Chapter 1: Problem 3
Find \(\frac{d y}{d x}\) at \((2,1)\) if \(\frac{x+y}{x-y}=3\)
Short Answer
Expert verified
The derivative of \(y\) with respect to \(x\) at the point \((2,1)\) is \(1/2\).
Step by step solution
01
Simplify the given equation
First, start by simplifying the equation, \(\frac{x+y}{x-y}=3\). Multiply both sides of the equation by \(x-y\) to get rid of the fraction gives \(x+y=3x-3y\). Rearrange terms to isolate \(y\) gives \(4y=2x\), Which simplifies to \(y=\frac{x}{2}\).
02
Differentiate the equation with respect to \(x\)
Next, differentiate both sides of the equation \(y=\frac{x}{2}\) with respect to \(x\). The left side is \(dy/dx\) and the right side is \(1/2\). Therefore, \(\frac{dy}{dx}=\frac{1}{2}\), no matter what the value of \(x\) is.
03
Evaluate the derivative at the point (2,1)
Finally, evaluate the value of \(\frac{dy}{dx}\) at the point \((2,1)\). Since the derivative does not contain \(x\) or \(y\) terms, its value is the same at any point. So, \(\frac{dy}{dx}=\frac{1}{2}\) at \((2,1)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
The concept of a derivative is at the heart of differential calculus. The derivative of a function represents the rate of change of a variable with respect to another. In simpler terms, it shows how one quantity changes as another quantity changes. In mathematical terms, if you have a function \( y = f(x) \), then its derivative \( \frac{dy}{dx} \) tells us the slope of the tangent line to the function at any point. This slope is essentially the velocity of change.
- The derivative \( \frac{dy}{dx} \) can be thought of as the "speed" at which \( y \) changes as \( x \) changes.
- It provides a powerful tool for analyzing physical phenomena where we are interested in rates of change, such as speed, growth rates, and slopes of curves.
Implicit Differentiation
Sometimes, a function is not presented in an explicit form, like \( y = f(x) \). Instead, you might encounter an equation where \( y \) and \( x \) are mixed, such as \( \frac{x+y}{x-y}=3 \). Implicit differentiation helps us find the derivative of such equations. It is a technique used when it is difficult or impossible to solve for \( y \) as a clear function of \( x \).
- Differentiate each term of the equation with respect to \( x \), treating \( y \) as an implicit function of \( x \).
- Apply the chain rule, where \( \frac{dy}{dx} \) appears when differentiating terms involving \( y \).
Equation Simplification
Equation simplification is a valuable first step when dealing with complex equations, especially those that contain fractions or multiple terms involving \( x \) and \( y \). Simplification involves reducing an equation to its simplest form by eliminating fractions, combining like terms, or reorganizing the equation.
- The process begins by getting rid of any fractions or complex expressions. Multiply through by any denominator to clear fractions.
- Rearrange the terms to isolate variables and simplify the relationships among them. This helps in understanding the equation better and in applying further calculus techniques.