Chapter 1: Problem 121
A function \(f:[2, \infty) \rightarrow[5, \infty)\) is defined as \(f(x)=x^{2}-4 x+9 .\) Find its inverse.
Short Answer
Expert verified
The inverse of the function \(f(x)=x^{2}-4x+9\) is \(f^{-1}(x) = 2 + \sqrt{16 - 4(9 - x)}\)
Step by step solution
01
Express the function in terms of y
Start by replacing \(f(x)\) with \(y\). You get: \(y = x^{2} - 4x + 9\)
02
Swap x and y
Now, interchange x and y. This gives: \(x = y^{2} - 4y + 9\)
03
Solve for y
Rearrange above equation to find y in terms of x. This will give a quadratic equation of the form \(y^{2} - 4y + (9 - x) = 0\). This can be solved by using the quadratic formula \(y = [-b \pm \sqrt{(b^{2} - 4a(c))}] / 2a\), where in this case, a = 1, b = -4, and c = 9 - x. This would give us \(y = [4 \pm \sqrt{(-4)^{2} - 4(1)(9 - x)}] / 2\), which simplifies to \(y = 2 \pm \sqrt{16 - 4(9 - x)}\)
04
Check Intervals
By the definition, \(y\), the output of our function, should be greater or equal to 5 this means \(y = 2 - \sqrt{16 - 4(9 - x)}\) would give us a number less than 5. Therefore, the function \(f^{-1}(x) = 2 + \sqrt{16 - 4(9 - x)}\) is the correct inverse function for the given interval.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Functions
Quadratic functions are special types of functions that are characterized by a polynomial of degree two. They have the general form: \( f(x) = ax^2 + bx + c \). The graph of a quadratic function is a parabola, which can either open upwards or downwards depending on the sign of the coefficient \( a \).
Quadratic functions are fundamental in mathematics due to their simple yet rich structure.
Here are some standard characteristics:
Quadratic functions are fundamental in mathematics due to their simple yet rich structure.
Here are some standard characteristics:
- Vertex: The turning point of the parabola. This point can be found using the formula \( x = -\frac{b}{2a} \) for the axis of symmetry.
- Axis of Symmetry: A vertical line through the vertex \( x = -\frac{b}{2a} \) that divides the parabola into two symmetrical halves.
- Roots or Zeros: The points where the parabola intersects the x-axis. These solutions are found by setting \( f(x) = 0 \).
- Y-intercept: This is the point where the parabola intersects the y-axis, given by \( c \).
Function Domain
A function's domain is the set of all possible input values (x-values) that allow the function to operate successfully. For a quadratic function, the domain is generally all real numbers since you can square any real number and perform additional operations.
However, when finding the inverse of a function, the domain can become restricted.
For instance, the original function defined in the exercise has the domain \( [2, \infty) \). This means that only values of \( x \) starting from 2 up to infinity are considered when using the function, ensuring the function behaves appropriately, such as maintaining the inverse's validity and keeping the function one-to-one across the specified interval.
However, when finding the inverse of a function, the domain can become restricted.
For instance, the original function defined in the exercise has the domain \( [2, \infty) \). This means that only values of \( x \) starting from 2 up to infinity are considered when using the function, ensuring the function behaves appropriately, such as maintaining the inverse's validity and keeping the function one-to-one across the specified interval.
- Important Note: Always check the domain when working with the inverse function. The function must be one-to-one on the given domain.
Function Range
The range of a function consists of all possible output values (y-values) that the function can produce. In the context of a quadratic function, the range is often influenced considerably by the direction in which the parabola opens and its vertex.
For the function in our exercise, \( y = x^2 - 4x + 9 \), only values from 5 up to infinity are considered, as specified by \( [5, \infty) \). This is due to the fact that the parabola opens upwards, hitting a minimum point (vertex) at \( y = 5 \) when \( x \) is within the interval \( [2, \infty) \).
For the function in our exercise, \( y = x^2 - 4x + 9 \), only values from 5 up to infinity are considered, as specified by \( [5, \infty) \). This is due to the fact that the parabola opens upwards, hitting a minimum point (vertex) at \( y = 5 \) when \( x \) is within the interval \( [2, \infty) \).
- Vertex and Range Relation: For such quadratic functions where the parabola opens upwards, the vertex form indicates the lowest point in the range.
- Effect on Inverse: When finding the inverse, the range of the original function becomes the domain of the inverse, and vice versa.