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91Ó°ÊÓ

If the position function of a particle is \(x(t)=t^{2}+8 t, t>0,\) find the distance that the particle travels from \(t=0\) to \(t=4\) .

Short Answer

Expert verified
The particle would travel a distance of 48 units from \(t=0\) to \(t=4\).

Step by step solution

01

Identify the position function x(t)

The position function given to us is \(x(t) = t^{2}+8t\)
02

Evaluate the Position Function at \(t=4\)

Plug \(t=4\) into the position function: \(x(4)=(4)^{2}+8(4)=16+32=48\)
03

Evaluate the Position Function at \(t=0\)

Plug \(t=0\) into the position function: \(x(0) = (0)^{2} + 8(0)=0\)
04

Calculate the distance traveled

The distance traveled by the particle from \(t=0\) to \(t=4\) would be \(x(4) - x(0) = 48 - 0 = 48\) units

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