Chapter 9: Problem 34
Solve the given equation in the complex number system. $$x^{4}=i$$
Short Answer
Expert verified
Question: Find the roots of the equation \(x^4 = i\) in the complex number system.
Answer: The roots of the equation \(x^4 = i\) are \(x_0 = e^{i\frac{\pi}{8}}\), \(x_1 = e^{i\frac{5\pi}{8}}\), \(x_2 = e^{i\frac{9\pi}{8}}\), and \(x_3 = e^{i\frac{13\pi}{8}}\).
Step by step solution
01
Express i in polar form
First, let's express \(i\) in polar form. Recall that a complex number \(z = a + bi\) can be represented in polar form as \(z = re^{i\theta}\), where \(r\) is the modulus of \(z\) and \(\theta\) is its argument.
The complex number \(i\) can be written as \(0 + 1i\), so its real part \(a = 0\) and its imaginary part \(b = 1\). The modulus of \(i\) is \(r = \sqrt{a^2 + b^2} = \sqrt{0^2 + 1^2} = 1\). The argument of \(i\) is \(\theta = \arctan{\frac{b}{a}}\). However, since \(a = 0\), the arctangent is undefined. Instead, we recall that \(i\) lies on the positive imaginary axis, so its argument is \(\theta = \frac{\pi}{2}\). Therefore, the polar form of \(i\) is:
$$i = 1e^{i\frac{\pi}{2}}$$
02
Use De Moivre's theorem to find the roots
Now that we have \(i\) in polar form, we can solve the equation \(x^4 = 1e^{i\frac{\pi}{2}}\) using De Moivre's theorem. Recall that De Moivre's theorem states that for any complex number \(z = re^{i\theta}\) and any positive integer \(n\), the \(n\) roots of the equation \(w^n = z\) are given by:
$$w_k = \sqrt[n]{r}\left(\cos\left(\frac{\theta + 2\pi k}{n}\right) + i\sin\left(\frac{\theta + 2\pi k}{n}\right)\right), \quad k = 0, 1, 2, \dots, n-1$$
We want to find the roots \(x\) of the equation \(x^4 = 1e^{i\frac{\pi}{2}}\). In our case, we have \(r = 1\), \(n = 4\), and \(\theta = \frac{\pi}{2}\). Plugging these values into the formula above, we get:
$$x_k = \sqrt[4]{1}\left(\cos\left(\frac{\frac{\pi}{2} + 2\pi k}{4}\right) + i\sin\left(\frac{\frac{\pi}{2} + 2\pi k}{4}\right)\right), \quad k = 0, 1, 2, 3 $$
03
Compute the roots
Now, we will compute each root \(x_k\) for \(k = 0, 1, 2, 3\).
$$x_0 = \sqrt[4]{1}\left(\cos\left(\frac{\frac{\pi}{2}}{4}\right) + i\sin\left(\frac{\frac{\pi}{2}}{4}\right)\right) = e^{i\frac{\pi}{8}}$$
$$x_1 = \sqrt[4]{1}\left(\cos\left(\frac{\frac{5\pi}{2}}{4}\right) + i\sin\left(\frac{\frac{5\pi}{2}}{4}\right)\right) = e^{i\frac{5\pi}{8}}$$
$$x_2 = \sqrt[4]{1}\left(\cos\left(\frac{\frac{9\pi}{2}}{4}\right) + i\sin\left(\frac{\frac{9\pi}{2}}{4}\right)\right) = e^{i \frac{9\pi}{8}}$$
$$x_3 = \sqrt[4]{1}\left(\cos\left(\frac{\frac{13\pi}{2}}{4}\right) + i\sin\left(\frac{\frac{13\pi}{2}}{4}\right)\right) = e^{i\frac{13\pi}{8}}$$
These are the four roots of the equation \(x^4 = i\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
De Moivre's Theorem
De Moivre's Theorem is a powerful tool in the world of complex numbers. It provides a simple way to compute powers and roots of complex numbers when they are in polar form. According to the theorem, for a complex number in polar form, expressed as \(z = r e^{i \theta}\), the \(n\)-th power of \(z\) is given by raising the modulus \(r\) to the power \(n\), and multiplying the argument \(\theta\) by \(n\). Mathematically, it is expressed as:
- \(z^n = r^n e^{i n\theta}\)
Polar Form
Polar form is a different way to express complex numbers. Instead of using the standard form \(a + bi\) with real and imaginary parts, polar form uses a radius and angle. Any complex number \(z = a + bi\) can be shown in polar form as:
- \(z = r(\cos \theta + i\sin \theta)\) or equivalently \(z = re^{i\theta}\)
Roots of Unity
The term *Roots of Unity* refers to complex solutions of an equation \(x^n = 1\). These are special because they lie on the complex unit circle, evenly spaced, and play a crucial role in various areas of mathematics.
- For example, for \(x^4 = 1\), the roots are \(1, -1, i, \text{and} -i\).
- These solutions divide the complex circle into equal sectors, each having an angle of \(\frac{2\pi}{n}\) radians.
Complex Equation Solving
Complex equation solving involves finding values that satisfy an equation where the unknown variable is a complex number. The methodology often leverages polar form and De Moivre's Theorem. In cases like \(x^4 = i\), the objective is to express \(i\) in a friendly form - namely, polar form - allowing us to comfortably apply De Moivre's Theorem. The solution’s process typically goes as follows:
- Convert the complex constant to polar form to grasp its modulus and argument.
- Use De Moivre's Theorem to find all possible roots. These roots will be symmetrically placed around the unit circle.