/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 60 Use a calculator to approximate ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use a calculator to approximate the required term or sum. $$a_{50} \text { where } a_{n}=\frac{\ln n}{n^{2}}$$

Short Answer

Expert verified
Answer: To find the approximate value of the 50th term, substitute n with 50 in the general term formula, which gives $$a_{50}=\frac{\ln 50}{50^{2}}$$. Using a calculator, we can find that the approximate value of the 50th term is around 0.00139.

Step by step solution

01

Identify the term's number in the sequence

We are given the general term: $$a_{n}=\frac{\ln n}{n^{2}}$$ We need to find the 50th term, so we will substitute the value of n with 50.
02

Substitute the value of n into the formula

Now that we know we're looking for the 50th term, we can substitute n with 50 in the general term formula. $$ a_{50}=\frac{\ln 50}{50^{2}} $$
03

Compute the value

All that is left now is to compute this value. Since we are allowed to use a calculator, we can easily find the approximation. $$ a_{50} \approx \frac{\ln 50}{50^{2}} $$ Enter the expression into the calculator and obtain the approximate value.
04

Interpret the result

The calculator will provide the approximate value for the 50th term of the given sequence. This value represents the 50th term in a sequence where the general term is expressed as $$a_{n}=\frac{\ln n}{n^{2}}$$.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

General Term of a Sequence
In precalculus, understanding the general term of a sequence is fundamental to analyzing its properties and behavior. The general term, often denoted as an, represents a formula that can calculate any term in the sequence based on its position, n.

For example, with the general term an = \(\frac{\ln n}{n^{2}}\), you can find any term in the sequence just by plugging in the value of n, where n is a positive integer. So if you wanted the 50th term, identified as a50, you'd substitute 50 for n in the formula to calculate its value. This approach is a methodical and efficient way to handle sequences without listing all of its terms.
Logarithmic Functions
Logarithmic functions are the inverse of exponential functions and have widespread applications in science, engineering, and mathematics. The natural logarithm, denoted as \(\ln(x)\), uses the base \(e\), where e is an irrational and transcendental number approximately equal to 2.71828.

Logarithms have unique properties that make them useful for solving equations involving exponential growth or decay. For instance, they can transform multiplicative relationships into additive ones, making certain classes of problems easier to tackle. In the context of sequences, logarithms can be used within the general term to create sequences that grow or decay at rates proportional to the reciprocal of the term's position, like in the example \(a_n = \frac{\ln n}{n^2}\).
Sequence Term Approximation
When dealing with sequences, especially those whose general term involves irrational numbers or complex operations, finding an exact value for specific terms may be impractical or impossible. Approximation becomes crucial in understanding the behavior of the sequence.

To approximate a term in a sequence like a50 of \(a_n = \frac{\ln n}{n^2}\), one might use a scientific calculator or a software tool capable of computing logarithms. Approximation gives us a practical value to work with and can be particularly useful when the sequence describes a real-world scenario where an exact number is not necessary, or when contributing to a summation where the precise value may have a negligible effect on the total.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The number of bachelor's degrees (in thousands) awarded in year \(n\) is approximated by the sequence \(\left\\{a_{n}\right\\},\) where \(a_{n}=\) \(25.3 n+1250\) and \(n=0\) corresponds to \(2000 .\) (a) Approximately how many bachelor's degrees were awarded in 2004 and in \(2007 ?\) (b) Approximately how many bachelor's degrees will be awarded between 2004 and 2009 (inclusive)?

Use a calculator to approximate the required term or sum. $$a_{102} \text { where } a_{n}=\frac{n^{3}-n^{2}+5 n}{3 n^{2}+2 n-1}$$

Deal with the Fibonacci sequence \(\left\\{a_{n}\right\\}\) that was discussed in Example 6. Leonardo Fibonacci discovered the sequence in the thirteenth century in connection with this problem: A rabbit colony begins with one pair of adult rabbits (one male, one female). Each adult pair produces one pair of babies (one male, one female) every month. Each pair of baby rabbits becomes adult and produces the first offspring at age two months. Assuming that no rabbits die, how many adult pairs of rabbits are in the colony at the end of \(n\) months \((n=1,2,\) 3, ...)? [Hint: It may be helpful to make up a chart listing for each month the number of adult pairs, the number of one-month-old pairs, and the number of baby pairs.]

In Exercises \(49-54,\) you are asked to find a geometric sequence. In each case, round the common ratio r to four decimal places. The number of students per computer in U.S. schools in year \(n\) (with \(n=1\) corresponding to 1997 ) can be approximated by a geometric sequence whose first two terms are \(a_{1}=5.912\) and \(a_{2}=5.687\) (a) Find a formula for \(a_{n}\) (b) What is the number of students per computer in \(2007 ?\) (c) In what year will there first be fewer than 3 students per computer?

In Exercises \(49-54,\) you are asked to find a geometric sequence. In each case, round the common ratio r to four decimal places. The value of all group life insurance (in billions of dollars) in year \(n\) can be approximated by a geometric sequence \(\left\\{c_{n}\right\\},\) where \(n=1\) corresponds to \(1991 .\) (a) If there was \(\$ 3.9631\) billion in effect in 1991 and \(\$ 4.1672\) billion in \(1992,\) find a formula for \(c_{n}\) (b) How much group life insurance is in effect in \(2000 ?\) In \(2004 ?\) In \(2008 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.