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Find the indicated term of the expansion of the given expression. fifth, \((c-d)^{7}\)

Short Answer

Expert verified
Answer: The fifth term in the expansion is \(35c^{3}d^{4}\).

Step by step solution

01

Understand the binomial theorem formula

The general formula for the binomial theorem is \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^{k}\). In our case, \(a=c, b=-d, \text{ and } n=7\).
02

Find the formula for the fifth term

We are looking for the fifth term, which means k will be equal to 4 (since we start at k=0 for the first term). So, we will substitute \(n=7, a=c, b=-d,\) and \(k=4\) into the formula: \(T_{k+1} = \binom{n}{k} a^{n-k} b^{k} = \binom{7}{4} c^{(7-4)} (-d)^4\)
03

Calculate the binomial coefficient

Now, let's find the binomial coefficient: \(\binom{7}{4} = \frac{7!}{4!(7-4)!} = \frac{7!}{4!3!}\). Using the factorial formula for each, we obtain: \(\frac{7\times6\times5\times4\times3\times2}{(4\times3\times2\times1)\times(3\times2)} = 35\)
04

Calculate the whole formula for the fifth term

Now substitute the binomial coefficient in the formula: \(T_{5} = 35c^{3}(-d)^4\)
05

Simplify and write the final answer

Finally, we simplify the expression: \(T_{5} = 35c^{3}d^{4}\) Therefore, the fifth term in the expansion of \((c-d)^{7}\) is \(35c^{3}d^{4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient
The binomial coefficient, often read as 'n choose k', is a fundamental component in combinatorics and the binomial theorem. It tells us how many ways we can choose 'k' elements from a set of 'n' elements, irrespective of the order. The binomial coefficient is denoted as \(\binom{n}{k}\).

Mathematically, it is defined as the number of ways to form 'k' combinations from 'n' distinct items. To compute the value, the formula used is: \[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]where '!' represents a factorial. In the context of binomial expansion, such as \((a + b)^n\), the coefficients determine the weighting of each term in the expansion.

For example, in our exercise, to find the fifth term (which is actually the term when k=4) of \((c - d)^7\), we calculate the binomial coefficient using \(n = 7\) and \(k = 4\). Using the formula, we get \(\binom{7}{4} = \frac{7!}{4!(7 - 4)!}\), which simplifies to 35, indicating there are 35 ways of choosing 4 items from 7, or that the weight of the fifth term in our binomial expansion is 35.
Factorial
The concept of a factorial is vital in mathematics, especially in permutations, combinations, and thus in the computation of binomial coefficients. 'Factorial' is represented by an exclamation point (!) and it signifies the product of all positive integers up to a given number.

For any non-negative integer 'n', the factorial is defined as: \[ n! = n \times (n - 1) \times (n - 2) \times \cdots \times 2 \times 1 \]The factorial of zero (0!) is defined as 1, according to convention.

Factorials grow very quickly with 'n'. They are key in calculations involving the binomial theorem because they are part of the formula used to find binomial coefficients. For instance, in our example, when we calculate \(\frac{7!}{4!3!}\), we are using factorials to account for the number of different ways we can arrange '7' items, and then dividing by the arrangements of the items in both the subset and the remaining set.
Symbolic Exponentiation
Symbolic exponentiation is used when raising an indeterminate or an algebraic expression to a power. In the binomial theorem, we see a perfect example of symbolic exponentiation when expanding a binomial expression, such as \((c - d)^{7}\).
The process of symbolic exponentiation involves applying the exponent to each term within the parentheses. This action follows the rules of exponents, where for any real numbers 'a' and 'b', and a positive integer 'n': \[ (a \cdot b)^{n} = a^{n} \cdot b^{n} \]Another rule to remember is that any nonzero number to the zeroth power is '1'.

In our exercise, we apply symbolic exponentiation in steps, where \(c\) and \((-d)\) are raised to specific powers defined by the terms of the binomial theorem. For instance, in the fifth term of \((c - d)^{7}\), we calculate \(c^{(7-4)}(-d)^4\), which involves raising \(c\) to the third power and \(-d\) to the fourth power to contribute to the expanded form.

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Most popular questions from this chapter

Deal with the Fibonacci sequence \(\left\\{a_{n}\right\\}\) that was discussed in Example 6. Leonardo Fibonacci discovered the sequence in the thirteenth century in connection with this problem: A rabbit colony begins with one pair of adult rabbits (one male, one female). Each adult pair produces one pair of babies (one male, one female) every month. Each pair of baby rabbits becomes adult and produces the first offspring at age two months. Assuming that no rabbits die, how many adult pairs of rabbits are in the colony at the end of \(n\) months \((n=1,2,\) 3, ...)? [Hint: It may be helpful to make up a chart listing for each month the number of adult pairs, the number of one-month-old pairs, and the number of baby pairs.]

According to data and projections in an article in \(U S A\) Today, the number of Internet phone calls (in millions) is approximated by $$f(x)=.075 x^{3}-.86 x^{2}+3.66 x-4 \quad(3 \leq x \leq 7)$$ where \(x=3\) corresponds to \(2003 .^{\dagger}\) Write the rule of a function \(g(x),\) which provides the same information as \(f,\) but has \(-x=0\) corresponding to \(2003 .\) [Hint: See Exercise 67.]

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