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Find \(g\) o \(f\) and find the difference quotient of the function \(g \circ f\) $$f(x)=x+1 ; g(x)=\frac{2}{x-1}$$

Short Answer

Expert verified
Answer: The difference quotient of the composition of functions \(g \circ f\) is \(\frac{-2}{x(x+h)}\).

Step by step solution

01

Find \(g \circ f\)

To find the composition \(g \circ f\), we can substitute the function \(f(x)\) into the input of function \(g(x)\). So we have: $$(g \circ f)(x) = g(f(x)) = g(x+1) = \frac{2}{(x+1) - 1}$$ Simplifying the expression, we get: $$(g \circ f)(x) = \frac{2}{x}$$ Now that we have found the composition of the functions, let's move on to finding the difference quotient for \((g \circ f)(x)\).
02

Find the difference quotient

To find the difference quotient for \((g \circ f)(x)\), we will use the formula: $$\frac{(g \circ f)(x+h) - (g \circ f)(x)}{h}$$ Substituting the composition function we derived in step 1: $$=\frac{\frac{2}{x+h} - \frac{2}{x}}{h}$$
03

Simplify the expression

Now, let's simplify the expression: $$=\frac{\frac{2(x) - 2(x+h)}{x(x+h)}}{h}$$ Distribute the negative sign: $$=\frac{\frac{2x - 2x - 2h}{x(x+h)}}{h}$$ Simplify the numerator: $$=\frac{\frac{-2h}{x(x+h)}}{h}$$ Now, divide by \(h\): $$=\frac{-2h}{x(x+h)} \cdot \frac{1}{h}$$ The \(h\) terms will cancel out, leaving: $$=\frac{-2}{x(x+h)}$$
04

Final answer

The difference quotient of the function \(g \circ f\) is: $$\frac{-2}{x(x+h)}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference Quotient
The difference quotient is a fundamental tool in calculus, used primarily to find the derivative of a function. When dealing with the difference quotient, we examine how a function changes as the input changes by observing the average rate of change over an interval.

For any function \(f(x)\), the difference quotient formula is given by:
  • \[ \frac{f(x+h) - f(x)}{h} \]
Here, \(h\) represents a small increment added to \(x\). By finding \(f(x + h)\) and \(f(x)\), and then taking their difference, we're able to determine how much the function changes per unit change in \(x\).

In this exercise, the difference quotient is applied to the composed function \((g \circ f)(x)\). The purpose is to simplify the expression to understand its behavior as \(h\) approaches zero, revealing the instantaneous rate of change. This process involves first calculating \((g \circ f)(x+h)\), substituting it back into the formula, and simplifying rigorously to cancel terms, resulting in the final formula.
Precalculus Problem Solving
Precalculus problem-solving skills are crucial for approaching mathematical problems systematically. These skills involve a variety of strategies and techniques to understand, set up, and solve problems before diving into calculus. Learning to manage such problems effectively builds a foundation for more advanced mathematical concepts.

In precalculus, composition of functions is a common task. It involves substituting one function into another, a skill necessary for generating complex functions from simpler ones. To find \((g \circ f)(x)\), we substitute \(f(x)\) into \(g(x)\) directly. Thus, understanding the concept of function composition allows us to manipulate and analyze combinations of basic functions.

Moreover, precalculus often involves simplifying expressions and functions to reveal their core characteristics. This simplification process is essential in preparing for calculus problems, where functions' behaviors at specific points become crucial. The exercise demonstrates this through function composition and the further application of the difference quotient.
Rational Functions
Rational functions are fractions involving polynomials in both the numerator and the denominator. Their unique properties and potential for having undefined points or asymptotes make them particularly interesting and sometimes challenging.

In this problem, we encounter a rational function when combining \(g\) and \(f\) to form \(g \circ f(x) = \frac{2}{x}\). This expression is simplified from \(\frac{2}{x+1-1}\), demonstrating how rational functions often require simplification.

Key aspects of rational functions include:
  • Identifying restrictions: These occur where the denominator equals zero, making the function undefined. In \(g \circ f(x)\), since the denominator is \(x\), the function is undefined at \(x = 0\).
  • Asymptotic behavior: As \(x\) approaches certain values, the graph of the function may tend toward infinity, creating vertical or horizontal asymptotes.
Understanding rational functions' behavior is crucial, especially as they are frequently used in modeling real-world situations and appear often in calculus problems for continuity and limit evaluations.

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Most popular questions from this chapter

It is possible to write every even natural number uniquely as the product of two natural numbers, one odd and one a power of two. For example: \(46=23 \times 2 \quad 36=9 \times 2^{2} \quad 8=1 \times 2^{3}\) Consider the function whose input is the set of even integers and whose output is the odd number you get in the above process. So if the input is \(36,\) the output is 9. If the input is \(46,\) the output is 23 (a) Write a table of values for inputs 2,4,6,8,10,12 and 14 (b) Find five different inputs that give an output of 3

If \(f(x)=x^{3}+c x^{2}+4 x-1\) for some constant \(c\) and \(f(1)=2,\) find \(c .[\text {Hint: Use the rule of } f \text { to compute } f(1) .]\)

Sketch the graph of the equation. $$|x|+|y|=1$$

Find the dimensions of a box with a square base that has a volume of 867 cubic inches and the smallest possible surface area, as follows. (a) Write an equation for the surface area \(S\) of the box in terms of \(x\) and \(h .[\) Be sure to include all four sides, the top, and the bottom of the box.] (b) Write an equation in \(x\) and \(h\) that expresses the fact that the volume of the box is 867 . (c) Write an equation that expresses \(S\) as a function of \(x\). [Hint: Solve the equation in part (b) for \(h\), and substitute the result in the equation of part (a).] (d) Graph the function in part (c), and find the value of \(x\) that produces the smallest possible value of \(S .\) What is \(h\) in this case?

Determine the domain of the function according to the usual convention. $$g(u)=\frac{u^{2}+1}{u^{2}-u-6}$$

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