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A function \(y=g(x)\) is described by some geometric property of its graph. Write a differential equation of the form \(d y / d x=f(x, y)\) having the function \(g\) as its solution (or as one of its solutions). The slope of the graph of \(g\) at the point \((x, y)\) is the sum of \(x\) and \(y\).

Short Answer

Expert verified
The differential equation is \(\frac{dy}{dx} = x + y\).

Step by step solution

01

Understand the Problem

We are given a geometric property of a function's graph, namely the slope at any point \((x, y)\) is the sum of \(x\) and \(y\). Our task is to express this property as a differential equation of the form \(dy/dx = f(x, y)\) so that the function \(g(x)\) which possesses this property is a solution.
02

Express the Slope of the Tangent

The slope of the tangent line at any point \((x, y)\) on the graph of a function \(y=g(x)\) can be represented by the derivative \(dy/dx\). According to the problem statement, this slope is the sum of the coordinates \(x\) and \(y\). So we write this as \(\frac{dy}{dx} = x + y\).
03

Formulate the Differential Equation

Using the information from Step 2, we can directly write the differential equation that \(g(x)\) satisfies: \(\frac{dy}{dx} = f(x, y) = x + y\). This equation captures the given property of the function \(g(x)\), where its slope at any point is the sum of \(x\) and \(y\).
04

Conclude with the General Solution Form

Not asked explicitly, but understanding that the differential equation can be solved to find solutions, we recognize that this problem describes an initial setup for solving ordinary differential equations where \(y\) is expressed in terms of \(x\) through integration and other techniques.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope of a Graph
When you hear the term "slope of a graph," think about the steepness or the direction of a line. In the context of a function,
the slope tells us how much the function's value (y) changes for a small change in the input (x).
This is captured by the derivative d y/d x, which is central to understanding any graph's behavior.

In our problem, the slope is given a specific geometric property: at any point (x, y) is the sum of x and y.
This means if you move slightly in the x direction, you add both the current x-coordinate and the current y-coordinate together to determine the y-coordinate change.
This relationship is expressed in mathematical terms as \(\frac{dy}{dx} = x + y\), directly tying the slope to the position on the graph.
  • The slope equation helps understand how quickly and in what direction the graph rises or falls.
  • This can illustrate key features of the graph, such as maximum or minimum points, where the slope becomes zero.
This creates a dynamic picture of how the function behaves at any moment.
Geometric Properties
Geometric properties give us insight into the shape and behavior of graphs. Understanding these helps us knit together visuals with equations.
They cover features such as symmetry, slopes, intercepts, and the general form of the graph at various points.
In our specific problem, the geometric property is that the graph's slope at any point is the sum of x and y.
This property is not just a random coincidence but a deliberate characteristic that shapes the entire curve's trajectory.
With the equation \(\frac{dy}{dx} = x + y\):
  • The linear form y = x + y in the slope expression hints at consistent growth.
  • This alignment suggests that as x gains value, y also increases, conforming to the linear geometric property.
Geometric properties like these help predict a graph's future behavior, deducing how the function stretches and twists across the coordinate plane.
This understanding is crucial for sketching rough graph visuals before exact calculations.
Ordinary Differential Equations
Ordinary Differential Equations (ODEs) are mathematical expressions involving derivatives of a function. They play a big role in describing dynamic systems.
An ODE is called "ordinary" when it involves one independent variable, distinguishing it from partial differential equations which involve multiple variables.
Our equation \(\frac{dy}{dx} = x + y\) is an excellent example of an ODE.
The aim of solving an ODE is to find the function y = g(x) that satisfies the given equation for all x values. This requires techniques like integration, substitution, or linear algebra.
Knowing the ODE provides:
  • A framework to pinpoint the behavior of a function over specific intervals.
  • A way to discover general solutions that fit many initial conditions.
For beginners, understanding ODEs is crucial. They're used in physics to describe motion, in biology for population dynamics, and in finance for model growth rates.
Gaining fluency in ODEs gives you versatile tools to model real-world phenomena accurately.
In many academic and professional settings, they are instrumental for predicting future trends based on current states.

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Most popular questions from this chapter

(a) Find constants \(A\) and \(B\) such that \(y_{p}(x)=A \sin x+\) \(B \cos x\) is a solution of \(d y / d x+y=2 \sin x . \quad\) (b) Use the result of part (a) and the method of Problem 31 to find the general solution of \(d y / d x+y=2 \sin x .\) (c) Solve the initial value problem \(d y / d x+y=2 \sin x, y(0)=1\).

According to one cosmological theory, there were equal amounts of the two uranium isotopes \({ }^{235} \mathrm{U}\) and \({ }^{238} \mathrm{U}\) at the creation of the universe in the "big bang." At present there are \(137.7\) atoms of \({ }^{238} \mathrm{U}\) for each atom of \({ }^{235} \mathrm{U}\). Using the half-lives \(4.51 \times 10^{9}\) years for \({ }^{238} \mathrm{U}\) and \(7.10 \times 10^{8}\) years for \({ }^{235} \mathrm{U}\), calculate the age of the universe.

A water tank has the shape obtained by revolving the curve \(y=x^{4 / 3}\) around the \(y\) -axis. A plug at the bottom is removed at 12 noon, when the depth of water in the tank is \(12 \mathrm{ft}\). At 1 P.M. the depth of the water is \(6 \mathrm{ft}\). When will the tank be empty?

Consider a reservoir with a volume of 8 billion cubic feet (ft \(^{3}\) ) and an initial pollutant concentration of \(0.25 \%\). There is a daily inflow of 500 million \(\mathrm{ft}^{3}\) of water with a pollutant concentration of \(0.05 \%\) and an equal daily outflow of the well-mixed water in the reservoir. How long will it take to reduce the pollutant concentration in the reservoir to \(0.10 \%\) ?

$$ y^{\prime}=(1-y) \cos x, y(\pi)=2 $$

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