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Show that AB is not equal to BA by computing both products. $$A=\left(\begin{array}{ll} 2 & 3 \\ 1 & 5 \end{array}\right), \quad B=\left(\begin{array}{rr} -1 & 1 \\ 3 & 2 \end{array}\right)$$

Short Answer

Expert verified
Answer: No, the products of matrices A and B in the order AB and BA are not equal. We have AB = $\left(\begin{array}{cc} 7 & 8 \\ 14 & 11 \end{array}\right)$ and BA = $\left(\begin{array}{cc} -1 & 2 \\ 8 & 19 \end{array}\right)$. Their elements are not the same, thus AB is not equal to BA (i.e., \(AB\not=BA\)).

Step by step solution

01

Compute AB

First, let's compute the product of A and B in the order AB. To do this, we will take the dot product of each row of A with each column of B, and place the result in the corresponding position of the resultant matrix. $$AB = \left(\begin{array}{ll} 2 & 3 \\\ 1 & 5 \end{array}\right) \left(\begin{array}{rr} -1 & 1 \\\ 3 & 2 \end{array}\right) = \left(\begin{array}{cc} (2)(-1) + (3)(3) & (2)(1) + (3)(2) \\\ (1)(-1) + (5)(3) & (1)(1) + (5)(2) \end{array}\right)$$
02

Simplify AB

Now, we will simplify the expressions in the resulting elements of the matrix AB. $$AB = \left(\begin{array}{cc} (-2) + (9) & (2) + (6) \\\ (-1) + (15) & (1) + (10) \end{array}\right) = \left(\begin{array}{cc} 7 & 8 \\\ 14 & 11 \end{array}\right)$$
03

Compute BA

Next, let's compute the product of A and B in the order BA. Just like in Step 1, we will take the dot product of each row of B with each column of A, and place the result in the corresponding position of the resultant matrix. $$BA = \left(\begin{array}{rr} -1 & 1 \\\ 3 & 2 \end{array}\right) \left(\begin{array}{ll} 2 & 3 \\\ 1 & 5 \end{array}\right) = \left(\begin{array}{cc} (-1)(2) + (1)(1) & (-1)(3) + (1)(5) \\\ (3)(2) + (2)(1) & (3)(3) + (2)(5) \end{array}\right)$$
04

Simplify BA

Just like in Step 2, we will simplify the expressions in the resulting elements of the matrix BA. $$BA = \left(\begin{array}{cc} (-2) + (1) & (-3) + (5) \\\ (6) + (2) & (9) + (10) \end{array}\right) = \left(\begin{array}{cc} -1 & 2 \\\ 8 & 19 \end{array}\right)$$
05

Compare AB and BA

Now that we have calculated both products AB and BA, we will compare them to see if they are equal. We have: $$AB = \left(\begin{array}{cc} 7 & 8 \\\ 14 & 11 \end{array}\right)$$ and $$BA = \left(\begin{array}{cc} -1 & 2 \\\ 8 & 19 \end{array}\right)$$ We can see from these two matrices that AB and BA are not equal, as their elements are not the same. Hence, we have shown that \(AB\not=BA\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Non-Commutative Property
In the world of matrix operations, it's crucial to understand that multiplication does not follow the commutative property. In simpler terms, for matrices, the equation \(AB = BA\) does not necessarily hold. This is unlike basic arithmetic with real numbers, where the order does not affect the product. For example, if you multiply \(2 \times 3\), it is the same as \(3 \times 2\). However, when it comes to matrices, changing the order changes the result, as we've seen from the matrices \(A\) and \(B\).

Consider our matrices \(A\) and \(B\):
  • When we computed \(AB\), we got a matrix \(\left(\begin{array}{cc} 7 & 8 \ 14 & 11 \end{array}\right)\).
  • But when we reversed the order to \(BA\), the matrix became \(\left(\begin{array}{cc} -1 & 2 \ 8 & 19 \end{array}\right)\).

This difference highlights a fundamental characteristic of matrices: matrix multiplication is non-commutative. The result can change dramatically based on the sequence of multiplication. This is a key concept to remember when you're solving problems or applying matrices in practical scenarios.
Matrix Arithmetic
Matrix arithmetic involves a set of rules and operations, including addition, subtraction, and multiplication, which are similar but not identical to those in regular arithmetic.

When multiplying matrices like \(A\) and \(B\), you need to use the dot product technique. This involves multiplying each element of the rows of the first matrix with the corresponding elements of the columns of the second matrix. The result goes into the new matrix.

For example, in multiplying \(AB\), each element in the resulting matrix was derived by:
  • Taking the dot product of the first row of \(A\) with the columns of \(B\).
  • Calculating the same for the second row, and so on.

Similarly, for \(BA\), we reversed this process, showing how the approach remains consistent, but the results vary based on the matrix order.

To fully grasp matrix arithmetic, practice is key. Working through multiple examples can familiarize you with matrix multiplication rules and their unique nature compared to basic numerical calculations.
Order of Operations in Matrices
The order of operations is a cornerstone in working with matrices, much like its importance in standard arithmetic calculations. For matrices, the sequence in which operations are performed affects the overall outcome greatly, especially in multiplication.

While addition and subtraction of matrices don't require specific orders due to their commutative nature, multiplication certainly does.

As showcased in the exercise:
  • The analysis of \(AB\) versus \(BA\) exhibited different results due entirely to the order of multiplication.
  • This reinforces the non-commutative nature of matrix products and the necessity to carefully order operations to achieve the desired outcome.
  • Recognizing how each action impacts the result can aid in avoiding errors, especially in complex calculations involving larger matrices.

Understanding the order of operations when dealing with matrices prepares you for advanced mathematical processes and is crucial for accurate computations. Always verify the sequence of your operations to ensure precise and correct answers.

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