/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 If \(x=\tan \left(\frac{y}{2}\ri... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If \(x=\tan \left(\frac{y}{2}\right)-\left(\frac{(1+\tan (y / 2))^{2}}{\tan (y / 2)}\right)\), prove that \(2 \frac{d y}{d x}=-\sin y(1+\sin y+\cos y)\)

Short Answer

Expert verified
\(2 \frac{d y}{d x} = -2\sin y(1+\sin y+\cos y)\)

Step by step solution

01

Differentiate the Given Equation Implicitly

Given \( x=\tan \left(\frac{y}{2}\right)-\left(\frac{(1+\tan (y / 2))^{2}}{\tan (y/ 2)}\right) \), implicitly differentiating both sides with respect to x, we get: \( 1 = \frac{1}{2}(1+\tan^2(\frac{y}{2}))\frac{dy}{dx} - \frac{2(1+\tan( \frac{y}{2} ))}{\tan^2(\frac{y}{2})}\frac{dy}{dx} \)
02

Calculate the Derivative \( \frac{d y}{d x} \)

Rearrange and simplify to find the derivative: \( \frac{d y}{d x} = \frac{2}{1+ \frac{2}{1+\tan(\frac{y}{2})}} = 2(1 - \sin(\frac{y}{2})) \)
03

Replace \( \sin(\frac{y}{2}) \)

Notice that on the right-hand side of the equation, we have \( 1+\sin y+\cos y \). It can be broken down into \( 2\cos^2(\frac{y}{2}) + 2\sin(\frac{y}{2})\cos(\frac{y}{2}) = 2(1 - \sin(\frac{y}{2})) \). Replacing \( 1 - \sin(\frac{y}{2}) \) in the derivative \( \frac{d y}{d x} \) we get: \( \frac{d y}{d x} = -\sin y(1+\sin y+\cos y) \)
04

Obtain the Final Answer

Multiply both sides by 2 to match the form in the given problem: \( 2 \frac{d y}{d x} = -2\sin y(1+\sin y+\cos y) \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.