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In Problems, use a computer system or graphing calculator to plot a slope field and/or enough solution curves to indicate the stability or instability of each critical point of the given differential equation. (Some of these critical points may be semistable in the sense mentioned in Example 6.) $\$$ $$ \frac{d x}{d t}=\left(x^{2}-4\right)^{3} $$

Short Answer

Expert verified
The critical points \( x = 2 \) and \( x = -2 \) are semistable.

Step by step solution

01

Identify Critical Points

Critical points of a differential equation occur where the derivative is zero. For \( \frac{dx}{dt} = (x^2 - 4)^3 \), set \( (x^2 - 4)^3 = 0 \). Solve \( x^2 - 4 = 0 \) to find \( x^2 = 4 \). Thus, the critical points are \( x = 2 \) and \( x = -2 \).
02

Consider Stability of Critical Points

To assess stability, evaluate the derivative of the function:\( f'(x) = 3(x^2 - 4)^2 \times 2x = 6x(x^2 - 4)^2 \). Analyze the sign of \( f'(x) \) near the critical points. If \( f'(x) > 0 \), the function is unstable, if \( f'(x) < 0 \), it's stable, and if \( f'(x) = 0 \), further analysis is needed (could be semistable).
03

Analyze \( x = 2 \)

At \( x = 2 \), \( f'(x) = 6 \times 2 \times 0 = 0 \). This suggests potential semistability. Test points just below and above \( x = 2 \) (e.g., \( x = 1.9, 2.1 \)). \( f'(1.9) \) and \( f'(2.1) \) can be used to understand behavior; they suggest that \( x = 2 \) is a semistable point.
04

Analyze \( x = -2 \)

Similarly at \( x = -2 \), \( f'(x) = 6 \times (-2) \times 0 = 0 \). Again, test points around \( x = -2 \) (e.g., \( x = -2.1, -1.9 \)), and observe behavior. Calculations show similar semistability like \( x = 2 \).
05

Use Graphing Tools

Use a graphing calculator or a computer system to input \( \frac{dx}{dt} = (x^2 - 4)^3 \). Plot the slope field and observe the behavior of solution curves near critical points. This visualization helps confirm the semistability at both \( x = 2 \) and \( x = -2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Critical Points
Critical points are special values in a differential equation where the solution does not change. In simpler terms, these are the values of the variable where the rate of change is zero. For our exercise, we have the differential equation \( \frac{dx}{dt} = (x^2 - 4)^3 \). To find critical points, we set the derivative equal to zero. This translates into solving \((x^2 - 4)^3 = 0\), which simplifies to \(x^2 - 4 = 0\). Solving this gives us \(x = 2\) and \(x = -2\). These values are where the slope of the solution curve is horizontal, indicating no change at that point.

By identifying critical points, we can predict where the differential equation's behavior might alter, shift, or even remain steady. This foundational step is crucial for both stability analysis and the broader study of dynamic systems.
Performing Stability Analysis
Stability analysis helps determine how solutions behave as they approach the critical points over time.

In this exercise, we take the function's derivative, \(f'(x) = 6x(x^2 - 4)^2\), to analyze the stability around critical points. We check the sign of \(f'(x)\) in the neighboring areas of these points:
  • If \(f'(x) > 0\), the point is unstable, meaning solutions move away.
  • If \(f'(x) < 0\), it's stable, with solutions moving towards the point.
  • If \(f'(x) = 0\), it requires further investigation for possible semistability.
When evaluating at \(x = 2\) and \(x = -2\), we find \(f'(x) = 0\), hinting at semistability. By testing values near these critical points, we can further confirm semistability, indicating that solutions slightly above or below the points show oscillatory or dampening behavior without diverging permanently.
Visualizing with Slope Field
A slope field is a graphical representation that provides a visual insight into the behavior of differential equations over time.

By plotting a slope field using a graphing calculator or computer software, we can see a pattern of lines, where each line's slope represents the derivative of the equation at that point. For the equation \(\frac{dx}{dt} = (x^2 - 4)^3\), a slope field illustrates the movement trends of solution curves near our critical points, \(x = 2\) and \(x = -2\).

These visual tools help illustrate how solutions interact with these points, showing whether they approach and stabilize, move away, or behave in a complex manner, confirming any potential semistable behavior noted in the mathematical analysis.
Exploring Semistability
Semistability is a unique concept in differential equations where a critical point is neither completely stable nor completely unstable.

At a semistable point like \(x = 2\) or \(x = -2\), solutions may approach the point from one direction while leaving from the other.
  • The function's derivative being zero at this point indicates the need for deeper analysis.
  • Testing nearby points (such as \(x = 1.9\), \(x = 2.1\), \(x = -2.1\), and \(x = -1.9\)) provides insights into the solution's behavior.
This type of stability can be visualized through oscilloscope behavior or flatlined trajectories inside a slope field, confirming that while solutions might not settle at these points, they exhibit reactive behaviors, crucial for understanding the system's overall dynamics.

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Most popular questions from this chapter

In Problems, use a computer system or graphing calculator to plot a slope field and/or enough solution curves to indicate the stability or instability of each critical point of the given differential equation. (Some of these critical points may be semistable in the sense mentioned in Example 6.) $\$$ $$ \frac{d x}{d t}=\left(x^{2}-4\right)^{2} $$

Separate variables and use partial fractions to solve the initial value problems in Problems \(1-8 .\) Use either the exact solution or a computer- generated slope field to sketch the graphs of several solutions of the given differential equation, and highlight the indicated particular solution. The time rate of change of an alligator population \(P\) in a swamp is proportional to the square of \(P\). The swamp contained a dozen alligators in 1988 , two dozen in 1998 . When will there be four dozen alligators in the swamp? What happens thereafter?

In Problems first solve the equation \(f(x)=0\) to find the critical points of the given autonomous differential equation \(d x / d t=f(x) .\) Then analyze the sign of \(f(x)\) to determine whether each crifical point is stable or unstable, and construct the corresponding phase diagrant for the differential equarion. Next, solve the differential equarion explicitly for \(x(t)\) in terms of t. Finally use either the exact solution or a computer-generated slope field to sketch typical solution curves for the given differential equation, and verify visually the stability of each critical point. $$ \frac{d x}{d t}=-(3-x)^{2} $$

A woman bails out of an airplane at an altitude of 10,000 \(\mathrm{ft}\), falls freely for \(20 \mathrm{~s}\), then opens her parachute. How long will it take her to reach the ground? Assume linear air resistance \(\rho v \mathrm{ft} / \mathrm{s}^{2}\), taking \(\rho=0.15\) without the parachute and \(\rho=1.5\) with the parachute. (Suggestion: First determine her height above the ground and velocity when the parachute opens.)

In Problems first solve the equation \(f(x)=0\) to find the critical points of the given autonomous differential equation \(d x / d t=f(x) .\) Then analyze the sign of \(f(x)\) to determine whether each crifical point is stable or unstable, and construct the corresponding phase diagrant for the differential equarion. Next, solve the differential equarion explicitly for \(x(t)\) in terms of t. Finally use either the exact solution or a computer-generated slope field to sketch typical solution curves for the given differential equation, and verify visually the stability of each critical point. $$ \frac{d x}{d t}=x^{2}-5 x+4 $$

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