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Find the average rate of change of the function. \(f(x)=x \log |x|,\) as \(x\) goes from 1 to 4

Short Answer

Expert verified
Answer: The average rate of change of the function is \(\frac{4\cdot\log4}{3}\).

Step by step solution

01

Find the value of the function at x = 1 and x = 4

First, we need to find the value of the function at the given x values. To do this, plug x = 1 and x = 4 into the function, \(f(x)=x \log |x|\). For x = 1: $$f(1) = 1\log|1| = 1\cdot0 = 0$$ For x = 4: $$f(4) = 4\log|4| = 4\cdot\log4$$
02

Calculate the difference in the dependent variable

Now we need to calculate the difference between f(4) and f(1). $$f(4)-f(1)= 4\cdot\log4 - 0 = 4\cdot\log4$$
03

Determine the difference in the independent variable

In this case, the difference between the two x values is: $$4-1=3$$
04

Calculate the average rate of change of the function

Now, divide the difference in the dependent variable by the difference in the independent variable to find the average rate of change: $$\frac{f(4)-f(1)}{4-1}=\frac{4\cdot\log4}{3}$$ So, the average rate of change of the function \(f(x)=x \log |x|\) as x goes from 1 to 4 is \(\frac{4\cdot\log4}{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Analysis
Analyzing functions is a fundamental aspect in understanding their behaviors and characteristics. In the example given with the function \(f(x) = x \log |x|\), function analysis involves evaluating the function at specific points and understanding how the function changes within an interval. By taking the values of \(f(x)\) at \(x = 1\) and \(x = 4\), we are essentially extracting snapshots of the function's output at these points.

Function analysis often includes finding the function's domain and range, intercepts, intervals of increase or decrease, and rates of change. The average rate of change is especially important as it gives us a measure of how quickly or slowly the function values are changing between two points. A zero average rate of change indicates that the function has the same output at both points, implying a horizontal line segment between the points on the graph. If the rate is positive or negative, it points to an increasing or decreasing trend, respectively, over the interval.
Logarithmic Functions
Logarithmic functions are the inverse of exponential functions. They have the form \(y = \log_b(x)\), where \(b\) is the base and must be a positive real number different from 1. The logarithm of a number is the exponent by which the base must be raised to produce that number. For example, if we have \(2^3 = 8\), then \(\log_2(8) = 3\).

In calculus and other areas of mathematics, the natural logarithm, which has the base \(e\) (Euler's number, approximately 2.718), is often used. Logarithmic functions are used to model various phenomena in science and engineering, such as the decay of radioactive substances and the intensity of sound. In the function \(f(x)=x \log |x|\), the logarithmic component is critical to understanding how the function behaves as it helps to describe growth and decay processes.
Calculus
Calculus is the branch of mathematics that studies changes and motion, primarily through the derivative and the integral. It allows us to understand how functions change over time or across space. The foundational concept in calculus is the limit, which leads to the definition of the derivative and the integral. Derivatives measure the instantaneous rate of change, while integrals measure the accumulation of quantities.

In this example, the average rate of change of \(f(x) = x \log |x|\) from \(x = 1\) to \(x = 4\) is a concept from calculus known as the Mean Value Theorem for Derivatives. This theorem essentially states that for any continuous and differentiable function over an interval, there exists at least one point in the interval where the instantaneous rate of change (the derivative) is the same as the average rate of change over the interval. Calculus provides the tools to find precise changes even when the function itself is not linear, making it a powerful tool for analysis in science, engineering, and economics.

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Most popular questions from this chapter

Determine whether an exponential, power, or logarithmic model (or none or several of these) is appropriate for the data by determining which (if any) of the following sets of points are approximately linear: $$\\{(x, \ln y)\\}, \quad\\{(\ln x, \ln y)\\}, \quad\\{(\ln x, y)\\}$$ where the given data set consists of the points \(\\{(x, y)\\}\) $$\begin{array}{|l|c|c|c|c|c|c|} \hline x & 1 & 3 & 5 & 7 & 9 & 11 \\ \hline y & 2 & 25 & 81 & 175 & 310 & 497 \\ \hline \end{array}$$

Deal with functions of the form \(f(x)=P e^{k x}\) where \(k\) is the continuous exponential growth rate (see Example 6 ). One hour after an experiment begins, the number of bacteria in a culture is \(100 .\) An hour later, there are 500 . (a) Find the number of bacteria at the beginning of the experiment and the number three hours later. (b) How long does it take the number of bacteria at any given time to double?

Simplify the expression without using a calculator. $$\sqrt{54 m^{-6} n^{3}}$$

This exercise provides a justification for the claim that the function \(M(x)=c(.5)^{x / h}\) gives the mass after \(x\) years of a radioactive element with half-life \(h\) years. Suppose we have \(c\) grams of an element that has a half-life of 50 years. Then after 50 years, we would have \(c\left(\frac{1}{2}\right)\) grams. After another 50 years, we would have half of that, namely, \(c\left(\frac{1}{2}\right)\left(\frac{1}{2}\right)=c\left(\frac{1}{2}\right)^{2}\) (a) How much remains after a third 50-year period? After a fourth 50 -year period? (b) How much remains after \(t 50\) -year periods? (c) If \(x\) is the number of years, then \(x / 50\) is the number of 50-year periods. By replacing the number of periods \(t\) in part (b) by \(x / 50,\) you obtain the amount remaining after \(x\) years. This gives the function \(M(x)\) when \(h=50\) The same argument works in the general case (just replace 50 by \(h\) ). Find \(M(x)\).

Find the difference quotient of the given function. Then rationalize its numerator and simplify. $$g(x)=\sqrt{x^{2}-x}$$

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