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Find general solutions of the differential equations. Primes denote derivatives with respect to \(x\) throughout. $$ y^{\prime}=y+y^{3} $$

Short Answer

Expert verified
The general solution is \( \ln \left( \frac{|y|}{\sqrt{|1+y^2|}} \right) = x + C \).

Step by step solution

01

Recognize the equation type

The given differential equation is \( y' = y + y^3 \), which is a separable differential equation. This means we can rewrite it as \( \frac{dy}{dx} = y + y^3 \).
02

Separate variables

Rewrite the equation in the form that allows variables to be separated: \( \frac{dy}{y + y^3} = dx \). This form allows us to integrate both sides with respect to their respective variables.
03

Simplify the left side

Factor the denominator \( y + y^3 \) as \( y(1 + y^2) \), allowing it to be rewritten as \( \frac{dy}{y(1 + y^2)} \). This simplifies further as \( \frac{1}{y} - \frac{y}{1+y^2} \).
04

Integrate both sides

Integrate \( \frac{1}{y} - \frac{y}{1+y^2} \) with respect to \( y \) and the right side with respect to \( x \). The integrals are \( \int \left( \frac{1}{y} - \frac{y}{1+y^2} \right) dy = \ln|y| - \frac{1}{2} \ln|1+y^2| \) and \( \int dx = x + C \).
05

Combine integrated results

The result of the integration yields \( \ln|y| - \frac{1}{2} \ln|1+y^2| = x + C \). We can rewrite this as \( \ln \left( \frac{|y|}{\sqrt{|1+y^2|}} \right) = x + C \).
06

Solve for y

Exponentiate both sides to remove the natural log and solve for \( y \): \( \frac{|y|}{\sqrt{|1+y^2|}} = e^{x+C} \). This results in \( |y| = \sqrt{|1+y^2|} e^{x+C} \). Depending on initial conditions or further simplification, solve explicitly for \( y \).
07

Simplify and express \( y \)

Manual simplification or boundary conditions are often needed to express \( y \) explicitly. However, generally, this equation represents the implicit solution involving \( y \), with specific solutions derived from initial conditions if provided.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Separable Differential Equations
A separable differential equation is a type of differential equation that can be rearranged in such a way that all terms involving the dependent variable (usually denoted as \(y\)) are on one side of the equation, while all terms involving the independent variable (usually \(x\)) are on the other. This separation allows each side to be integrated independently.

To separate the variables, we start with the equation in the form \(\frac{dy}{dx} = f(y) g(x)\). The next step is to rearrange it as \(f(y)\, dy = g(x)\, dx\).

In practice, separation of variables often involves recognizing that the equation allows such a division, as seen in the original problem where \(y' = y + y^3\) was rewritten as \(\frac{dy}{y + y^3} = dx\). This step is crucial for solving the differential equation using integration.
Integration
Integration is the process of finding an integral, which is the reverse operation of differentiation. It helps to find a function when its derivative or rate of change is known. In the context of separable differential equations, integration is used to solve for the function after the variables have been separated.

Once the differential equation has been rearranged to isolate differentials, like \(\int \frac{1}{y} - \frac{y}{1+y^2} \, dy = \int dx\), the next step is to solve these integrals independently. This means finding functions whose derivatives match the given expressions:
  • The integral \(\int \frac{1}{y} \, dy\) gives \(\ln|y|\).
  • The integral \(\int \frac{y}{1+y^2} \, dy\) gives \(-\frac{1}{2} \ln|1+y^2|\).
Combining these results provides an expression involving both \(y\) and \(x\). Each integration might require special techniques or simplifications to complete.
General Solutions
A general solution to a differential equation includes all possible solutions, symbolized by an arbitrary constant \(C\). This reflects that many functions can satisfy a differential equation, and specific solutions can be found by choosing particular values for \(C\) based on additional conditions.

When we integrate both sides of a separated differential equation, our resulting expression, such as \(\ln \left( \frac{|y|}{\sqrt{|1+y^2|}} \right) = x + C\), becomes the general solution. This indicates that there are infinitely many curves, all differing just by a vertical shift controlled by \(C\), that satisfy the differential equation.

Without initial or boundary conditions, we cannot determine a unique solution, so we generalize by including \(C\), which allows for flexibility and a complete family of solutions.
Implicit Solutions
An implicit solution occurs when the solution to a differential equation is not expressed solely as \(y=f(x)\), but rather in a relationship involving both \(y\) and \(x\). This happens quite commonly in differential equations since not all can be easily solved for \(y\) explicitly.

In our example, the solution derived \(\frac{|y|}{\sqrt{|1+y^2|}} = e^{x+C}\) is an implicit solution. Solving for \(y\) can be complicated, and the nature of the function derived means algebraic manipulation might not neatly isolate \(y\).

Implicit solutions are often sufficient, especially if simplifying further does not provide additional clarity or insights, or when they give necessary information about the behavior of the function across different domains. In many cases, using implicit forms aids in maintaining general solution frameworks without unnecessary complexity.

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