Chapter 8: Problem 2
Find the slope of the normal to the curve \(y=x^{x}+1\) at \(x=2\).
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Chapter 8: Problem 2
Find the slope of the normal to the curve \(y=x^{x}+1\) at \(x=2\).
These are the key concepts you need to understand to accurately answer the question.
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The length of sub-tangent to the curve \(\sqrt{x}+\sqrt{y}=3\) at \((4,1)\) is (a) 2 (b) \(\frac{1}{2}\) (c) \(-3\) (d) 4
The area of the triangle formed by the tangent to the curve \(y=\frac{8}{4+x^{2}}\) at \(x=2\) and the co-ordinate axes is (a) 2 sq. units (b) 4 sq. units (c) 8 sq. units (d) \(\frac{7}{2}\) sq. units
If the tangent at \(P\) to the curve \(y^{2}=x^{3}\) intersects the curve again at \(Q\) and the straight line \(O P, O Q\) makes angles \(\alpha, \beta\) with the \(x\)-axis, where \(O\) is origin, then find the value of \(\left(\frac{\tan \alpha}{\tan \beta}+2013\right)\).
Let the line be \(y=x-2\) and the parabola be \(y=x^{2}\) \(+3 x+2\). Then (a) the nearest point between the curves is \((-1,0)\) (b) the nearest point between the curves is \((-2,0)\) (c) the shorest distance between the curves is \(\frac{3}{\sqrt{2}}\) (d) the shorest distance between the curves is \(\frac{5}{\sqrt{2}}\)
Minimum distance between two points \(P\) and \(Q\), where \(P\) lies on the parabola \(y^{2}-x+2=0\) and \(Q\) lies on the parabola \(x^{2}-y+2=0\) is (a) \(7 \sqrt{2}\) (b) 4 (c) \(\frac{7}{2 \sqrt{2}}\) (d) None
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