This exercise provides a justification for the claim that the function
\(M(x)=c(.5)^{x / h}\) gives the mass after \(x\) years of a radioactive element
with half-life \(h\) years. Suppose we have \(c\) grams of an element that has a
half-life of 50 years. Then after 50 years, we would have
\(c\left(\frac{1}{2}\right)\) grams. After another 50 years, we would have half
of that, namely,
\(c\left(\frac{1}{2}\right)\left(\frac{1}{2}\right)=c\left(\frac{1}{2}\right)^{2}\)
(a) How much remains after a third 50-year period? After a fourth 50 -year
period?
(b) How much remains after \(t 50\) -year periods?
(c) If \(x\) is the number of years, then \(x / 50\) is the number of 50-year
periods. By replacing the number of periods \(t\) in part (b) by \(x / 50,\) you
obtain the amount remaining after \(x\) years. This gives the function \(M(x)\)
when \(h=50\) The same argument works in the general case (just replace 50 by
\(h\) ). Find \(M(x)\).