Chapter 1: Problem 13
Now find the derivative of each of the following functions. \(f(x)=\ln \left(10^{x}\right)\)
Short Answer
Expert verified
The derivative of the function \(f(x)=\ln \left(10^{x}\right)\) is \(f'(x) = \ln(10)\).
Step by step solution
01
Analyze the function
The given function \(f(x)=\ln \left(10^{x}\right)\) can be seen as a composition of two functions: \(u(x) = 10^x\) and \(v(x) = \ln(x)\). So the task is to apply the chain rule when differentiating.
02
Apply chain rule
To formulate the chain rule for \(f(x) = v(u(x))\), the derivative is given by \(f'(x) = v'(u(x)) * u'(x)\). So first differentiate \(v(x) = \ln(x)\) to get \(v'(x) = \frac{1}{x}\), then differentiate \(u(x) = 10^x\) to get \(u'(x) = 10^x \ln(10)\).
03
Substitute back into the chain rule
Substitute \(v'(u(x))\) and \(u'(x)\) back into the chain rule expression to get \(f'(x) = \frac{1}{10^x} * 10^x \ln(10)\).
04
Simplify the expression
The \(10^x\) terms cancel out, so \(f'(x) = \ln(10)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
chain rule
The chain rule is a fundamental tool in calculus used to find the derivative of composite functions. Picture a scenario where a task is completed using multiple smaller tasks; each smaller task needs to be done one after another. Similarly, when a function is composed of several inner functions, you need the chain rule to unravel its derivative.
When you differentiate a function like \( f(x) = \ln(10^x) \), you are actually dealing with a composition—one function nested inside another. To find its derivative, you start by recognizing the outer function (here it's \( \ln(x) \)) and the inner function (here it’s \( 10^x \)).
When you differentiate a function like \( f(x) = \ln(10^x) \), you are actually dealing with a composition—one function nested inside another. To find its derivative, you start by recognizing the outer function (here it's \( \ln(x) \)) and the inner function (here it’s \( 10^x \)).
- Differentiate the outer function \( v(x) = \ln(x) \) as if the inner function was "just x", giving \( v'(x) = \frac{1}{x} \).
- The next step is to differentiate the inner function \( u(x) = 10^x \), yielding \( u'(x) = 10^x \ln(10) \).
- Finally, multiply the derivative of the outer function, evaluated at the inner function \( u(x) \), by the derivative of the inner function. This gives us \( f'(x) = \frac{1}{10^x} \cdot 10^x \ln(10) \).
logarithmic differentiation
Logarithmic differentiation is a potent technique used chiefly when dealing with products, quotients or powers where traditional differentiation would be cumbersome. It employs the natural logarithm's unique property of turning differentiation into a more manageable process.
In the function \( f(x) = \ln(10^x) \), this technique proves particularly helpful. By the property of logarithms, you can rewrite it as \( x \ln(10) \). This simplification allows for an easier differentiation process. Instead of grappling with the power directly, you differentiate the simpler expression.
Here’s how it works in simple steps:
In the function \( f(x) = \ln(10^x) \), this technique proves particularly helpful. By the property of logarithms, you can rewrite it as \( x \ln(10) \). This simplification allows for an easier differentiation process. Instead of grappling with the power directly, you differentiate the simpler expression.
Here’s how it works in simple steps:
- Take the natural logarithm of the function.
- Differentiate the logarithm as you normally would.
- Solve the simpler equation for the original function's derivative.
composite functions
Composite functions are functions composed inside another function, much like a sandwich where one ingredient is layered over another. In mathematical terms, if you have two functions \( u(x) \) and \( v(x) \), a composition of these would be expressed as \( v(u(x)) \).
In our example, \( f(x) = \ln(10^x) \), the function \( 10^x \) is nested inside \( \ln(x) \), creating a composite function. The way you handle such functions is by picking them apart using differentiation techniques.
The concept is as follows:
In our example, \( f(x) = \ln(10^x) \), the function \( 10^x \) is nested inside \( \ln(x) \), creating a composite function. The way you handle such functions is by picking them apart using differentiation techniques.
The concept is as follows:
- First, identify the individual components of the composite function. In this case, recognize \( u(x) = 10^x \) and \( v(x) = \ln(x) \) as parts of \( f(x) \).
- Next, use techniques like the chain rule to differentiate the components systematically rather than trying to perform all calculations at once.
- Finally, piece them back together to determine your original function's derivative.