/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Calculating the Number of Period... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Calculating the Number of Periods At 9 percent interest, how long does it take to double your money? To quadruple it?

Short Answer

Expert verified
At a 9% interest rate, it takes approximately 8.043 years to double the investment and approximately 16.086 years to quadruple it.

Step by step solution

01

Write down the compound interest formula

We will use the compound interest formula to solve this problem: \[A = P(1 + \frac{r}{n})^{nt}\]
02

Doubling the investment scenario

First, we will determine the time required to double the investment. In this case, A would be equal to 2 * P. Substitute A = 2 * P into the formula: \(2P = P(1 + \frac{r}{n})^{nt}\)
03

Solve for t to double the investment

Divide both sides by P to simplify: \(2 = (1 + \frac{r}{n})^{nt}\) The problem states that the annual interest rate is 9% or 0.09. We can assume interest is compounded annually (n = 1). If that's the case, the formula becomes: \(2 = (1 + 0.09)^{t}\) Next, solve for t by taking the natural logarithm of both sides: \(\ln{2} = \ln{(1.09)^t}\) Then, use the power rule for logarithms: \(\ln{2} = t \ln{1.09}\) Finally, divide by the log(1.09) to solve for t: \(t = \frac{\ln{2}}{\ln{1.09}} \approx 8.043\) So, it takes approximately 8.043 years to double the investment at a 9% interest rate.
04

Quadrupling the investment scenario

Now, we will determine the time required to quadruple the investment. In this case, A would be equal to 4 * P. Substitute A = 4 * P into the formula: \(4P = P(1 + \frac{r}{n})^{nt}\)
05

Solve for t to quadruple the investment

Divide both sides by P to simplify: \(4 = (1 + \frac{r}{n})^{nt}\) Again, we use the annual interest rate of 9% or 0.09 and compound interest annually (n = 1): \(4 = (1 + 0.09)^{t}\) Next, solve for t by taking the natural logarithm of both sides: \(\ln{4} = \ln{(1.09)^t}\) Then, use the power rule for logarithms: \(\ln{4} = t \ln{1.09}\) Finally, divide by the log(1.09) to solve for t: \(t = \frac{\ln{4}}{\ln{1.09}} \approx 16.086\) So, it takes approximately 16.086 years to quadruple the investment at a 9% interest rate. In conclusion, at a 9% interest rate, it takes about 8.043 years to double the investment and about 16.086 years to quadruple it.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Compound Interest Formula
Understanding the compound interest formula is essential for anyone looking to grow their investments over time. Compound interest represents the interest on a loan or deposit calculated based on both the initial principal and the accumulated interest from previous periods. The generic formula for compound interest is:

\[\[\begin{align*}A &= P\biggl(1 + \frac{r}{n}\biggr)^{nt}\tag{1} \end{align*}\]\]
Where:
  • A is the future value of the investment/loan, including interest.
  • P is the principal amount (the initial amount of money).
  • r is the annual interest rate (in decimal form).
  • n is the number of times that interest is compounded per year.
  • t is the time the money is invested or borrowed for, in years.

This formula helps us understand how investments grow over time and is widely used in financial planning and savings strategies. The more frequently the interest is compounded, the higher the total amount of interest will be.
Calculating Number of Periods
When you're trying to figure out how long it will take for your money to reach a certain value with compound interest, you're calculating the number of periods. In finance, a 'period' often refers to the intervals at which interest is compounded. Using the formula for compound interest, you can isolate the variable t to find out how long you need to invest your money to double or quadruple it, as demonstrated in our exercise.

To find the number of periods, you need to transform the compound interest equation:
\[\[\begin{align*}A &= P\biggl(1 + \frac{r}{n}\biggr)^{nt}\tag{2}\end{align*}\]\]
and solve for t. This often requires using logarithms, which allows you to solve for time when dealing with exponential growth. The calculation of t is a foundational concept of financial mathematics, illustrating how time, interest rates, and compounding frequencies influence the growth of investments.
Logarithmic Calculations
Logarithmic calculations are useful in financial mathematics, particularly when dealing with compound interest. As compound interest is an exponential function, logarithms allow us to deal with questions involving time and rates more effectively. A logarithm answers the question: to what exponent must we raise a base number to obtain another number? The natural logarithm (symbolized as ln) is particularly useful when the base number is e (approximately 2.71828), which is a constant that naturally arises in the context of continuous growth.

To solve for t in the compound interest formula, you'd take the natural logarithm of both sides of the equation. This utilizes the power rule of logarithms, which says:
\[\[\begin{align*}ln(a^b) &= b \times ln(a)\tag{3}\end{align*}\]\]
Applying this rule simplifies the process of isolating the variable t in the equation, enabling you to calculate the number of periods needed for an investment to reach a certain value.
Financial Mathematics
Financial mathematics is a branch of applied mathematics that analyzes and models the financial markets, focusing on the mathematical techniques used in financial decision-making. It involves tools from quantitative analysis, statistics, stochastic calculus, and economic theory. In the context of our discussion, financial mathematics includes concepts such as the time value of money, which is the principle that money available now is worth more than the same amount in the future due to its potential earning capacity.

This principle is manifest in the compound interest formula, which calculates what an investment will be worth in the future if it earns a certain rate of interest that is compounded over time. Whether it's computing how long it takes for an investment to double or determining the present value of a stream of future cash flows, financial mathematics is essential for making sound economic decisions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Perpetuities An investor purchasing a British consol is entitled to receive annual payments from the British government forever. What is the price of a consol that pays \(\$ 120\) annually if the next payment occurs one year from today? The market interest rate is 5.7 percent.

Ordinary Annuities and Annuities Due As discussed in the text, an annuity due is identical to an ordinary annuity except that the periodic payments occur at the beginning of each period and not at the end of the period. Show that the relationship between the value of an ordinary annuity and the value of an otherwise equivalent annuity due is: Annuity due value \(=\) Ordinary annuity value \(\times(1+r)\) Show this for both present and future values.

Annuity Present Values What is the value today of a 15 -year annuity that pays \(\$ 750\) a year? The annuity's first payment occurs six years from today. The annual interest rate is 12 percent for years 1 through 5 , and 15 percent thereafter.

Present Value and Interest Rates What is the relationship between the value of an annuity and the level of interest rates? Suppose you just bought a 12-year annuity of \(\$ 7,500\) per year at the current interest rate of 10 percent per year. What happens to the value of your investment if interest rates suddenly drop to 5 percent? What if interest rates suddenly rise to 15 percent?

Calculating Rates of Return Although appealing to more refined tastes, art as a collectible has not always performed so profitably. During 2003, Sotheby's sold the Edgar Degas bronze sculpture Petite Danseuse de Quartorze Ans at auction for a price of \(\$ 10,311,500\). Unfortunately for the previous owner, he had purchased it in 1999 at a price of \(\$ 12,377,500\). What was his annual rate of return on this sculpture?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.