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In Exercises \(30-36,\) perform the indicated operations, then simplify your answers by using appropriate definitions and identities. $$(1-\sec t)^{2}$$

Short Answer

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Question: Expand and simplify the expression \((1-\sec{t})^2\). Answer: The simplified expression is \(\frac{1-2\cos{t}+\sin^2{t}}{\cos^2{t}}\).

Step by step solution

01

Rewrite the expression using secant identity

Firstly, we need to rewrite the expression, \((1-\sec{t})^2\), using the secant identity. So, replace \(\sec{t}\) with \(\frac{1}{\cos{t}}\). The expression becomes: $$(1-\frac{1}{\cos{t}})^2$$
02

Calculate the square of the expression

Now, we will expand the expression and square it: $$\left(1-\frac{1}{\cos{t}}\right)^2=\left(\frac{\cos{t}-1}{\cos{t}}\right)^2=\frac{(\cos{t}-1)^2}{\cos^2{t}}$$
03

Expand the numerator

Expand the numerator by multiplying \((\cos{t}-1)\) by itself: $$\frac{(\cos{t}-1)^2}{\cos^2{t}}=\frac{\cos^2{t}-2\cos{t}+1}{\cos^2{t}}$$
04

Simplify the expression using trigonometric identity

Use the Pythagorean identity, \(\sin^2{t}+\cos^2{t}=1\), to simplify the expression further. Since we have \(\cos^2{t}\) in the numerator, we can rewrite this identity as \(\sin^2{t}=1-\cos^2{t}\). Now, substitute \(\sin^2{t}=1-\cos^2{t}\) in the expression: $$\frac{\cos^2{-}2\cos{t}+1}{\cos^2{t}}=\frac{(1-\sin^2{t}){-}2\cos{t}+1}{\cos^2{t}}=\frac{1-2\cos{t}+\sin^2{t}}{\cos^2{t}}$$ So the final simplified expression is: $$\frac{1-2\cos{t}+\sin^2{t}}{\cos^2{t}}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Secant Identity
Understanding the secant identity is crucial for simplifying trigonometric expressions. The secant of an angle, represented as \( \text{sec}(t) \), is defined as the reciprocal of the cosine of that angle. In essence, \( \text{sec}(t) = \frac{1}{\text{cos}(t)} \). This definition is pivotal in transforming complex trigonometric expressions into more manageable forms.

When faced with an expression involving the secant function, such as \( (1-\text{sec}(t))^2 \), the first step is to substitute \( \text{sec}(t) \) with \( \frac{1}{\text{cos}(t)} \). Rewriting functions in terms of sine and cosine can often lead to further simplifications, as these are the fundamental trigonometric functions upon which most identities are built.
Trigonometric Simplification
The process of trigonometric simplification involves rewriting trigonometric expressions in a simpler or more compact form. This often involves applying various trigonometric identities and algebraic manipulations. To simplify an expression like \( \frac{(\text{cos}(t) - 1)^2}{\text{cos}^2(t)} \), we expand the numerator and look for opportunities to simplify the expression.

For instance, after expansion, you might have terms that are common in both the numerator and the denominator that can be canceled out. Another approach is to use known identities to transform parts of the expression into equivalent forms that are easier to work with or combine. Understanding these strategies is essential for efficiency and accuracy in solving trigonometry problems.
Pythagorean Identity
The Pythagorean identity is a cornerstone of trigonometry, expressing a fundamental relationship between the sine and cosine of an angle. The identity states that \( \text{sin}^2(t) + \text{cos}^2(t) = 1 \), which can be rearranged depending on the needs of the problem at hand. For example, we can isolate \( \text{sin}^2(t) \) to get \( \text{sin}^2(t) = 1 - \text{cos}^2(t) \).

This powerful identity allows us to convert sine-squared terms to cosine-squared terms or vice versa, significantly simplifying expressions where both sine and cosine functions appear. Referring back to the original exercise, this identity is applied to replace \( \text{cos}^2(t) \) with \( 1 - \text{sin}^2(t) \) in the expression, helping to achieve the final simplified result.

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Most popular questions from this chapter

A wheel is rotating around its axle. Find the angle (in radians) through which the wheel tums in the given time when it rotates at the given mumber of revolutions per minute ( \(r p m\) ). Assume that \(t>0\) and \(k>0\). 4.25 minutes, \(5 \mathrm{rpm}\)

Graph the function. Does the function appear to be periodic? If so, what is the period? $$h(t)=|\tan t|$$

Show that the given function is periodic with period less than \(2 \pi\). [Hint: Find a positive number \(k\) with \(k<2 \pi \text { such that } f(t+k)=f(t) \text { for every t in the domain of } f .]\) $$f(t)=\sin (\pi t)$$

Explore various ways in which a calculator can produce inaccurate graphs of trigonometric functions. These exercises also provide examples of two functions, with different graphs, whose graphs appear identical in certain viewing windows. Choose a viewing window with \(-3 \leq y \leq 3\) and \(0 \leq x \leq k\) where \(k\) is chosen as follows. $$\begin{array}{|l|c|} \hline \text { Width of Screen } & k \\ \hline \begin{array}{l} \text { 95 pixels } \\ (\mathrm{TI}-83 / 84+) \end{array} & 188 \pi \\ \hline \begin{array}{l} \text { 127 pixels } \\ \text { (TI-86, Casio) } \end{array} & 252 \pi \\ \hline \begin{array}{l} \text { 131 pixels } \\ \text { (HP-39gs) } \end{array} & 260 \pi \\ \hline \begin{array}{l} \text { 159 pixels } \\ \text { (TI-89) } \end{array} & 316 \pi \\ \hline \end{array}$$ (a) Graph \(y=\cos x\) and the constant function \(y=1\) on the same screen. Do the graphs look identical? Are the functions the same? (b) Use the trace feature to move the cursor along the graph of \(y=\cos x,\) starting at \(x=0 .\) For what values of \(x\) did the calculator plot points? [Hint: \(2 \pi \approx 6.28 .]\) Use this information to explain why the two graphs look identical.

Graph the function. Does the function appear to be periodic? If so, what is the period? $$g(t)=|\sin t|$$

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