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Find the first five terms of the recursively defined sequence. $$a_{1}=-16 \text { and } a_{n}=\frac{a_{n-1}}{2} \quad \text { for } n \geq 2$$

Short Answer

Expert verified
Answer: The first five terms of the given recursively defined sequence are -16, -8, -4, -2, and -1.

Step by step solution

01

Understand the given sequence

The given sequence is defined recursively by the first term \(a_1\) and a relationship between any term and its preceding term (here, \(a_n\) and \(a_{n-1}\)). In this case, the sequence starts with \(a_1 = -16\), and the relationship is given as: \[a_n = \frac{a_{n-1}}{2}\]
02

Determine the first term in the sequence

The given sequence has its first term explicitly defined: \[a_1 = -16\]
03

Compute the second term in the sequence

We can compute the second term by applying the given relationship to the first term: \[a_2 = \frac{a_1}{2} = \frac{-16}{2}\] Thus, \(a_2\) is: \[a_2 = -8\]
04

Compute the third term in the sequence

Applying the relationship to the second term, we can find the third term: \[a_3 = \frac{a_2}{2} = \frac{-8}{2}\] So, the third term in the sequence is: \[a_3 = -4\]
05

Compute the fourth term in the sequence

Using the relationship for the third term, we compute the fourth term as follows: \[a_4 = \frac{a_3}{2} = \frac{-4}{2}\] Then, the fourth term in the sequence will be: \[a_4 = -2\]
06

Compute the fifth term in the sequence

Once again, apply the given relationship, this time to the fourth term to calculate the fifth term in the sequence: \[a_5 = \frac{a_4}{2} = \frac{-2}{2}\] Thus, the fifth term is: \[a_5 = -1\]
07

Summarize the result

In conclusion, the first five terms of the given recursively defined sequence are: \[a_1 = -16,\ a_2 = -8,\ a_3 = -4,\ a_4 = -2,\ a_5 = -1\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sequence and Series
Understanding sequences and series forms a foundational aspect of mathematics, particularly in algebra and calculus. A sequence is simply a set of numbers listed in a specific order. The numbers in a sequence, referred to as terms, follow a certain rule that dictates the progression from one term to the next.

For example, the sequence 3, 6, 9, 12, and so on, is defined by the rule 'start with 3 and add 3 each time'. The terms continue indefinitely unless a limit is set. On the other hand, a series is the sum of the terms of a sequence. If we take the sequence mentioned before and add the terms together like 3 + 6 + 9 + 12, we have a series.

Sequences can be either finite or infinite, depending on whether there is a natural end or if they could continue endlessly. When working with sequences, identifying the rule that generates the terms is crucial. This rule can be explicit, with a formula for the nth term, or recursive, where each term depends on one or more of the previous terms.

To help students understand these concepts, visually illustrating the sequence or breaking down series into partial sums can be effective. Interactive tools can also be used for exploration, allowing students to manipulate terms and see resulting changes in real time.
Recursive Formula
A recursive formula is a way to define a sequence based on the previous terms. Unlike an explicit formula, which directly expresses the nth term based on the initial term and any common patterns observed, a recursive formula emphasizes the relationship between successive terms.

For instance, if you have a sequence where each term is half of the previous term, you can express it recursively. Given the first term, each following term can be found by applying the formula to the one before it. This makes recursive sequences vital in computer science and mathematics due to their inherent nature of iteration, commonly seen in programming and algorithm design.

To get better at identifying and working with recursive formulas, practice is key. Students should start with simple examples and progressively tackle more complex ones. Additionally, they could create their own sequences using different operations, discovering the effects these operations have on the sequence's terms.
Arithmetic Sequence
An arithmetic sequence is a specific type of sequence where the difference between consecutive terms is constant. This difference is called the common difference, denoted as 'd'. The formula for an arithmetic sequence can be expressed as \(a_n = a_1 + (n - 1)d\), where \(a_n\) is the nth term, \(a_1\) is the first term, and 'n' is the number of the term in the sequence.

It might appear at first glance that an arithmetic sequence relates to the problem at hand, but as the given sequence halves each term, it is not arithmetic but geometric. An exercise improvement advice for students struggling with this concept would be to compare and contrast different types of sequences and identify patterns and rules governing their formation. Students would benefit from using examples both in numerical and visual formats—including tables or graphs—to draw a clear distinction between arithmetic and other types of sequences.

Engaging in exercises that require finding several terms in different arithmetic sequences, both by using the explicit formula and by applying the common difference successively, can enhance their understanding of this concept.

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Most popular questions from this chapter

Use a recursively defined sequence to find the answer, as in Example 9. Lisa Chow is buying a condo. She takes out an 80,000 dollars mortgage for 30 years at \(6 \%\) annual interest. Her monthly payment is 479.64 dollars. (a) How much does she owe after one year ( 12 payments)? (b) How much interest does Lisa pay during the first five years? [Hint: The interest paid is the difference between her total payments and the amount of the loan paid off after five years \((80,000 \text { dollars }-\text { remaining balance }) .]\) (c) After 15 years, Lisa sells the condo and pays off the remaining mortgage balance. How much does she pay?

A ball is dropped from a height of 8 feet. On each bounce, it rises to half its previous height. When the ball hits the ground for the seventh time, how far has it traveled?

In Exercises \(49-54,\) you are asked to find a geometric sequence. In each case, round the common ratio r to four decimal places. According to data from the U.S. National Center for Education Statistics, the number of bachelor's degrees earned by women can be approximated by a geometric sequence \(\left\\{c_{n}\right\\}\) where \(n=1\) corresponds to 1996 (a) If 642,000 degrees were earned in 1996 and 659,334 in 1997 find a formula for \(c_{n}\) (b) How many degrees were earned in \(2000 ?\) In \(2002 ?\) In \(2005 ?\) (c) Find the total number of degrees earned from 1996 to 2005.

(a) Let \(f\) be the function given by \(f(x)=x^{5} .\) Let \(h\) be a nonzero number and compute \(f(x+h)-f(x)\) (but leave all binomial coefficients in the form \(\left(\begin{array}{l}5 \\ r\end{array}\right)\) here and below). (b) Use part (a) to show that \(h\) is a factor of \(f(x+h)-f(x)\) and find \(\frac{f(x+h)-f(x)}{h}\) (c) If \(h\) is very close to \(0,\) find a simple approximation of the quantity \(\frac{f(x+h)-f(x)}{h} .\) [See part (b).]

Use a calculator to approximate the required term or sum. $$a_{12} \text { where } a_{n}=\left(1+\frac{1}{n}\right)^{n}$$

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