Chapter 3: Problem 1
Find a particular solution \(y_{p}\) of the given equation. In all these problems, primes denote derivatives with respect to \(x\). $$ y^{\prime \prime}+16 y=e^{3 x} $$
Short Answer
Expert verified
The particular solution is \(y_{p} = \frac{1}{25} e^{3x}\).
Step by step solution
01
Analyze the Given Differential Equation
The differential equation given is a second-order linear differential equation with the form \(y'' + 16y = e^{3x}\). The left side represents the homogeneous part and the right side, \(e^{3x}\), is a non-homogeneous term that indicates we need to find a particular solution.
02
Assume a Form for the Particular Solution
Since the non-homogeneous part is \(e^{3x}\), we assume a particular solution of the form \(y_p = A e^{3x}\), where \(A\) is a constant to be determined.
03
Compute the Derivatives
Compute the first and second derivatives of the assumed particular solution:\(y_p = A e^{3x}\), so \(y_p' = 3A e^{3x}\) and \(y_p'' = 9A e^{3x}\).
04
Substitute into the Differential Equation
Substitute \(y_p\), \(y_p'\), and \(y_p''\) into the original differential equation:\(y'' + 16y = 9A e^{3x} + 16A e^{3x} = (9A + 16A) e^{3x}\)Simplify to get \((25A e^{3x}) = e^{3x}\).
05
Solve for the Coefficient A
To satisfy the equation \(25A e^{3x} = e^{3x}\), the coefficients must be equal. This gives \(25A = 1\), so \(A = \frac{1}{25}\).
06
Write the Particular Solution
Thus, the particular solution \(y_{p}\) is \(y_p = \frac{1}{25} e^{3x}\). This satisfies the non-homogeneous differential equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differential Equations
Differential equations are mathematical equations that relate a function with its derivatives. They are extremely important in modeling real-world phenomena like motion, growth, electricity, and even economics. In simpler terms, if you know how something changes over time or space (the derivative), you can use a differential equation to predict its future state (the function).
A differential equation can be classified by its order, which is determined by the highest derivative present in the equation. For example:
Solving differential equations often involves finding a particular function or family of functions that satisfies the equation, allowing us to predict outcomes based on the modeled system.
A differential equation can be classified by its order, which is determined by the highest derivative present in the equation. For example:
- First-order differential equations have the form \( y' = f(x, y) \).
- Second-order differential equations, like the one in our problem, involve the second derivative, \( y'' \).
Solving differential equations often involves finding a particular function or family of functions that satisfies the equation, allowing us to predict outcomes based on the modeled system.
Linear Differential Equation
A linear differential equation is a type of differential equation that involves a linear combination of the unknown function and its derivatives. These equations have the general form:
The given exercise involves a linear second-order differential equation \(y'' + 16y = e^{3x}\). The left side is the linear operator applied to \(y\) and its derivatives, while \(e^{3x}\) is the non-homogeneous term.
The linearity of differential equations allows the superposition principle: if \(y_1\) and \(y_2\) are solutions, then the sum \(c_1y_1 + c_2y_2\) is also a solution. This property is fundamental since it can simplify finding solutions by breaking down complex problems into simpler parts.
- \( a_n(x) \frac{d^n y}{dx^n} + a_{n-1}(x) \frac{d^{n-1} y}{dx^{n-1}} + \ldots + a_1(x) \frac{dy}{dx} + a_0(x)y = g(x) \)
The given exercise involves a linear second-order differential equation \(y'' + 16y = e^{3x}\). The left side is the linear operator applied to \(y\) and its derivatives, while \(e^{3x}\) is the non-homogeneous term.
The linearity of differential equations allows the superposition principle: if \(y_1\) and \(y_2\) are solutions, then the sum \(c_1y_1 + c_2y_2\) is also a solution. This property is fundamental since it can simplify finding solutions by breaking down complex problems into simpler parts.
Non-Homogeneous Equation
A non-homogeneous differential equation includes a term that is not the derivative of the function being studied. This term, \(g(x)\) in the general form of a linear differential equation, makes finding solutions slightly more complex.
In the given equation \(y'' + 16y = e^{3x}\), \(e^{3x}\) is the non-homogeneous part. Detecting this term informs us that aside from solving the homogeneous equation (where \(g(x) = 0\)), we need a particular solution that specifically satisfies the non-homogeneous behavior.
To find this particular solution in a non-homogeneous linear differential equation:
In the given equation \(y'' + 16y = e^{3x}\), \(e^{3x}\) is the non-homogeneous part. Detecting this term informs us that aside from solving the homogeneous equation (where \(g(x) = 0\)), we need a particular solution that specifically satisfies the non-homogeneous behavior.
To find this particular solution in a non-homogeneous linear differential equation:
- Identify the form of the non-homogeneous function \(g(x)\).
- Assume a particular solution based on the form of \(g(x)\) (in this example, \(y_p = A e^{3x}\)).
- Solve for unknown coefficients by substituting back into the original equation.