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A computer will be required for the remaining problems in this section. In Problems 9 through 12, an initial value problem and its exact solution are given. In each of these four problems, use the Runge-Kutta method with step sizes \(h=0.1\) and \(h=0.05\) to approximate to five decimal places the values \(x(1)\) and \(y(1) .\) Compare the approximations with the actual values. $$ \begin{aligned} &x^{\prime}=-x-y-\left(1+t^{3}\right) e^{-t}, \quad x(0)=0 \\ &y^{\prime}=-x-y-\left(t-3 t^{2}\right) e^{-t}, \quad y(0)=1 \\ &x(t)=e^{-t}(\sin t-t), \quad y(t)=e^{-t}\left(\cos t+t^{3}\right) \end{aligned} $$

Short Answer

Expert verified
Use the Runge-Kutta method with step sizes 0.1 and 0.05 to approximate \(x(1)\) and \(y(1)\), comparing with exact values \(x(1) = e^{-1} (\sin 1 - 1)\) and \(y(1) = e^{-1} (\cos 1 + 1)\). Smaller step size should yield more accurate approximations.

Step by step solution

01

Understand the Initial Value Problem

You are given a system of differential equations with initial values to solve using the Runge-Kutta method. Ensure you comprehend each equation and its initial condition: the first equation is \( x'(t) = -x - y - (1+t^3) e^{-t}, \) with \( x(0) = 0, \) and the second is \( y'(t) = -x - y - (t-3t^2) e^{-t}, \) with \( y(0) = 1. \)
02

Recognize Exact Solutions for Comparison

The exact solutions for the differential equations are provided as \( x(t) = e^{-t}(\sin t - t) \) and \( y(t) = e^{-t}(\cos t + t^3). \) These will be used to compare against the Runge-Kutta approximations at \( t = 1. \)
03

Implement the Runge-Kutta Method

Apply the 4th-order Runge-Kutta method to approximate the values. This involves calculating four intermediate values (\(k_1, k_2, k_3, k_4\)) for each function over each step. Use the step sizes \(h = 0.1\) and \(h = 0.05\) and iterate from \(t = 0\) to \(t = 1.\)
04

Calculate for Step Size h=0.1

For \(h=0.1\), compute the intermediate function values at each time step and apply the Runge-Kutta formula to approximately solve the differential equations from \(t=0\) to \(t=1.\) This will give the approximated values \(x(1)\) and \(y(1)\).
05

Calculate for Step Size h=0.05

Repeat the calculation using \(h=0.05\) for higher precision. The smaller step size should yield results closer to the exact solution by more accurately tracing the solution curves across the interval.
06

Compare Approximations to Exact Solutions

Calculate the exact values at \(t=1\) using the given functions: \(x(1) = e^{-1}(\sin 1 - 1)\) and \(y(1) = e^{-1}(\cos 1 + 1^3)\). Compare the results obtained from the Runge-Kutta approximations with these exact values to assess accuracy.
07

Evaluate and Conclude

Analyze the differences between the approximations for both step sizes and the exact solutions. Conclude which step size provided better accuracy and examine possible reasons for any discrepancies observed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
Differential equations are mathematical expressions that relate a function with its derivatives. They are fundamental in modeling various physical systems, where changes in certain variables affect others. In this exercise, we are given a system of two differential equations: \( x'(t) = -x(t) - y(t) - (1+t^3)e^{-t} \) and \( y'(t) = -x(t) - y(t) - (t-3t^2)e^{-t} \). Here, \(x(t)\) and \(y(t)\) are functions of time \(t\), and their derivatives \(x'(t)\) and \(y'(t)\) describe how these functions change over time. Understanding how these equations model the behavior of a system is crucial for analyzing problems in many scientific and engineering fields. By solving them, we can predict future behavior, under a given set of initial conditions.
Initial Value Problem
An initial value problem (IVP) involves a differential equation along with a specified value at a given point, which is usually \(t=0\). This initial condition completes the description of the system. In our problem, we are given \(x(0) = 0\) and \(y(0) = 1\). This means that at the starting point \(t=0\), the function \(x(t)\) has a value of 0, and \(y(t)\) has a value of 1. These initial values are essential as they set the conditions under which the solution operates, providing a starting point for numerical methods such as the Runge-Kutta method to approximate the evolution of these functions over time.
Numerical Approximation
Numerical approximation methods help us find an approximate solution to complex differential equations, which might not be solvable analytically. The Runge-Kutta method is one such technique. Specifically, the fourth-order Runge-Kutta method (RK4) is a powerful tool that balances computational efficiency and accuracy. By using step sizes of \(h=0.1\) and \(h=0.05\), we can incrementally predict the values of \(x(1)\) and \(y(1)\). The RK4 method involves calculating four intermediate values, \(k_1, k_2, k_3,\) and \(k_4\), which help refine the slope estimation at each step. Smaller step sizes usually yield more accurate results because they better trace the curve of the actual solution.
Exact Solution Comparison
Analyzing the accuracy of numerical approximations is vital, and this is done by comparing them to the exact solutions. Given in this problem, the exact solutions are \(x(t) = e^{-t}(\sin t - t)\) and \(y(t)= e^{-t}(\cos t + t^3)\). At \(t=1\), these equations yield exact values for \(x(1)\) and \(y(1)\), which serve as benchmarks to assess the performance of the Runge-Kutta method. By calculating these exact solutions, we can determine how close the Runge-Kutta approximated values are. Discrepancies between these values can indicate the need for smaller step sizes or more precise computation to achieve the desired accuracy.

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Most popular questions from this chapter

Consider the crossbow bolt of Problem 14, fired with the same initial velocity of \(288 \mathrm{ft} / \mathrm{s}\) and with the air resistance deceleration \((0.0002) v^{2}\) directed opposite its direction of motion. Suppose that this bolt is fired from ground level at an initial angle of \(45^{\circ}\). Find how high vertically and how far horizontally it goes, and how long it remains in the air.

Find general solutions of the linear systems in Problems 1 through 20. If initial conditions are given, find the particular solution that satisfies them. In Problems 1 through 6, use a computer system or graphing calculator to construct a direction field and typical solution curves for the given system. $$ x^{\prime}=-3 x+2 y, y^{\prime}=-3 x+4 y ; x(0)=0, y(0)=2 $$

A computer will be required for the remaining problems in this section. In Problems 9 through 12, an initial value problem and its exact solution are given. In each of these four problems, use the Runge-Kutta method with step sizes \(h=0.1\) and \(h=0.05\) to approximate to five decimal places the values \(x(1)\) and \(y(1) .\) Compare the approximations with the actual values. $$ \begin{aligned} &x^{\prime}=x+2 y, \quad x(0)=0 \\ &y^{\prime}=x+e^{-t}, \quad y(0)=0 \\ &x(t)=\frac{1}{9}\left(2 e^{2 t}-2 e^{-t}+6 t e^{-t}\right), \\ &y(t)=\frac{1}{9}\left(e^{2 t}-e^{-t}+6 t e^{-t}\right) \end{aligned} $$

Find general solutions of the linear systems in Problems 1 through 20. If initial conditions are given, find the particular solution that satisfies them. In Problems 1 through 6, use a computer system or graphing calculator to construct a direction field and typical solution curves for the given system. $$ x^{\prime}=x+9 y, y^{\prime}=-2 x-5 y ; x(0)=3, y(0)=2 $$

Suppose that \(L_{1} x=t D x+x\) and that \(L_{2} x=D x+t x\). Show that \(L_{1} L_{2} x \neq L_{2} L_{1} x\). Thus linear operators with variable coefficients generally do not commute.

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