Chapter 1: Problem 143
Let \(f: R^{+} \rightarrow R\) be defined as \(f(x)=x^{2}-x+2\) and \(g:[1,2] \rightarrow[1,2]\) be defined as \(g(x)=\\{x\\}+1\), where \(\\{,\\}=\), Fractional part function. If the domain and range of \(f(g(x))\) are \([a, b]\) and \([c, d)\), then find the value of \(\frac{b}{a}+\frac{d}{c}\)
Short Answer
Expert verified
The value of \(\frac{b}{a}+\frac{d}{c}\) is 2.
Step by step solution
01
Understanding the Function \(g(x)\)
The function \(g(x)\) is defined on the interval [1,2] and has the form \(g(x)=\{x\}+1\), where \(\{x\}\) is the fractional part of \(x\). By definition, the fractional part of any number is always in the range [0, 1). Therefore, the function \(g(x)\) can take any value in the interval [1, 2). This means that the domain of \(f(g(x))\) will be [1, 2).
02
Finding the Range of \(f(g(x))\)
The range of \(f(g(x))\) can be found by substituting the domain of \(g(x)\) into function \(f(x)\). We have \(f(x)=x^{2}-x+2\). Plugging the interval [1, 2) into this expression will yield the range of \(f(g(x))\). Since \(f(x)\) is a quadratic function with a positive leading coefficient, it will have its minimum at the x-coordinate corresponding to the vertex of the parabola. The vertex is at \(x = \frac{-(-1)}{2*1} =\frac{1}{2}\). Since \(\frac{1}{2}\) is not in [1,2), we need to evaluate \(f(x)\) at the endpoints of the interval to find the minimum and maximum value. Thus we have \(f(1) = 1^{2} - 1 + 2 = 2\) and as \(x\) approaches 2, \(f(x)\) grows without bound, which means the range will be [2, \(\infty\)).
03
Calculating the Required Sum
Finally, we need to find the value of \(\frac{b}{a}+\frac{d}{c}\), where \([a, b]\) is the domain and \([c, d)\) is the range of \(f(g(x))\). From our previous steps we find that \(a=1\), \(b=2\), \(c=2\), and \(d=\infty\). Therefore, \(\frac{b}{a}=2/1=2\) and as for the second ratio, since the denominator is infinity and any finite number divided by infinity is zero, thus \(\frac{d}{c}= \frac{\infty}{2} = 0\). So \(\frac{b}{a}+\frac{d}{c} = 2 + 0 = 2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Functions
Quadratic functions are a type of polynomial function and are generally represented in the form \(f(x) = ax^2 + bx + c\). In these equations:
- \(a\), \(b\), and \(c\) are constants.
- The coefficient \(a\) must be non-zero (\(a eq 0\)); otherwise, the function would no longer be quadratic.
- The quadratic term \(ax^2\) gives the function its characteristic parabolic shape.
Fractional Part Function
The fractional part function, often represented as \(\{x\}\), extracts the decimal portion of a number. This function is defined as:
- \(\{x\} = x - \lfloor x \rfloor\) where \(\lfloor x \rfloor\) is the greatest integer less than or equal to \(x\).
- Whole part: \(\lfloor 1.75 \rfloor = 1\)
- Fractional part: \(\{1.75\} = 1.75 - 1 = 0.75\)
Function Composition
Function composition involves creating a new function by applying one function to the results of another, denoted as \((f \circ g)(x) = f(g(x))\). This is an important concept in calculus and helps solve complex equations by breaking them into manageable parts.
- The function \(g(x)\) is applied first to the input \(x\).
- The result of \(g(x)\) is then used as the input for the function \(f(x)\).