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Find the limit if it exists. If the limit does not exist, explain why. $$\lim _{x \rightarrow 2}\left(6 x^{3}-2 x^{2}+5 x-3\right)$$

Short Answer

Expert verified
Answer: The limit as x approaches 2 is 47.

Step by step solution

01

Identify the function

The given function is a polynomial function: $$f(x) = 6x^3 - 2x^2 + 5x - 3$$ We are asked to find the limit as x approaches 2: $$\lim _{x \rightarrow 2}\left(6 x^{3}-2 x^{2}+5 x-3\right)$$
02

Evaluate the function at x = 2

Since polynomial functions are continuous everywhere, we can find the limit by simply evaluating the function at x = 2: $$f(2) = 6(2)^3 - 2(2)^2 + 5(2) - 3$$
03

Perform the calculations

Now, we compute the value of the function at x = 2: $$f(2) = 6(8) - 2(4) + 5(2) - 3$$ $$f(2) = 48 - 8 + 10 - 3$$ $$f(2) = 47$$
04

Write the conclusion

Since we found the value of the function at x = 2, we can write the limit as follows: $$ \lim _{x \rightarrow 2}\left(6 x^{3}-2 x^{2}+5 x-3\right) = f(2) = 47 $$ Therefore, the limit as x approaches 2 is 47.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits of Polynomial Functions
Understanding the limits of polynomial functions is essential for anyone studying calculus. A polynomial function, in simple terms, is a mathematical expression consisting of terms that include a variable (like x) raised to whole number powers and coefficients. For example, the function described in our exercise, \( f(x) = 6x^3 - 2x^2 + 5x - 3 \), is a polynomial because every term has the variable \( x \) raised to a whole number power.

When finding the limit of such a function as \( x \) approaches a specific value, you can often substitute the value directly into the polynomial. This method works because polynomials are continuous over all real numbers, which means there are no breaks, holes, or jumps in the graph of the function. Since continuity plays a key role here, you can just plug the number you're approaching into the function to find the limit. This simplicity makes calculations straightforward, just as in our given example where \( f(2) \) equals 47.
Continuous Functions
A continuous function is one where small changes to the input result in small changes to the output, with no interruptions in the graph. In more practical terms, you could draw the graph of a continuous function without lifting your pencil from the paper. Continuous functions play a pivotal role in calculus as they often permit the direct evaluation of limits.

Since polynomial functions are always continuous, they beautifully illustrate this concept. No matter which polynomial you're working with, it will be continuous across all real numbers. That's why, in the exercise above, we could find the limit as \( x \) approaches 2 simply by evaluating \( f(2) \), leading us to our solution of 47 seamlessly. Without continuity, we'd have to consider more complex techniques to evaluate limits.
Limit Evaluation
Limit evaluation is a fundamental concept in calculus, which involves finding the value that a function approaches as the input approaches a certain point. The method of evaluating a limit can vary depending on the type of function and the point to which \( x \) is approaching.

In the scenario of polynomial functions, we are fortunate because evaluating limits is as easy as substituting the point we are approaching into the function, thanks to their continuous nature. This direct substitution method is the most efficient and preferred technique in this case.

To illustrate, the exercise we are discussing asks for the limit of \( f(x) = 6x^3 - 2x^2 + 5x - 3 \) as \( x \) approaches 2. Given that the polynomial function is continuous, we avoid complications and simply calculate \( f(2) \) for our limit. As seen in the step-by-step solution, the end result is 47, which tells us that as \( x \) gets infinitely close to 2, \( f(x) \) gets infinitely close to 47.

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