/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 List the transformations that wi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

List the transformations that will change the graph of \(g(x)=\ln x\) into the graph of the given function. $$h(x)=\ln (x-4)$$

Short Answer

Expert verified
Answer: A horizontal shift to the right by 4 units is needed.

Step by step solution

01

Identify the original function and the transformed function

We have the original function g(x) as: $$g(x) = \ln x$$ And the transformed function h(x) as: $$h(x) = \ln (x-4)$$
02

Compare the functions and identify the transformation

We can see that the only difference between the two functions is the argument inside the natural logarithm. In the transformed function, instead of having \(x\), we have \((x-4)\): $$h(x) = \ln (x-4)$$ This indicates a horizontal shift.
03

Determine the direction and magnitude of the horizontal shift

The horizontal shift can be determined by looking at the value inside the parentheses. In this case, we have \((x-4)\) in the transformed function, which means the graph will shift to the right by 4 units.
04

List the transformations

To change the graph of \(g(x) = \ln x\) into the graph of \(h(x) = \ln (x-4)\), the following transformation is needed: 1. A horizontal shift to the right by 4 units.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Shift
Understanding the concept of a horizontal shift is crucial when studying transformations of functions. A horizontal shift moves every point on a graph to the left or right by a certain amount. This transformation doesn't change the shape of the graph; it simply translates it along the x-axis.

Let's decode the horizontal shift in the context of the exercise. Given the original function, \( g(x) = \ln x \), and the transformed function, \( h(x) = \ln (x-4) \), we observe a modification in the argument of the logarithm from \( x \) to \( (x-4) \). This minus four inside the logarithm indicates that every point on the graph of \( g(x) \) should be shifted horizontally to the right by 4 units to obtain the graph of \( h(x) \).

In practical terms, if you were to draw the original function on a graph paper, shifting it horizontally would involve taking a 'ruler' and shifting each point on the curve to the right side by the distance of four 'units' on the graph paper, where a unit corresponds to the distance between two consecutive lines. This type of manipulation is key in mathematics, as it allows us to visualize how functions can be transformed and how their graphs relate to each other.
Transformations of Functions
The term 'transformations of functions' refers to the various operations that can be applied to a function's equation to alter its graph. These changes include shifts, stretches, compressions, and reflections. Transformations can be applied to any part of the function's formula, resulting in a corresponding change in its graph.

Transformations can be horizontal or vertical shifts, moving the graph along the axes; stretches or compressions, which elongate or shorten the graph in the vertical or horizontal direction; or reflections, flipping the graph over an axis. Understanding how these transformations affect the shape and position of a graph is invaluable in graphing new functions based on familiar ones and plays a central role in calculus and algebra.

When applying a transformation, like the horizontal shift displayed in the exercise, it is important to analyze the algebraic changes in the function's formula. For our example with logarithmic functions, the horizontal shift is conveyed through an alteration inside the argument of the natural logarithm. Grasping the nature of these changes enhances a student's ability to quickly sketch graphs and predict the effects of varying different parameters in the functions' equations.
Natural Logarithm Graph
The natural logarithm graph represents the function \( f(x) = \ln x \), which is the inverse of the natural exponential function \( e^x \). It's important to note that the natural logarithm is only defined for positive real numbers, and its graph is characterized by a distinctive shape that approaches the y-axis (asymptote) but never touches it, while steadily increasing without bound as x becomes larger.

The graph of the natural logarithm passes through the point (1,0) since \( \ln(1) \) equals zero. It also exhibits certain properties, such as being continuously increasing (monotonically) and having a domain of all positive real numbers (\( x > 0 \)).

Understanding the graph of the natural logarithm function helps us better grasp various transformations, such as those presented in the exercise. When the argument of the natural logarithm is altered, as seen with \( h(x) = \ln (x-4) \), it shifts the graph horizontally without changing its overall shape. Hence, recognizing the base graph of the natural logarithm is an essential step before analyzing how transformations like shifts will affect the function's visual representation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Do Exercise 77 when the equation relating output to resources is \(Q=L^{1 / 4} C^{1 / 2}\)

Rationalize the denominator and simplify your answer. $$\begin{aligned} &1\\\ &\frac{2}{\sqrt{x}+2} \end{aligned}$$

Look back at Section \(4.4,\) where the basic properties of graphs of polynomial functions were discussed. Then review the basic properties of the graph of \(f(x)=a^{x}\) discussed in this section. Using these various properties, give an argument to show that for any fixed positive number \(a(\neq 1),\) it is not possible to find a polynomial function \(g(x)=c_{n} x^{n}+\dots+c_{1} x+c_{0}\) such that \(a^{x}=g(x)\) for \(a l l\) numbers \(x .\) In other words, no exponential function is a polynomial function. However, see Exercise \(81 .\)

Approximating Logarithmic Functions by Polynomials. For each positive integer \(n,\) let \(f_{n}\) be the polynomial function whose rule is $$ f_{n}(x)=x-\frac{x^{2}}{2}+\frac{x^{3}}{3}-\frac{x^{4}}{4}+\frac{x^{5}}{5}-\cdots \pm \frac{x^{n}}{n} $$ where the sign of the last term is \(+\) if \(n\) is odd and \(-\) if \(n\) is even. In the viewing window with \(-1 \leq x \leq 1\) and \(-4 \leq y \leq 1,\) graph \(g(x)=\ln (1+x)\) and \(f_{4}(x)\) on the same screen. For what values of \(x\) does \(f_{4}\) appear to be a good approximation of \(g ?\)

Deal with functions of the form \(f(x)=P e^{k x}\) where \(k\) is the continuous exponential growth rate (see Example 6 ). Between 1996 and \(2004,\) the number of United States subscribers to cell-phone plans has grown nearly exponentially. In 1996 there were 44,043,000 subscribers and in 2004 there were \(182,140,000^{\dagger}\) (a) What is the continuous growth rate of the number of cell-phone subscribers? (b) In what year were there 60,000,000 cell-phone subscribers? (c) Assuming that this rate continuous, in what year will there be 350,000,000 subscribers? (d) In 2007 the United States population was approximately 300 million. Is your answer to part (c) realistic? If not, what could have gone wrong?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.