Chapter 3: Problem 11
$$ \left(D^{2}-6 D+13\right) y=0 $$
Short Answer
Expert verified
The solution is \(y(t) = e^{3t}(C_1 \cos(2t) + C_2 \sin(2t))\).
Step by step solution
01
Identify the Characteristic Equation
The given differential equation is a second-order linear homogeneous differential equation: \(\left(D^{2}-6D+13\right)y=0\). The characteristic equation for this is obtained by replacing \(D\) with \(r\), resulting in \(r^2 - 6r + 13 = 0\).
02
Solve the Characteristic Equation
Use the quadratic formula \(r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where \(a = 1\), \(b = -6\), and \(c = 13\) to solve \(r^2 - 6r + 13 = 0\). Compute \(b^2 - 4ac = 36 - 52 = -16\). The discriminant is negative, indicating complex roots.
03
Find the Complex Roots
Since the discriminant is \(-16\), the complex roots are computed as: \(r = \frac{6 \pm \,i\sqrt{16}}{2} = \frac{6 \pm 4i}{2} = 3 \pm 2i\).
04
Write the General Solution
For complex roots of the form \(\alpha \pm \beta i\), the general solution is \(y(t) = e^{\alpha t}(C_1 \cos(\beta t) + C_2 \sin(\beta t))\). Here, \(\alpha = 3\) and \(\beta = 2\), so the solution is \(y(t) = e^{3t}(C_1 \cos(2t) + C_2 \sin(2t))\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Characteristic Equation
In second-order linear differential equations, the characteristic equation is crucial because it helps us determine the nature of the roots, which are essential for finding the equation's solution. For a differential equation such as \((D^2 - 6D + 13)y=0\), we replace the differential operator \(D\) with \(r\) to derive the characteristic equation: \(r^2 - 6r + 13 = 0\). This transformation makes it a quadratic equation, which is typically easier to solve.
You'll often use the quadratic formula \(r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) to find the roots. Here, \(a\) is the coefficient of \(r^2\), \(b\) is the coefficient of \(r\), and \(c\) is the constant term. Calculating the discriminant \(b^2 - 4ac\) will tell us whether the roots are real or complex.
You'll often use the quadratic formula \(r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) to find the roots. Here, \(a\) is the coefficient of \(r^2\), \(b\) is the coefficient of \(r\), and \(c\) is the constant term. Calculating the discriminant \(b^2 - 4ac\) will tell us whether the roots are real or complex.
- If the discriminant is positive, the equation has two distinct real roots.
- If it is zero, there are two real and equal roots.
- If negative, the roots are complex.
Complex Roots
Complex roots emerge when the discriminant of the quadratic equation (\(b^2 - 4ac\)) is negative. In our example, the computation \(36 - 52 = -16\) gives us a negative value, suggesting we have complex roots. Solving further with the quadratic formula, the roots are \(r = \frac{6 \pm 4i}{2}\), leading to \(3 \pm 2i\).
This means each root consists of a real part, \(\alpha = 3\), and an imaginary part, \(\beta = 2\). These roots are paired as they are conjugates of each other, forming solutions like \(r = 3 + 2i\) and \(r = 3 - 2i\). Understanding complex roots is essential because they introduce oscillatory components to the solution.
This means each root consists of a real part, \(\alpha = 3\), and an imaginary part, \(\beta = 2\). These roots are paired as they are conjugates of each other, forming solutions like \(r = 3 + 2i\) and \(r = 3 - 2i\). Understanding complex roots is essential because they introduce oscillatory components to the solution.
- Complex roots come in conjugate pairs.
- The real part affects exponential growth or decay.
- The imaginary part introduces sine and cosine oscillations.
General Solution of Differential Equations
For second-order homogeneous differential equations with complex roots, the general solution takes a specific, recurring form. When roots are of the form \(\alpha \pm \beta i\), the solution is given by:
Here, \(C_1\) and \(C_2\) are arbitrary constants determined by initial conditions. The exponential term \(e^{\alpha t}\) represents either decay or growth, while the trigonometric part describes oscillations, determined by the \(cos\) and \(sin\) functions.
- \(y(t) = e^{\alpha t}(C_1 \cos(\beta t) + C_2 \sin(\beta t))\)
Here, \(C_1\) and \(C_2\) are arbitrary constants determined by initial conditions. The exponential term \(e^{\alpha t}\) represents either decay or growth, while the trigonometric part describes oscillations, determined by the \(cos\) and \(sin\) functions.
- Exponential functions denote the influence of real roots.
- Trigonometric functions represent the impact of imaginary components.
- Constants \(C_1\) and \(C_2\) are often set by boundary or initial conditions.