
Step by step solution
01
Formulate the General Solution
To start solving the problem, we take the differential equation \( y'' + \lambda y = 0 \). A standard form solution for such differential equations is \( y(x) = A \cos(\sqrt{\lambda} x) + B \sin(\sqrt{\lambda} x) \), with constants \( A \) and \( B \).
02
Apply Boundary Condition at x=1
The boundary condition \( y(1) = 0 \) leads to \( A \cos(\sqrt{\lambda}) + B \sin(\sqrt{\lambda}) = 0 \). Simplifying gives the relationship \( A = -B \tan(\sqrt{\lambda}) \).
03
Apply Boundary Condition at x=0
Using the boundary condition \( y(0) + y'(0) = 0 \), we find \( A + \sqrt{\lambda} B = 0 \). By solving this together with the result of Step 2, eliminate constants \( A \) and \( B \) to better reveal the conditions for \( \lambda \).
04
Solve for the Eigenvalues
Combining the equations \( A = -B \tan(\sqrt{\lambda}) \) and \( A = -\sqrt{\lambda} B \), we equate \( \tan(\sqrt{\lambda}) = \sqrt{\lambda} \). For non-zero solutions, \( \lambda \) must satisfy \( \tan(\sqrt{\lambda}) = \sqrt{\lambda} \). This implies the sequence \( \beta_{n} \) are positive roots of \( \tan x = x \) yielding eigenvalues \( \lambda_{n} = \beta_n^2 \), \( n \geq 1 \).
05
Verify Zero Eigenvalue and Eigenfunction
For \( \lambda = 0 \), the differential equation simplifies to \( y'' = 0 \), leading to the solution \( y(x) = Cx + D \). The boundary conditions \( y(0) + y'(0) = 0 \) and \( y(1) = 0 \) give \( C = -D \) and \( C(1) + D = 0 \) respectively. Solving yields \( C = -1, D = 1 \), rendering \( y_0(x) = x - 1 \).
06
Construct Eigenfunctions
For \( \lambda_n = \beta_{n}^2 \), the corresponding eigenfunctions are derived from general form with \( A = B \tan(\beta_n) \). Using conditions yields \( y_n(x) = \beta_n \cos(\beta_n x) - \sin(\beta_n x) \). This solution satisfies both boundary conditions and the differential equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Eigenvalues
In the realm of the Sturm-Liouville problem, eigenvalues represent special values of the parameter \( \lambda \) where the boundary value problem has non-trivial solutions. In the problem discussed, these eigenvalues are derived from the equation:
- \( y'' + \lambda y = 0 \)
Eigenfunctions
Eigenfunctions are the corresponding functions that satisfy both the given differential equation and its associated boundary conditions for respective eigenvalues. In the given Sturm-Liouville problem, for \( \lambda_n = \beta_n^2 \), the eigenfunctions take the form:
- \( y_n(x) = \beta_n \cos(\beta_n x) - \sin(\beta_n x) \)
Differential Equations
The heart of the Sturm-Liouville problem is understanding differential equations. A differential equation involves derivatives of a function and provides critical insights into various physical phenomena. In this specific task, the differential equation given is:
- \( y'' + \lambda y = 0 \)
Boundary Conditions
Boundary conditions are vital components that complement differential equations by imposing specific restrictions necessary for a unique solution. In the analyzed problem, we deal with the following boundary conditions:
- \( y(0) + y'(0) = 0 \)
- \( y(1) = 0 \)