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Solve the equation. First express your answer in terms of natural logarithms (for instance, \(x=(2+\ln 5) /(\ln 3)) .\) Then use a calculator to find an approximation for the answer. $$3^{x}=5$$

Short Answer

Expert verified
Answer: The approximate value of x is 1.465.

Step by step solution

01

Take the natural logarithm of both sides

To be able to solve for x, we can take the natural logarithm of both sides of the equation. $$\ln{(3^x)} = \ln{5}$$
02

Apply the logarithmic identity

Use the logarithmic identity \(\ln{a^b} = b\ln{a}\) to rewrite the equation and isolate x. $$x\ln{3} = \ln{5}$$
03

Solve for x

Divide both sides by \(\ln{3}\) to solve for x. $$x = \frac{\ln{5}}{\ln{3}}$$ Now, we have found the exact value of x in terms of natural logarithms.
04

Approximate the answer using a calculator

Use a calculator to approximate the value of x. $$x \approx \frac{\ln{5}}{\ln{3}} \approx 1.465$$ The approximate value of x is 1.465.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithms
Natural logarithms are a fundamental concept when working with exponential equations. The natural logarithm is the inverse function of the exponential function with a base of the constant 'e', approximately equal to 2.71828. It is commonly denoted as 'ln'. For any positive number 'a', the natural logarithm of 'a', written as \(\ln(a)\), is the power to which 'e' must be raised to obtain the number 'a'.

Interestingly, the natural logarithm has a unique property: \(\ln(e) = 1\), because 'e' raised to the power of 1 is 'e'. This logarithm is 'natural' because it arises naturally in mathematics and science, describing growth rates, decay, and many phenomena in calculus and beyond.

When we solve exponential equations, as in the example provided, taking the natural logarithm of both sides allows us to untangle the exponent and solve for the variable. This process is essential because it translates multiplicative relationships into additive ones, which are often much easier to solve.
Logarithmic Identity
Logarithmic identities are like the secret keys for unlocking the solutions to equations involving exponents and logarithms. One of the most used logarithmic identities is the power rule: \(\ln(a^b) = b\ln(a)\). This identity allows you to bring down the exponent in a logarithmic expression, essentially reducing the exponent's influence and making the variable more accessible.

The power rule is pivotal when dealing with exponential equations because it transforms a seemingly complex exponential form into a more straightforward linear form. For instance, applying the identity to \(\ln(3^x)\), as shown in the exercise, we simplify the equation to \(x\ln(3)\). This step is crucial because it isolates 'x' to one side, streamlining the path to finding the solution.

Memorizing and understanding logarithmic identities is a valuable skill in mathematics because they frequently form the backbone of the steps that are taken in solving logarithmic and exponential equations.
Exponential Functions
Exponential functions represent one of the most exciting and ubiquitous types of functions in mathematics. Defined by the general formula \(y = a^x\), where 'a' is a positive constant and 'x' is the exponent, these functions model growth or decay processes, from populations to investments.

In an exponential function, the value of 'y' changes at a rate proportional to its current value, which leads to the characteristic rapidly increasing or decreasing 'J-shaped' curve when graphed. In the context of our exercise, the function \(3^x\) is an exponential function with a base of 3. It represents continuous multiplication by 3 as 'x' increases.

Understanding how exponential functions work is integral to solving equations where variables are exponents. The beauty of exponential functions lies not only in their applications but also in their properties, such as the fact that they're their own derivative and integral, crucial in calculus. Appreciation and comprehension of exponential functions provide a deeper insight into a broad range of problems in both pure and applied mathematics.

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