/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Find the rules of the functions ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the rules of the functions ff and \(f \circ f\) $$f(x)=1 / x$$

Short Answer

Expert verified
Answer: The rules of the given functions are \(f(x) = \frac{1}{x}\) and \(f(f(x)) = x\).

Step by step solution

01

Identify the given functions

The given function is \(f(x) = \frac{1}{x}\).
02

Understand the function composition

We are asked to determine the rule of the function \(f(f(x))\). This means we will substitute the given function \(f(x)\) into itself, replacing the input variable \(x\) with \(f(x)\).
03

Substitute the function into itself

Substitute the given function into itself: $$f(f(x)) = f\left(\frac{1}{x}\right)$$
04

Apply the function rule

Now, apply the rule of the function \(f(x)\) to the input \(\frac{1}{x}\):$$f\left(\frac{1}{x}\right) = \frac{1}{\left(\frac{1}{x}\right)}$$
05

Simplify the function

Simplify the expression to find the rule of \(f(f(x))\):$$f(f(x)) = x$$ Now we have both rules: \( f(x) = \frac{1}{x}\) and \(f(f(x)) = x\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Functions
Inverse functions are a fascinating mathematical concept. They allow us to unravel applications where inputs and outputs can be reversed. In simple terms, the inverse of a function essentially swaps the roles of the input and output. For instance, if function \(f\) takes \(x\) to \(y\), then its inverse, \(f^{-1}\), takes \(y\) back to \(x\). This means that if we apply a function and then its inverse, we get back to our original input:
\[f(f^{-1}(y)) = y\] and \[f^{-1}(f(x)) = x\].

When dealing with the function \(f(x) = \frac{1}{x}\), you might notice it appears to act as its own inverse. Thus, \(f(f(x)) = x\), which perfectly aligns with the property that applying a function followed by its inverse revert to the original value. This beautifully illustrates how inverses work in mathematical operations.
Rational Functions
Rational functions are expressions involving fractions with polynomials in both the numerator and the denominator. A classic example is \(f(x) = \frac{1}{x}\), where the expression is defined for all real numbers except where the denominator is zero, which in this case is when \(x = 0\).

Key Characteristics of Rational Functions:
  • Domain: All real numbers except where the denominator becomes zero.
  • Symmetry: Perfect for symmetric examples like \(f(x) = \frac{1}{x}\), which is symmetric with respect to the origin.
  • Behavior at Infinity: As \(x\) moves towards infinity, \(f(x)\) approaches zero. Similarly, as \(x\) approaches zero, \(f(x)\) explodes towards infinity or negative infinity.
These insights help us predict the behavior of rational functions and understand how they interact when composed with themselves or other functions.
Function Rules
Function rules lay the foundation for how inputs within a function map to outputs. It is the guideline or formula that defines the relationship between variables. The function rule for \(f(x) = \frac{1}{x}\) involves inputting \(x\) and returning the reciprocal of \(x\).

When we perform a composition such as \(f(f(x))\), we apply the function rule twice. In the case of \(f(x) = \frac{1}{x}\), we substitute \(x\) with \(f(x)\) and apply the rule again:
- Substitute: \(f(f(x)) = f\left(\frac{1}{x}\right)\)- Apply the rule: \(f\left(\frac{1}{x}\right) = \frac{1}{(\frac{1}{x})}\)
- Simplify to get \(f(f(x)) = x\).

This results from the rule of taking a reciprocal twice, which brings you back to the original number (except zero, since \(x = 0\) isn't defined here). Understanding these rules allows us to predict and simplify complex expressions effortlessly.

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Most popular questions from this chapter

Find the average rate of change of the function f over the given interval. $$f(x)=-\sqrt{x^{4}-x^{3}+2 x^{2}-x+4} \text { from } x=0 \text { to } x=3$$

Show that the inverse function of the function \(f\) whose rule is \(f(x)=\frac{2 x+1}{3 x-2}\) is \(f\) itself.

The estimated number of 15 - to 24 -year-old people worldwide (in millions) who are living with HIV/AIDS in selected years is given in the table."$$\begin{array}{|l|c|c|c|c|c|} \hline \text { Year } & 2001 & 2003 & 2005 & 2007 & 2009 \\ \hline \begin{array}{l} \text { 15- to 24-year-olds } \\ \text { with HIV/AIDS } \end{array} & 12 & 14.5 & 17 & 19 & 20.5 \\ \hline \end{array}$$(a) Use linear regression to find a function that models this data, with \(x=0\) corresponding to 2000 (b) According to your function, what is the average rate of change in this HIV/AIDS population over any time period between 2001 and \(2009 ?\) (c) Use the data in the table to find the average rate of change in this HIV/AIDS population from 2001 to 2009 . How does this rate compare with the one given by the model? (d) If the model remains accurate, when will the number of people in this age group with HIV/AIDS reach 25 million?

Find the radius \(r\) and height \(h\) of a cylindrical can with a surface area of 60 square inches and the largest possible volume, as follows. (a) Write an equation for the volume \(V\) of the can in terms of \(r\) and \(h\). (b) Write an equation in \(r\) and \(h\) that expresses the fact that the surface area of the can is \(60 .\) [ Hint: Think of cutting the top and bottom off the can; then cut the side of the can lengthwise and roll it out flat; it's now a rectangle. The surface area is the area of the top and bottom plus the area of this rectangle. The length of the rectangle is the same as the circumference of the original can (why?).] (c) Write an equation that expresses \(V\) as a function of \(r\) [Hint: Solve the equation in part (b) for \(h\), and substitute the result in the equation of part (a).] (d) Graph the function in part (c), and find the value of \(r\) that produces the largest possible value of \(V\). What is \(h\) in this case?

Use algebra to find the inverse of the given one-to-one function. $$f(x)=\sqrt[5]{\frac{3 x-1}{x-2}}$$

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