Chapter 4: Problem 63
Let \(f(x)=[x] \sin (\pi x)\), where \([,]=\), G.I.F Find the L.H.D at \(x=k\), where \(k \in 1\).
Short Answer
Expert verified
The Left Hand Derivative (L.H.D) of the function at \(x=k\) is \(f'(k-) = 0\).
Step by step solution
01
Understand the function
The function given is \(f(x)=[x] \sin (\pi x)\). Here, \([x]\) denotes the Greatest Integer Function (G.I.F) or Floor function, which gives the greatest integer less than or equal to x. The \(\sin (\pi x)\) is a periodic function.
02
Apply the product rule
The function \(f(x)\) is a product of two functions - G.I.F and sine function. To find the derivative, we could apply the product rule. However, since G.I.F is constant, its derivative is 0. Thus, derivative of f(x) simplifies to: \[f'(x) = [x]*0 + 0*\sin(\pi x) = 0\]. But we are required to find L.H.D, so we must proceed further.
03
Find the L.H.D at x=k
The Left Hand Derivative is the value the derivative approaches as we approach the point of interest from the left side. Formally, it's expressed as \(f'(x) = \lim_{{h \to 0-}} \frac{f(x+h)-f(x)}{h}\). Since \(f'(x) = 0\), the limit simplifies to \(f'(k-) = \lim_{{h \to 0-}} \frac{0-0}{h} = 0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Left Hand Derivative
The left hand derivative of a function at a given point is a way to describe how the function behaves as it approaches that point from the left side along the x-axis. When you calculate the left hand derivative, you focus on the limit of the difference quotient as the interval h between x and x+h approaches zero from the negative side. This term mathematically can be stated as:
- The left hand derivative at a point \( x = a \) is \( f'(a^-) = \lim_{{h o 0^-}} \frac{f(a + h) - f(a)}{h} \).
Product Rule
The product rule is an essential derivative rule in calculus which helps find the derivative of functions that are products of two other functions. If a function \( f(x) \) is defined as the product of two functions \( u(x) \) and \( v(x) \), i.e., \( f(x) = u(x) \cdot v(x) \), then its derivative \( f'(x) \) is given by:
In our original problem, the function involves \([x] \sin(\pi x)\), which is a product of the greatest integer function \([x]\) and the sine function \(\sin(\pi x)\). However, it’s crucial to understand that for derivative purposes, the greatest integer function is considered constant for non-integer inputs, leading to derivatives of zero in this particular breakdown, which simplifies the process quite significantly when computing further derivatives.
- \( f'(x) = u'(x)v(x) + u(x)v'(x) \)
In our original problem, the function involves \([x] \sin(\pi x)\), which is a product of the greatest integer function \([x]\) and the sine function \(\sin(\pi x)\). However, it’s crucial to understand that for derivative purposes, the greatest integer function is considered constant for non-integer inputs, leading to derivatives of zero in this particular breakdown, which simplifies the process quite significantly when computing further derivatives.
Periodic Function
A periodic function is a function that repeats its values in regular intervals or periods. Mathematically, a function \( f(x) \) is called periodic with period T if for all \( x \), \( f(x + T) = f(x) \). One of the most well-known periodic functions is the sine function, which repeats its values every \( 2\pi \).
- The periodicity of \( \sin(\pi x) \) plays an essential role in ensuring that the behavior patterns repeat predictably, simplifying analyses and calculations, particularly in integral and derivative applications.