/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Which of the statements are nece... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Which of the statements are necessarily true? (A) If \(\mathrm{f}\) is differentiable and \(\mathrm{f}(-1)=\mathrm{f}(1)\), then there is a number \(\mathrm{c}\) such that \(|\mathrm{c}|<\mathrm{l}\) and \(\mathrm{f}^{\prime}(\mathrm{C})=0\). (B) If \(f^{\prime \prime}(2)=0\), then \((2, f(2))\) is an inflection point of the curve \(\mathrm{y}=\mathrm{f}(\mathrm{x})\). (C) There exists a function \(f\) such that \(f(x)>0, f(x)<0\), and $f^{\prime \prime}(x)>0\( for all \)x$. (D) If \(f^{\prime}(x)\) exists and is nonzero for all \(x\), then $f(1) \neq f(0) .$

Short Answer

Expert verified
A) For a differentiable function f, if f(-1) = f(1), there exists a number c such that |c| < 1 and f'(c) = 0. B) If f''(2) = 0, then the point (2, f(2)) is an inflection point. C) There exists a function f such that f(x) > 0, f''(x) < 0, and f(1) = f(0). D) If f'(x) exists and is nonzero for all x, then f(1) ≠ f(0). Answer: Statements A and D are necessarily true, while statements B and C are not.

Step by step solution

01

Statement A: Rolle's Theorem Application

By Rolle's Theorem, if a function is continuous on the interval [a, b], differentiable on the interval (a, b), and f(a) = f(b), then there exists a number c in the interval (a, b) such that the derivative f'(c) = 0. In this case, a = -1, b = 1, and f(-1) = f(1). Since f is differentiable, it's also continuous. Therefore, there exists a number c such that |c| < 1 (c is in the interval (-1, 1)) and f'(c) = 0. Statement A is true.
02

Statement B: Inflection Point Analysis

An inflection point is a point on a curve where the concavity of the function changes. If f''(2) = 0, that simply means that the second derivative is 0 at x = 2. This condition by itself is not sufficient to conclude that (2, f(2)) is an inflection point. We also require that f''(x) changes its sign around x = 2. Statement B is not necessarily true.
03

Statement C: Function Properties Examination

Statement C is self-contradictory. A function cannot be simultaneously greater than 0 (f(x) > 0) and less than 0 (f(x) < 0). This statement is false.
04

Statement D: Nonzero Derivative Analysis

If f'(x) exists and is nonzero for all x, that implies that f is strictly increasing or strictly decreasing for all x. This means that f(1) and f(0) cannot be equal, otherwise it would contradict the given condition. Therefore, f(1) ≠ f(0), and statement D is true. In summary, statements A and D are necessarily true, while statements B and C are not.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For any real \(\theta\), the maximum value of \(\cos ^{2}(\cos \theta)+\) $\sin ^{2}(\sin \theta)$ is (A) 1 (B) \(1+\sin ^{2} 1\) (C) \(\left.1+\cos ^{2}\right]\) (D) Does not exist

Consider $\mathrm{f}(\mathrm{x})=|1-\mathrm{x}| 1<\mathrm{x}<2 \quad 1 \leq \mathrm{x} \leq 2$ and \(g(x)=f(x)+b \sin \pi / 2 x, \quad 1 \leq x \leq 2\) then which of the following is correct? (A) Rolles Theorem is applicable to both \(\mathrm{f}, \mathrm{g}\) and \(\mathrm{b}=3 / 2\) (B) LMVT is not applicable to \(\mathrm{f}\) and Rolle's Theorem if applicable to \(g\) with \(b=1 / 2\) (C) LMVT is applicable to \(\mathrm{f}\) and Rolle's Theorem is applicable to \(g\) with \(b=1\) (D) Rolle's Theorem is not applicable to both \(\mathrm{f}, \mathrm{g}\) for any real \(\underline{b}\)

Let \(f(x)=a x^{5}+b x^{4}+c x^{3}+d x^{2}+e x\), where \(a, b_{1} c, d, e \in R\) and \(f(x)=0\) has a positive root \(\alpha\), then (A) \(\mathrm{f}(\mathrm{x})=0\) has root al such that \(0<\alpha_{1}<\alpha\) (B) \(\mathrm{f}^{\prime}(\mathrm{x})=0\) has at least one real root (C) \(\mathrm{f}^{\prime}(\mathrm{x})=0\) has at least two real roots (D) All of the above

A differentiable function \(\mathrm{f}(\mathrm{x})\) has a relative minimum at \(x=0\), then the function \(y=f(x)+a x+b\) has a relative minimum at \(x=0\) for (A) all a and all \(b\) (B) all b if \(\mathbf{a}=0\) (C) all \(b>0\) (D) all \(\mathrm{a}>0\)

The function \(\mathrm{f}(\mathrm{x})=\left|\frac{\mathrm{x}^{2}-2}{\mathrm{x}^{2}-4}\right|\) has (A) no point of local minima (B) no point of local maxima (C) exactly one point of local minima (D) exactly one point of local maxima

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.