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Find the position function \(x(t)\) of a moving particle with the given acceleration a \((t)\), initial position \(x_{0}=x(0)\), and initial velocity \(v_{0}=v(0)\). \(a(t)=2 t+1, v_{0}=-7, x_{0}=4\)

Short Answer

Expert verified
The position function is \(x(t) = \frac{t^3}{3} + \frac{t^2}{2} - 7t + 4\).

Step by step solution

01

Integrate the acceleration function

To find the velocity function, integrate the acceleration function. The given acceleration is \(a(t) = 2t + 1\). Integrate this function with respect to \(t\):\[v(t) = \int (2t + 1) \, dt = t^2 + t + C_1\]
02

Use initial velocity to find constant C1

We are given the initial velocity \(v_0 = -7\). Substitute \(t = 0\) and \(v(0) = -7\) into the velocity equation to solve for \(C_1\):\[v(0) = 0^2 + 0 + C_1 = -7 \]Thus, \(C_1 = -7\). So, the velocity function is:\[v(t) = t^2 + t - 7\]
03

Integrate the velocity function

Integrate the velocity function to find the position function. The velocity function is \(v(t) = t^2 + t - 7\). Integrate this function with respect to \(t\):\[x(t) = \int (t^2 + t - 7) \, dt = \frac{t^3}{3} + \frac{t^2}{2} - 7t + C_2\]
04

Use initial position to find constant C2

Use the initial position \(x_0 = 4\) to find the constant \(C_2\). Substitute \(t = 0\) and \(x(0) = 4\) into the position equation:\[x(0) = \frac{0^3}{3} + \frac{0^2}{2} - 7\cdot0 + C_2 = 4 \]Thus, \(C_2 = 4\). The position function is:\[x(t) = \frac{t^3}{3} + \frac{t^2}{2} - 7t + 4\]
05

Final Position Function

The final position function for the moving particle is:\[x(t) = \frac{t^3}{3} + \frac{t^2}{2} - 7t + 4\] This function describes the position of the particle as a function of time \(t\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Initial Conditions
In the world of differential equations, **initial conditions** play a crucial role. They allow us to pin down the specific solution out of all possible solutions. When a differential equation is involved, you aren't dealing with just one possible answer. Imagine you're trying to find out the position of a moving particle. You have the acceleration and you know the mathematical form of the motion. However, to know the particle's exact trajectory, you must know where it started from and its initial velocity.- Initial position, noted as \(x_0\), tells us the starting point of the particle. Think of it as the particle's address at time zero.- Initial velocity, noted as \(v_0\), indicates how fast and in what direction the particle is moving at the starting point.In our problem, the initial conditions are \(x_0 = 4\) and \(v_0 = -7\). These values are essential for finding the constants in our integration steps and help us pinpoint the exact position function for the particle's motion.
Integration
Integration is a foundational tool used to solve differential equations and find functions from their derivatives. When analyzing particle motion, you often start with acceleration, which is the second derivative of the position function. To find the position function, you need to **integrate** the acceleration function:1. First, integrate acceleration to get the velocity function.2. Next, integrate the velocity function to find the position.Let's break it down:- Integrating the given acceleration \(a(t) = 2t + 1\) provides the velocity function: \[ v(t) = \int (2t + 1) \, dt = t^2 + t + C_1 \]- Where \(C_1\) is an integration constant that can be found using initial velocity conditions.- Then, integrating the velocity \(v(t) = t^2 + t - 7\) gives us the position function: \[ x(t) = \int (t^2 + t - 7) \, dt = \frac{t^3}{3} + \frac{t^2}{2} - 7t + C_2 \]Each integration step adds a constant which is determined using initial conditions, making your solution specific to the problem's scenario.
Particle Motion Analysis
**Particle motion analysis** involves understanding how a particle moves along a path over time, which can be described by its position function \(x(t)\). This analysis is critical in physics and engineering to predict the future movement of objects.- **Position function:** Provides the location of the particle at any given time \(t\). In this exercise, the position function is: \[ x(t) = \frac{t^3}{3} + \frac{t^2}{2} - 7t + 4 \] - **Velocity function:** Derived from the position function, helps us understand the speed and direction at which a particle moves.To analyze particle motion, follow these steps:1. **Calculate acceleration:** Start by understanding how the object's speed changes over time.2. **Integrate to obtain velocity:** This describes how fast the particle is moving at any point in time.3. **Integrate velocity for position:** Finally, determine the exact placement of the particle at any future time.In real-world applications, this entire analysis provides insights into whether a particle is speeding up or slowing down, moving forward or backward, and reaching specific locations at certain times. Understanding the correlation between acceleration, velocity, and position is key to mastering particle motion analysis.

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Most popular questions from this chapter

A tank contains 1000 liters (L) of a solution consisting of \(100 \mathrm{~kg}\) of salt dissolved in water. Pure water is pumped into the tank at the rate of \(5 \mathrm{~L} / \mathrm{s}\), and the mixture - kept uniform by stirring \(-\) is pumped out at the same rate. How long will it be until only \(10 \mathrm{~kg}\) of salt remains in the tank?

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A river \(100 \mathrm{ft}\) wide is flowing north at \(w\) feet per second. A dog starts at \((100,0)\) and swims at \(v_{0}=4 \mathrm{ft} / \mathrm{s}\), always heading toward a tree at \((0,0)\) on the west bank directly across from the dog's starting point. (a) If \(w=2 \mathrm{ft} / \mathrm{s}\), show that the dog reaches the tree. (b) If \(w=4 \mathrm{ft} / \mathrm{s}\) show that the dog reaches instead the point on the west bank \(50 \mathrm{ft}\) north of the tree. (c) If \(w=6 \mathrm{ft} / \mathrm{s}\), show that the dog never reaches the west bank.

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