/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Find the range of the function \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the range of the function \(f(x)=2 \cos x+\sec ^{2} x, x \in\left(0, \frac{\pi}{2}\right)\)

Short Answer

Expert verified
The range of the function \(f(x)=2 \cos x+\sec^{2} x, x \in\left(0,\frac{\pi}{2}\right)\) is \(y\geq3\).

Step by step solution

01

Identify the Maximum and Minimum of Each Trigonometric Function

The \(\cos x\) function has a range from -1 to 1, and within the domain of \(0, \frac{\pi}{2}\) it reduces from 1 to 0. On the other hand, \(\sec^{2} x\) is equivalent to \(1 / \cos^{2} x\), and it will increase from 1 to \(\infty\) when \(x\) changes from 0 to \(\frac{\pi}{2}\).
02

Determine the Maximum and Minimum of the Function

As \(x\) varies from 0 to \(\frac{\pi}{2}\), the value of the function will vary from a maximum to a minimum. The maximum of \(f(x)\) within the domain occurs at \(x=0\) and the minimum occurs at \(x=\frac{\pi}{2}\). Evaluating the function at these points gives: - At \(x=0\), \(f(x)\) becomes \(2(1) + 1 = 3\), - At \(x=\frac{\pi}{2}\), \(f(x)\) becomes \(2(0) + \infty = \infty\).
03

Determine the Range

From the above evaluations, we see that the function spans from 3 to \(\infty\) as \(x\) varies from 0 to \(\frac{\pi}{2}\). Therefore, the range of the function is all real numbers greater than or equal to 3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cosine Function
The cosine function, denoted as \( \cos x \), is one of the basic trigonometric functions. It helps describe the horizontal component of an angle in the unit circle. In a general sense, the value of \( \cos x \) varies between -1 and 1 for all angles in radians. However, within the specific domain of \(0\) to \( \frac{\pi}{2}\), which is the first quadrant of the unit circle, the cosine function value starts at 1 when \( x = 0 \) and decreases to 0 as \( x \) approaches \( \frac{\pi}{2} \). This behavior is crucial because knowing how the cosine function behaves in this domain helps in understanding other trigonometric properties.

Overall, the cosine function plays a vital role in determining angles and distances, particularly when working with right triangles and circular motion.
Secant Function
The secant function, represented as \( \sec x \), is closely related to the cosine function. It is defined as the reciprocal of the cosine function: \( \sec x = \frac{1}{\cos x} \). This means the secant function is undefined where the cosine function equals zero because division by zero is undefined.

In the domain of \( x \in (0, \frac{\pi}{2}) \), the secant function becomes positive and increases as \( x \) gets closer to \( \frac{\pi}{2} \), moving from 1 to approaching infinity. This is due to \( \cos x \) approaching zero, leading the value of \( \sec x = \frac{1}{\cos x} \) to increase infinitely.
  • When \( x = 0 \): \( \sec x = 1 \).
  • As \( x \rightarrow \frac{\pi}{2} \): \( \sec x \rightarrow \infty \).
This function is significant in trigonometry, particularly when dealing with secant secures relationships in waveforms and oscillations.
Range of a Function
The range of a function refers to the set of all possible output values (\( y \)-values) a function can produce. For the specific function given, \( f(x) = 2 \cos x + \sec^2 x \), determining the range involves considering how each trigonometric component behaves in the defined domain.

From the cosine function, we know within \( x \in (0, \frac{\pi}{2}) \), \( \cos x \) decreases from 1 to 0. Simultaneously, \( \sec^2 x = \left( \frac{1}{\cos x} \right)^2 \) starts at 1 and increases to infinity as \( x \) approaches \( \frac{\pi}{2} \).
  • At \( x = 0 \): \( f(x) = 2(1) + 1 = 3 \).
  • As \( x \to \frac{\pi}{2} \): \( f(x) \to \infty \).
Hence, within this domain, the function progresses from an output of 3 to values that become infinitely large.
The calculated range for \( f(x) \) is therefore \([3, \infty)\), meaning it includes all real numbers from 3 upwards.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.