/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Find the average rate of change ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the average rate of change of the function. \(h(x)=2^{x}\) as \(x\) goes from 1 to 1.001

Short Answer

Expert verified
Answer: The approximate average rate of change is 0.693.

Step by step solution

01

Identify the given values

We are given the function \(h(x) = 2^x\), and we need to find the average rate of change as x goes from 1 to 1.001. So, \(x_1 = 1\) and \(x_2 = 1.001\).
02

Calculate the function values at \(x_1\) and \(x_2\)

To find the function values at \(x_1\) and \(x_2\), we simply plug in the values into the function: \(h(x_1) = h(1) = 2^1 = 2\) \(h(x_2) = h(1.001) = 2^{1.001}\)
03

Calculate the average rate of change

Now, we will use the formula for the average rate of change: Average rate of change \(= \frac{h(x_2) - h(x_1)}{x_2 - x_1} = \frac{2^{1.001} - 2}{1.001 - 1}\) Average rate of change \(= \frac{2^{1.001} - 2}{0.001}\) Now, you can use a calculator to find the approximate value of this expression. The average rate of change of the function \(h(x) = 2^{x}\) as \(x\) goes from 1 to 1.001 is approximately 0.693.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. In real-world applications, exponential functions model situations where growth or decay occurs at a constant percentage rate, such as population growth, radioactive decay, or interest calculations.
An exponential function has the form \( f(x) = a^x \), where \(a\) is a positive constant referred to as the base. The function \( h(x) = 2^x \), presented in our exercise, is a simple exponential function where the base is 2. Here, the exponent \( x \) determines the behavior of the function. As \( x \) increases, \( h(x) \) grows rapidly, demonstrating the characteristic growth nature of exponential functions.
Understanding exponential functions is essential because they appear frequently in various fields, including biology, finance, and physics. By mastering this concept, you can better predict and describe how quantities change over time under such conditions.
Calculus
Calculus is a branch of mathematics focusing on rates of change and the accumulation of quantities. It is divided into two main areas: differential calculus and integral calculus. In this case, we are primarily dealing with differential calculus, as we're interested in the rate of change of the function \( h(x) = 2^x \).
The average rate of change, as calculated in the exercise, provides an approximate measure of how the function's output changes over an interval. Calculating the exact rate of change at a point (i.e., the derivative) is a core concept in calculus. This is particularly useful for non-linear functions, like exponential ones, where the changes are not constant.
Understanding these rates is crucial, especially in physics or engineering fields, where you need to know how a parameter changes with respect to another. Calculus tools allow us to predict and analyze behavior dynamically.
Function Analysis
Analyzing a function requires understanding its behavior over a set of inputs. For the function \( h(x) = 2^x \), function analysis involves examining its properties, such as its domain, range, and how it changes.
  • Domain: The domain of \( h(x) = 2^x \) comprises all real numbers since any real number can be used as an exponent for a positive base.
  • Range: The range includes all positive real numbers, as \( 2^x \) is always positive for any real \( x \).
  • Growth: The function grows exponentially fast due to the nature of its exponent. This means any small change in \( x \) can lead to significant changes in \( h(x) \).
Analyzing a function like this helps us predict and understand how a system it models might behave. This is particularly useful in solving real-world problems. Function analysis makes use of calculus tools to gather insights into these characteristics, such as finding when and where the function might reach certain values or how rapidly changes occur.

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Most popular questions from this chapter

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